CN103470757A - Equal-strength self-enhancement pressure vessel with variable structure size - Google Patents

Abstract

The invention provides an equal-strength self-enhancement pressure vessel with the variable structure size, and aims to improve safety of the pressure vessel, reduce manufacturing cost and solve the technical problems that in the prior art, calculation is complicated and inaccurate, and a vessel is unequal in strength, fixed and unreasonable in structure, and inflexible in design. The equal-strength self-enhancement pressure vessel has the advantages that under the condition that loads are unchanged, the structure size is flexible and changeable, and the equal-strength structure is achieved (the total stress in a plastic zone is constant and the total stress of an elastic zone is constantly smaller than yield strength). According to the technical scheme, when the diameter ratio k is larger than the kc lambada value which is determined by a formula, the superstrain degree epsilon lambada of the vessel is determined according to another formula: k21n (epsilon lambada (k-1) +1) 2-(lambada -1) k2-(epsilon lambada (k-1) +1) 2 +lambada=0, and the internal pressure p of the vessel is lambada times of the initial yield load pe of a vessel with the same size and free of self-enhancement; when k is smaller than or equal to the kc lambada value which is determined by the formula, the superstrain degree of the vessel can be 100%, and in the self-enhancement pressure vessel of which maximum bearing capacity can be total yield pressure or of the structure, all the stress of the vessel is within a safety range. The diameter ratio k is the ratio of the external radius of the vessel to the internal diameter of the vessel.

Description

The equal strength self-reinforcing pressure vessel that a kind of physical dimension is variable

Technical field

The present invention relates to the variable equal strength self-reinforcing pressure vessel of a kind of physical dimension, belong to the technical fields such as machine science technology, process industrial.

Background technique

Pressurized container belongs to special equipment, is widely used, as industries such as machinery, chemical industry, pharmacy, the energy, material, food, metallurgy, oil, building, Aeronautics and Astronautics, weapons.At first pressurized container will guarantee Security, enough bearing capacitys will be arranged, but can not unilateral increase wall thickness, and this not only increases cost, also affects its Security.The self intensification technology is to improve the ingenious of pressurized container bearing capacity and Security thereof and effective measures.The self intensification technology of pressurized container is, before operation is used, it is carried out to pressure treatment, makes the barrel inner surrender, produces plastic deformation, form plastic zone, and skin is still elastic state.Keep the release after a period of time of this pressure.Release rear cylinder body internal layer plastic is because there being residual deformation can not return to original state, original state is tried hard to return in outer elastic region, can not return to original state and be subject to stopping of internal layer plastic zone, therefore bear stretching, main form pre-tensile stress, and internal layer is tried hard to the compression of recovery and is mainly produced compressive pre-stress because being subject to skin.So just formed the pre-stressed state of the outer tension of a kind of internal layer pressurized.After container comes into operation and bears interior pressure, prestressing force is superimposed with the interior stress of pressing p to cause of operation, and the inboard wall stress that stress is larger is reduced, and the outer wall stress that stress is less increases to some extent, thereby makes stress in container wall be tending towards even.Can improve the bearing capacity of pressurized container thus.Self intensification that Here it is.

The key factor of self intensification technology is the plastic zone degree of depth, i.e. determining of container elastic and plastic properties regional boundary radius surface, or superstrain degree

determine, r wherein _i, r _j, r _obe respectively inside radius, radius of elastic-plastic junction, the outer radius of shell; K is the footpath ratio, k=r _o/ r _i; k _jfor the plastic zone degree of depth, k _j=r _j/ r _i; Consult Fig. 1.The superstrain degree not only has influence on the enforcement of self-reinforcing process, and the distributional pattern, bearing capacity, the total stress that affect the residual stress after the removal from strengthen pressure of self intensification container distribute and even the Security of container and Economy etc., and ε is k _jtoo large, after the removal from strengthen pressure, container there will be compression yield, and compressive residual stress can surpass the ultimate strength σ of container material _y; ε is k _jtoo little, bearing capacity is not high, the waste material.Determine k _jor r _jor ε, existing technology mainly contains 1) graphical solution; 2) press formula

rough calculation; 3) trial and error method, suppose some r _j, calculate self intensification and process rear r _jthe equivalent stress σ of place's total stress (residual prestress and operational stresses induced sum) _ej, ask for and make σ _ejminimum r _j; 4) press formula

(the 3rd intensity theory) or

(fourth strength theory) calculates.These methods or too rough (as graphical solution and the estimation technique), can not reflect question essence again; Or too loaded down with trivial details (as trial and error method), can not reflect question essence.And all can not guarantee not occur reverse yielding, be that after time institute's applied pressure is processed in the removal self intensification, container may produce because being subject to excessive compression the secondary compression surrender, that visible technology in the past can not obtain is rational in infrastructure, not only safety but also economic pressurized container, more can not obtain the pressurized container of structurally variable.Viewpoint from safety, economy, self-reinforcing pressure vessel should guarantee not produce reverse yielding, guarantee that again every stress is less than yield strength, also to make bearing capacity improve, and have that physical dimension is flexible and changeable, equal strength (is that the wall internal stress is constant, can save material like this) characteristic such as design, because industrial operational condition is ever-changing.

The present invention, from first guaranteeing the Security of pressurized container, has proposed a kind of self-reinforcing pressure vessel of special construction, not only safety but also economize material and flexible design.

Summary of the invention

The purpose of this invention is to provide the variable equal strength self-reinforcing pressure vessel of a kind of physical dimension.

The technical solution adopted for the present invention to solve the technical problems is: construct the variable equal strength self-reinforcing pressure vessel of a kind of physical dimension, the physical dimension of this kind of pressurized container and bearing capacity are determined by specific technological scheme, specifically: the physical dimension of this self-reinforcing pressure vessel and bearing capacity are definite by particular requirement, and specifically: (1) footpath is greater than by formula than k

definite k _{c λ}the self-reinforcing pressure vessel of value, its superstrain degree is determined by following formula:

k ²ln[ε _λ(k-1)+1] ²-(λ-1)k ²-[ε _λ(k-1)+1] ²+λ＝0，

Its bearing capacity p/ σ _ydetermine as follows:

$\frac{p}{{\mathrm{\&sigma;}}_y}=\mathrm{\&lambda;}\frac{k^2-1}{\sqrt{3}{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}=\mathrm{\&lambda;}\frac{p_e}{{\mathrm{\&sigma;}}_y}$ (fourth strength theory) or $\frac{p}{{\mathrm{\&sigma;}}_y}=\mathrm{\&lambda;}\frac{k^2-1}{{2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}=\mathrm{\&lambda;}\frac{p_e}{{\mathrm{\&sigma;}}_y}$ (the 3rd intensity theory), its calculated thickness t determines as follows:

$t=r_i(\sqrt{\frac{\mathrm{\&lambda;}}{\mathrm{\&lambda;}-\sqrt{3}\frac{p}{{\mathrm{\&sigma;}}_y}}}-1)$ (fourth strength theory) or $t=r_1(\sqrt{\frac{\mathrm{\&lambda;}}{\mathrm{\&lambda;}-2\frac{p}{{\mathrm{\&sigma;}}_y}}}-1)$ (the 3rd intensity theory);

Wherein

K be footpath than (characterizing the physical dimension of this kind of self-reinforcing pressure vessel), equal self-reinforcing pressure vessel outer radius r _owith inside radius r _iratio, k=r _o/ r _i,

K _{c λ}for relatively critical footpath ratio, corresponding to the footpath ratio of λ,

λ is that bearing capacity strengthens coefficient, λ=p/p _e, the scope of λ is 1～+ ∞,

P is the interior pressure that self-reinforcing pressure vessel bears, or the title calculating pressure,

P _efor the maximum flexibility bearing capacity of non-self-reinforcing pressure vessel under same size (initial yield load),

ε _λfor the superstrain degree,

σ _yyield strength for the material of manufacturing self-reinforcing pressure vessel;

When this kind of self-reinforcing pressure vessel bears p=n σ _yload the time (wherein n is the scaling factor of load to yield strength), its footpath is than by formula

(fourth strength theory), or

(the 3rd intensity theory) determined, different λ obtains different footpaths than k, thereby obtains different wall thickness, to form motor-driven design proposal; (2) k is less than or equal to by formula

definite k _{c λ}the self-reinforcing pressure vessel of value, its plastic zone scope allows for whole wall thickness, and now its maximum load-carrying capacity is full yield pressure,

(fourth strength theory), or

(the 3rd intensity theory); Its footpath ratio is (fourth strength theory), or

(the 3rd intensity theory); Its calculated thickness is

(fourth strength theory), or

(the 3rd intensity theory).The equal strength self-reinforcing pressure vessel that described physical dimension is variable, physical dimension (k, the k of every stress at any point place and container in its wall _{j λ}), magnitude of load (λ) is by following relation constraint:

(1) press fourth strength theory, its residual stress relation is:

Plastic zone: axial residual stress ${\mathrm{\&sigma;}}_z^{\&prime;}=\frac{{\mathrm{\&sigma;}}_y}{\sqrt{3}}(\ln x^2-\mathrm{\&lambda;}+1),$

Residual stress radially ${\mathrm{\&sigma;}}_r^{\&prime;}=\frac{{\mathrm{\&sigma;}}_y}{\sqrt{3}}(\ln x^2-\mathrm{\&lambda;}+\frac{\mathrm{\&lambda;}}{x^2}),$

The hoop residual stress ${\mathrm{\&sigma;}}_{\mathrm{\&theta;}}^{\&prime;}=\frac{{\mathrm{\&sigma;}}_y}{\sqrt{3}}(\ln x^2-\mathrm{\&lambda;}-\frac{\mathrm{\&lambda;}}{x^2}+2),$

The equivalent residual stress ${\mathrm{\&sigma;}}_e^{\&prime;}={\mathrm{\&sigma;}}_y(1-\frac{\mathrm{\&lambda;}}{x^2});$

Elastic region: axial residual stress ${\mathrm{\&sigma;}}_z^{\&prime;}=\frac{{\mathrm{\&sigma;}}_y}{\sqrt{3}{k}^2}(k_{\mathrm{j\&lambda;}}^2-\mathrm{\&lambda;}),$

Residual stress radially ${\mathrm{\&sigma;}}_r^{\&prime;}=(1-\frac{k^2}{x^2}){\mathrm{\&sigma;}}_z^{\&prime;},$

The hoop residual stress ${\mathrm{\&sigma;}}_{\mathrm{\&theta;}}^{\&prime;}=(1+\frac{k^2}{x^2}){\mathrm{\&sigma;}}_z^{\&prime;},$

The equivalent residual stress ${\mathrm{\&sigma;}}_e^{\&prime;}=\frac{{\mathrm{\&sigma;}}_y}{x^2}(k_{\mathrm{j\&lambda;}}^2-\mathrm{\&lambda;});$

(2) press fourth strength theory, its total stress relation is:

Plastic zone: axial total stress ${\mathrm{\&sigma;}}_z=\frac{{\mathrm{\&sigma;}}_y}{\sqrt{3}}(\ln x^2-\mathrm{\&lambda;}+\frac{\mathrm{\&lambda;}}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+1),$

Total stress radially ${\mathrm{\&sigma;}}_r=\frac{{\mathrm{\&sigma;}}_y}{\sqrt{3}}(\ln x^2-\mathrm{\&lambda;}+\frac{\mathrm{\&lambda;}}{k^2}),$

The hoop total stress ${\mathrm{\&sigma;}}_{\mathrm{\&theta;}}=\frac{{\mathrm{\&sigma;}}_y}{\sqrt{3}}(\ln x^2-\mathrm{\&lambda;}+\frac{\mathrm{\&lambda;}}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+2),$

Equivalent total stress σ _e≡ σ _y;

Elastic region: axial total stress ${\mathrm{\&sigma;}}_z=\frac{k_{\mathrm{j\&lambda;}}^2}{\sqrt{3}{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}{\mathrm{\&sigma;}}_y,$

Total stress radially ${\mathrm{\&sigma;}}_r=\frac{k_{\mathrm{j\&lambda;}}^2}{\sqrt{3}}(\frac{1}{k^2}-\frac{1}{x^2}){\mathrm{\&sigma;}}_y,$

The hoop total stress ${\mathrm{\&sigma;}}_{\mathrm{\&theta;}}=\frac{k_{\mathrm{j\&lambda;}}^2}{\sqrt{3}}(\frac{1}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+\frac{1}{x^2}){\mathrm{\&sigma;}}_y,$

The equivalent total stress ${\mathrm{\&sigma;}}_{\mathrm{\&theta;}}=\frac{k_{\mathrm{j\&lambda;}}^2}{x^2}{\mathrm{\&sigma;}}_y;$

(3) by the 3rd intensity theory, its residual stress relation is:

Plastic zone: axial residual stress ${\mathrm{\&sigma;}}_z^{\&prime;}=\frac{{\mathrm{\&sigma;}}_y}{2}(\ln x^2-\mathrm{\&lambda;}+1),$

Residual stress radially ${\mathrm{\&sigma;}}_r^{\&prime;}=\frac{{\mathrm{\&sigma;}}_y}{2}(\ln x^2-\mathrm{\&lambda;}+\frac{\mathrm{\&lambda;}}{x^2}),$

The hoop residual stress ${\mathrm{\&sigma;}}_{\mathrm{\&theta;}}^{\&prime;}=\frac{{\mathrm{\&sigma;}}_y}{2}(\ln x^2-\mathrm{\&lambda;}-\frac{\mathrm{\&lambda;}}{x^2}+2),$

The equivalent residual stress ${\mathrm{\&sigma;}}_e^{\&prime;}={\mathrm{\&sigma;}}_y(1-\frac{\mathrm{\&lambda;}}{x^2});$

Elastic region: axial residual stress ${\mathrm{\&sigma;}}_z^{\&prime;}=\frac{{\mathrm{\&sigma;}}_y}{{2k}^2}(k_{\mathrm{j\&lambda;}}^2-\mathrm{\&lambda;}),$

Residual stress radially ${\mathrm{\&sigma;}}_r^{\&prime;}=(1-\frac{k^2}{x^2}){\mathrm{\&sigma;}}_z^{\&prime;},$

The hoop residual stress ${\mathrm{\&sigma;}}_{\mathrm{\&theta;}}^{\&prime;}=(1+\frac{k^2}{x^2}){\mathrm{\&sigma;}}_z^{\&prime;},$

The equivalent residual stress ${\mathrm{\&sigma;}}_e^{\&prime;}=\frac{{\mathrm{\&sigma;}}_y}{x^2}(k_{\mathrm{j\&lambda;}}^2-\mathrm{\&lambda;});$

(4) by the 3rd intensity theory, its total stress relation is:

Plastic zone: axial total stress ${\mathrm{\&sigma;}}_z=\frac{{\mathrm{\&sigma;}}_y}{2}(\ln x^2-\mathrm{\&lambda;}+\frac{\mathrm{\&lambda;}}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+1),$

Total stress radially ${\mathrm{\&sigma;}}_r=\frac{{\mathrm{\&sigma;}}_y}{2}(\ln x^2-\mathrm{\&lambda;}+\frac{\mathrm{\&lambda;}}{k^2}),$

The hoop total stress ${\mathrm{\&sigma;}}_{\mathrm{\&theta;}}=\frac{{\mathrm{\&sigma;}}_y}{2}(\ln x^2-\mathrm{\&lambda;}+\frac{\mathrm{\&lambda;}}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+2),$

Equivalent total stress σ _e≡ σ _y;

Elastic region: axial total stress ${\mathrm{\&sigma;}}_z=\frac{k_{\mathrm{j\&lambda;}}^2}{{2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}{\mathrm{\&sigma;}}_y,$

Total stress radially ${\mathrm{\&sigma;}}_r=\frac{k_{\mathrm{j\&lambda;}}^2}{2}(\frac{1}{k^2}-\frac{1}{x^2}){\mathrm{\&sigma;}}_y,$

The hoop total stress ${\mathrm{\&sigma;}}_{\mathrm{\&theta;}}=\frac{k_{\mathrm{j\&lambda;}}^2}{2}(\frac{1}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+\frac{1}{x^2}){\mathrm{\&sigma;}}_y,$

The equivalent total stress ${\mathrm{\&sigma;}}_{\mathrm{\&theta;}}=\frac{k_{\mathrm{j\&lambda;}}^2}{x^2}{\mathrm{\&sigma;}}_y;$

X=r/r wherein _i, r be container any point place radius, k _{j λ}for the plastic zone degree of depth of container corresponding to λ, it equals container plastic zone radius r _jwith inside radius r _iratio, all the other symbols as previously mentioned.Replace described yield strength σ with allowable stress [σ] _y, all the other feature invariants; And [σ]=min{ σ _b/ n _b, σ _y/ n _y, σ _0.2/ n _y, σ _y ^t/ n _y ^t, σ _0.2 ^t/ n _y ^t, σ _d ^t/ n _d, σ _n ^t/ n _n), σ wherein _bfor tensile strength, n _bfor corresponding to σ _bsafety coefficient (design of material coefficient), σ _0.2be 0.2% Non-proportional extension intensity, n _yfor corresponding to σ _ywith σ _0.2safety coefficient (design of material coefficient), σ _y ^tfor the yield strength under design temperature, σ _0.2 ^tfor 0.2% Non-proportional extension intensity, the n under design temperature _y ^tfor corresponding to σ _y ^twith σ _0.2 ^tsafety coefficient (design of material coefficient), σ _d ^tfor the creep rupture strength under design temperature, n _dfor corresponding to σ _d ^tsafety coefficient (design of material coefficient), σ _n ^tfor the creep limit under design temperature, n _nfor corresponding to σ _n ^tsafety coefficient (design of material coefficient).Or replace σ with [σ] φ _y, all the other feature invariants; Wherein [σ] the same, φ is welded joint coefficient.The blank thickness of such pressurized container=described calculated thickness+thickness tolerance+corrosion allowance+processing attenuate amount+thickness rounding value.

Beneficial effect of the present invention and advantage are: invented a kind of structural safety, science, reasonable, economic self-reinforcing pressure vessel, provide the superstrain degree calculating formula of such container, i.e. k ²ln[ε _λ(k-1)+1] ²-(λ-1) k ²-[ε _λ(k-1)+1] ²+ λ=0, this formula has been established container thickness size (with the k reflection) and superstrain degree ε _λbetween function relation, reflected the name of the game, that has avoided that prior art calculates is rough or loaded down with trivial details, has provided definite method of such structure of container size and bearing capacity etc., and bearing capacity requires, and different (embodying with λ) can have different physical dimensions (k, k _{j λ}deng), flexible design; Found the full surrender of container under certain bearing capacity and the overall dimensions of reverse yielding do not occurred or bear the required minimum dimension k of certain load _{c λ}, by formula

definite value.The whole wall thickness of the self-reinforcing pressure vessel of constructing with technological scheme of the present invention is minimized, superstrain degree less (being conducive to save the expense while carrying out the self intensification processing), and bearing capacity is higher.By technological scheme of the present invention, can guarantee container after self intensification is processed in whole barrel every stress all be no more than the yield strength σ of cylinder material _y, compression yield does not occur, total stress perseverance in whole plastic zone is σ _y, and elastic region total stress perseverance is less than σ _y, homogenizing stress distribution, reached the equal strength design effect, each stressometer formula is simple and clear, is convenient to designing and calculating, thereby can reduce design cost.The self-reinforcing pressure vessel of therefore being constructed with technological scheme provided by the invention is a kind of safe and economic product.Pressure vessels is cylindrical shape, therefore, the present invention is directed to cylindrical pressure vessel.

The accompanying drawing explanation

Fig. 1 is the autofrettaged cylinder that is subject to interior pressure.

Fig. 2 is relatively critical footpath ratio.

Fig. 3 determines plastic zone degree of depth k under various k and λ _juse figure.

Fig. 4 determines figure for the superstrain degree under various k and λ.

Fig. 5 is k=3, k _{j λ}=1.06693, the distribution of residual stress in some barrel of λ=1.2.

Fig. 6 is k=3, k _{j λ}=1.539944, the distribution of residual stress in some barrel of λ=1.8.

Fig. 7 is k=5, k _{j λ}=1.50584, the distribution of residual stress in some barrel of λ=1.8.

The distribution of equivalent residual stress in barrel when Fig. 8 is λ=1.8, different k.

Fig. 9 is the distribution of k=3, λ=1.2 o'clock total stress.

Figure 10 is the distribution of k=3, λ=1.8 o'clock total stress.

Figure 11 is bearing capacity p/ σ _yfigure.

Figure 12 is k～λ～n graph of a relation.

Embodiment

Below analyzed at first by reference to the accompanying drawings, to prove foundation of the present invention, then provided specific embodiment.The present invention be take following condition as basis: (1) container material is fully plastoelastic, and Bauschinger (Bauschinger) effect is disregarded, and compression yield strength equals tensile yield strength; (2) disregard strain hardening; (3) material does not have defect.Under other conditions, with reference to technological scheme of the present invention, carry out.Shown in Fig. 1, be a pressure container cylinder that is subject to interior pressure, internal layer is plastic zone, and skin is elastic region, and the elastic-plastic interface radius is r _j.The large multiplex plastic material of pressurized container is made, be applicable to third and fourth theory of strength, below by the 3rd, the fourth strength theory demonstration, during without special instruction, the result of the 3rd intensity theory is marked with (III), the result of fourth strength theory is marked with (IV), and the two identical result is marked with (III, IV).

After the removal from strengthen pressure, during based on fourth strength theory, the residual stress in container wall is:

Plastic zone: $\frac{{{\mathrm{\&sigma;}}_z}^{\&prime;}}{{\mathrm{\&sigma;}}_y}=\frac{1}{\sqrt{3}}[\frac{k_j^2}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+\ln \frac{x^2}{k_j^2}-(1-\frac{k_j^2}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+\ln k_j^2)\frac{1}{k^2-1}]---\left(1\right)$

$\frac{{{\mathrm{\&sigma;}}_r}^{\&prime;}}{{\mathrm{\&sigma;}}_y}=\frac{1}{\sqrt{3}}[\frac{k_j^2}{k^2}-1+\ln \frac{x^2}{k_j^2}-(1-\frac{k_j^2}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+\ln k_j^2)\frac{1}{k^2-1}(1-\frac{k^2}{x^2})]---\left(2\right)$

$\frac{{{\mathrm{\&sigma;}}_{\mathrm{\&theta;}}}^{\&prime;}}{{\mathrm{\&sigma;}}_y}=\frac{1}{\sqrt{3}}[\frac{k_j^2}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+1+\ln \frac{x^2}{k_j^2}-(1-\frac{k_j^2}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+\ln k_j^2)\frac{1}{k^2-1}(1+\frac{k^2}{x^2})]---\left(3\right)$

By the 3rd intensity theory, the plastic zone residual stress is by formula (1)～(3)

change 2 into.

Press fourth strength theory, the equivalent stress of residual stress is:

Elastic region: $\frac{{{\mathrm{\&sigma;}}_z}^{\&prime;}}{{\mathrm{\&sigma;}}_y}=\frac{1}{\sqrt{3}}[\frac{k_j^2}{k^2}-(1-\frac{k_j^2}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+\ln k_j^2)\frac{1}{k^2-1}]---\left(5\right)$

$\frac{{{\mathrm{\&sigma;}}_r}^{\&prime;}}{{\mathrm{\&sigma;}}_y}=\frac{1}{\sqrt{3}}(1-\frac{k^2}{x^2})[\frac{k_j^2}{k^2}-(1-\frac{k_j^2}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+\ln k_j^2)\frac{1}{k^2-1}]=(1-\frac{k^2}{x^2})\frac{{{\mathrm{\&sigma;}}_z}^{\&prime;}}{{\mathrm{\&sigma;}}_y}---\left(6\right)$

$\frac{{{\mathrm{\&sigma;}}_{\mathrm{\&theta;}}}^{\&prime;}}{{\mathrm{\&sigma;}}_y}=\frac{1}{\sqrt{3}}(1+\frac{k^2}{x^2})[\frac{k_j^2}{k^2}-(1-\frac{k_j^2}{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+\ln k_j^2)\frac{1}{k^2-1}]=(1+\frac{k^2}{x^2})\frac{{{\mathrm{\&sigma;}}_z}^{\&prime;}}{{\mathrm{\&sigma;}}_y}---\left(7\right)$

By the 3rd intensity theory, the elastic region residual stress is by formula (5)～(7)

change 2 into.

Equivalent stress is: $\frac{{{\mathrm{\&sigma;}}_e}^{\&prime;}}{{\mathrm{\&sigma;}}_y}=\frac{k^2(k_j^2-1-{\ln k}_j^2)}{(k^2-1)x^2}(\mathrm{III},\mathrm{IV})---\left(8\right)$

σ wherein _z' be axial residual stress, σ _r' be radially residual stress, σ _θ' be hoop residual stress, σ _yfor the yield strength of the material of manufacturing self-reinforcing pressure vessel, the relative radius that x is arbitrfary point in cylindrical wall, x=r/r _i, r be arbitrfary point in cylindrical wall radius, σ _e' be the equivalent residual stress, indexing i means the stress at internal face place, as internal face equivalent residual stress σ _ei', indexing j means the stress of elastoplasticity interface, as elastoplasticity interface equivalent residual stress σ _ej'; All the other meet ditto.At elastoplasticity interface, r=r _j, i.e. x=k _j, now

$\frac{{{\mathrm{\&sigma;}}_{\mathrm{ej}}}^{\&prime;}}{{\mathrm{\&sigma;}}_y}=\frac{k^2(k_j^2-1-{\ln k}_j^2)}{(k^2-1)x^2}(\mathrm{III},\mathrm{IV})---\left(9\right)$

Pressurized container bears interior pressure while being p, and under elastic state, in wall, the stress at any point place is (regardless of theory of strength):

Axial stress ${\mathrm{\&sigma;}}_z^p=\frac{p}{k^2-1},$ Radial stress ${\mathrm{\&sigma;}}_r^p=(1-\frac{k^2}{x^2}){\mathrm{\&sigma;}}_z^p,$ Circumference stress ${\text{\&sigma;}}_{\mathrm{\&theta;}}^p=(1+\frac{k^2}{x^2}){\mathrm{\&sigma;}}_z^p---\left(10\right)$

Equivalent stress: $\begin{array}{cc}\frac{{\mathrm{\&sigma;}}_e^p}{{\mathrm{\&sigma;}}_y}=\frac{\sqrt{3}{k}^2}{x^2(k^2-1)}\frac{p}{{\mathrm{\&sigma;}}_y}\left(\mathrm{IV}\right)& \frac{{\mathrm{\&sigma;}}_e^p}{{\mathrm{\&sigma;}}_y}=\frac{{2k}^2}{x^2(k^2-1)}\frac{p}{{\mathrm{\&sigma;}}_y}\left(\mathrm{III}\right)---\left(11\right)\end{array}$

The elastoplasticity interface: $\begin{array}{cc}\frac{{\mathrm{\&sigma;}}_{\mathrm{ej}}^p}{{\mathrm{\&sigma;}}_y}=\frac{\sqrt{3}{k}^2}{k_j^2(k^2-1)}\frac{p}{{\mathrm{\&sigma;}}_y}\left(\mathrm{IV}\right)& \frac{{\mathrm{\&sigma;}}_{\mathrm{ej}}^p}{{\mathrm{\&sigma;}}_y}=\frac{{\sqrt{3}k}^2}{k_j^2(k^2-1)}\frac{p}{{\mathrm{\&sigma;}}_y}\left(\mathrm{III}\right)---\left(12\right)\end{array}$

Obviously, if do not carry out the self intensification processing, by formula (12), known, load surpasses or $\frac{p}{{\mathrm{\&sigma;}}_y}=\frac{k^2-1}{{2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}=\frac{p_e}{{\mathrm{\&sigma;}}_y}\left(\mathrm{III}\right)$ The time, container will produce surrender and lose efficacy.

Total stress σ/σ _yequal residual prestress and the caused stress sum of interior pressure p,

Axial total stress σ _z=σ _z'+σ _z ^p, total stress σ radially _r=σ _r'+σ _r ^p, hoop total stress σ _θ=σ _θ'+σ _θ ^p(13)

The equivalent stress sum of the equivalent stress that the equivalent stress of total stress is residual stress and the caused stress of interior pressure p

σ _e＝σ _e′+σ _e ^p(III、IV) (14)

So, in the elastoplasticity interface, the equivalent stress of total stress is σ _ej'+σ _ej ^p,

$\frac{{\mathrm{\&sigma;}}_{\mathrm{ej}}}{{\mathrm{\&sigma;}}_y}=\frac{k^2(k_j^2-1-\ln k_j^2)}{(k^2-1){\mathrm{<figure-callout\; id="2"\; label="k\; j"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}_j^{}}+\frac{\sqrt{3}{k}^2}{k_j^2(k^2-1)}\frac{p}{{\mathrm{\&sigma;}}_y}\left(\mathrm{IV}\right)\frac{{\mathrm{\&sigma;}}_{\mathrm{ej}}}{{\mathrm{\&sigma;}}_y}=\frac{k^2(k_j^2-1-{\ln k}_j^2)}{(k^2-1){\mathrm{<figure-callout\; id="2"\; label="k\; j"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}_j^{}}+\frac{{2k}^2}{k_j^2(k^2-1)}\frac{p}{{\mathrm{\&sigma;}}_y}\left(\mathrm{III}\right)---\left(15\right)$

Work as σ _ej=σ _ythe time, container enters yield situation, so make σ in formula (15) _ej/ σ _y=1

$\frac{p}{{\mathrm{\&sigma;}}_y}=\frac{k^2-{\mathrm{<figure-callout\; id="2"\; label="k\; j"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}_j^{}+{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2{\mathrm{<figure-callout\; id="2"\; label="ln\; k\; j"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">ln</figure-callout>}k}_j^{}}{\sqrt{3}{k}^2}\left(\mathrm{IV}\right),\frac{p}{{\mathrm{\&sigma;}}_y}=\frac{k^2-{\mathrm{<figure-callout\; id="2"\; label="k\; j"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}_j^{}}{2{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}+{\ln k}_j\left(\mathrm{III}\right)---\left(16\right)$

Here it is when container elastoplasticity interface starts to surrender, k, k _jwith p/ σ _ytriangular relation, or to certain k and k _j, the maximum load that container elastoplasticity interface can bear while starting to surrender.Order

$\begin{array}{cc}\frac{p}{{\mathrm{\&sigma;}}_y}=\mathrm{\&lambda;}\frac{k^2-1}{\sqrt{3}{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}=\mathrm{\&lambda;}\frac{p_e}{{\mathrm{\&sigma;}}_y}\left(\mathrm{IV}\right)& \frac{p}{{\mathrm{\&sigma;}}_y}=\mathrm{\&lambda;}\frac{k^2-1}{{2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}=\mathrm{\&lambda;}\frac{p_e}{{\mathrm{\&sigma;}}_y}\left(\mathrm{III}\right)---\left(17\right)\end{array}$

P wherein _emaximum flexibility bearing capacity (initial yield load) for unidimensional lower non-self-reinforcing pressure vessel; λ is that bearing capacity strengthens coefficient, is the multiple of bearing capacity to initial yield load.By formula (17) substitution formula (16) a sizing than under k, (now the plastic zone degree of depth is denoted as to k corresponding to the plastic zone degree of depth of a certain λ _{j λ}) calculating formula

K ²lnk _{j λ} ²-(λ-1) k ²-k _{j λ} ²+ λ=0 or $\mathrm{\&lambda;}=\frac{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2\ln k_{\mathrm{j\&lambda;}}^2+k^2-k_{\mathrm{j\&lambda;}}^2}{k^2-1}(\mathrm{III},\mathrm{IV})---\left(18\right)$

K → ∞, λ be fixedly the time, k _{j λ}=e ^{0.5 λ-0.5}.Footpath is less than by formula than k

definite value (is established this value for k _c, and be called critical footpath ratio) time, k made in formula (18) _{j λ}=k, obtain relatively critical footpath and compare k _{c λ}, under certain λ, container wall integral yield and | σ _ei' |≤σ _ymaximum diameter than (being also required path ratio, now λ maximum of the certain load of stand under load):

K _{c λ} ²lnk _{c λ} ²-λ (k _cλ ²-1)=0 or λ _max=k _{c λ} ²lnk _{c λ} ²/ (k _{c λ} ²-1), 1≤e ^{0.5 λ-0.5}≤ k _{j λ}≤ _{kc λ}(III, IV) (19)

K _{c λ max}=k _c, corresponding to λ=2, when considering compression is not surrendered, λ can be larger.If k<k _c, k _jmax=k; If k<k _c, k _jmax=k _c.

As container actual (real) thickness≤k _{c λ}the time, can entirely surrender self intensification to container and process, entirely surrender the container that self intensification is processed, its bearing capacity can reach full yield load.

On the other hand, k<k _cthe time, the container plastic zone can be whole wall thickness, and now its maximum load-carrying capacity is full yield pressure,

$\begin{array}{cc}\frac{p_y}{{\mathrm{\&sigma;}}_y}=\frac{2}{\sqrt{3}}\ln k\left(\mathrm{IV}\right)& \frac{p_y}{{\mathrm{\&sigma;}}_y}=\ln k\left(\mathrm{III}\right)---\left(20\right)\end{array}$

And under same size, the maximum flexibility bearing capacity of non-self-reinforcing pressure vessel (initial yield load) is

$\begin{array}{cc}\frac{p_e}{{\mathrm{\&sigma;}}_y}=\frac{k^2-1}{\sqrt{3}{k}^2}\left(\mathrm{IV}\right)& \frac{p_e}{{\mathrm{\&sigma;}}_y}=\frac{k^2-1}{{2k}^2}\left(\mathrm{III}\right)---\left(21\right)\end{array}$

Obtain (theory of strength is corresponding) by formula (20), (21): $\frac{p_y}{p_e}=\frac{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2\ln k^2}{k^2-1}=\mathrm{\&eta;}(\mathrm{III},\mathrm{IV})---\left(22\right)$

Formula (22) and formula (19) are identical in form, the ratio that had both meaned full yield load and initial yield load with footpath than between relation, also mean under certain λ, container wall integral yield and | σ _ei' |≤σ _ythe maximum diameter ratio.The image of formula (23) or formula (19) is as shown in Figure of description 2.

As k, k _{j λ}the relation that meets formula (18) with λ (is called k _j=k _{j λ}) time, if λ<2, the container each stress all in safety range, as, | σ _ei' |≤σ _y, σ _ei≤ σ _y, can obtain the technique effect that guarantees vessel safety.

Footpath than the relation between k, superstrain degree ε and bearing capacity enhancing coefficient lambda three is

k ²ln[ε _λ(k-1)+1] ²-(λ-1)k ²-[ε _λ(k-1)+1] ²+λ＝0 (III、IV) (23)

In formula (23), make ε=1 also obtain formula (19).The image of formula (18), (23) is shown in respectively Figure of description 3,4, and this two figure can be used for determining the plastic zone degree of depth or superstrain degree.From formula (18), (23) and Fig. 3,4, λ is larger, and the load that will bear is higher, the desired plastic zone of container degree of depth k _{j λ}or superstrain degree ε _λlarger, and footpath is larger than k, k _{j λ}or ε _λless.This is reasonable and favourable in practical implementation, because container is thicker, the self intensification intractability is larger.By technological scheme of the present invention, can process flexibly ε _λwith bearing capacity p/ σ _yrelation, formed opening Design, for engineering design has brought very big facility.

K _jby formula (18), determined, by means of formula (18), formula (1)～(8) are simplified to

σ _z′/σ _y＝(lnx ²-λ+1)/ ^30.5(IV)，σ _z′/σ _y＝(l _nx ²-λ+1)/2(III) (1a)

σ _r′/σ _y＝(lnx ²+λ/x ²-λ)/3 ^0.5(IV)，σ _r′/σ _y＝(lnx ²+λ/x ²-λ)/2(III) (2a)

σ _θ′/σ _y＝(lnx ²-λ/x ²-λ+2)/3 ^0.5(IV)，σ _θ′/σ _y＝(lnx ²-λ/x ²-λ+2)/2(III) (3a)

σ _e′/σ _y＝1-λ/x ²(III、IV) (4a)

σ _z′/σ _y≡(k _jλ ²-λ)/(3 ^0.5k ²)(IV)，σ _z′/σ _y≡(k _jλ ²λ)/(2k ²)(III) (5a)

σ _r′/σ _y＝(1-k ²/x ²)σ _z′/σ _y(IV)，σ _r′/σ _y＝(1-k ²/x ²)σ _z′/σ _y(III) (6a)

σ _θ′/σ _y＝(1+k ²/x ²)σ _z′/σ _y(IV)，σ _θ′/σ _y＝(1+k ²/x ²)σ _z′/σ _y(III) (7a)

σ _e′/σ _y＝(k _jλ ²-λ)/x ²(III、IV) (8a)

By formula (4a), known, λ≤2 o'clock, | σ _ei'/σ _y|≤1.The self-reinforcing pressure vessel of being constructed by technological scheme of the present invention, residual stress is in safety range, and bearing capacity fully improves and container thickness fully reduces.K _j=k _{j λ}, k=3 or 5, λ=1.2,1.8 o'clock, under fourth strength theory, the image of residual stress is shown in respectively Figure of description 5,6,7, due to k _j=k _{j λ}, λ<2, so have in these three kinds of situations | σ _ei' |<σ _y, visible, the self-reinforcing pressure vessel of constructing by technological scheme of the present invention can obtain the technique effect that guarantees vessel safety.

Following analysis will further illustrate the technique effect of excellence of the present invention.As, by the container of technical solution of the present invention structure, λ=1.8 o'clock, different k and k _{j λ}the equivalent stress distribution of interior the residual stress of lower whole wall (comprise mould, elastic region) is as shown in Figure of description 8 (IV).From this figure and Related Formula, | σ _e'/σ _y|≤1, i.e. removal from strengthen pressure, compression yield can not occur in container.Now this figure is described as follows:

(1) curve B AA:k=1.93322..., k _{j λ}=k=k _{c λ}=1.93322....Only have plastic zone, there is no elastic region.From a B to an A, x changes to k from 1 _{j λ}, σ _e'/σ _yfrom-0.8 monotone increasing to 0.51837....

(2) curve B CD:k=2, k _{j λ}=1.736906....The plastic zone curve is that a B arrives a some C, and x changes to k from 1 _{j λ}, σ _e'/σ _yfrom-0.8 monotone increasing to 0.40335...; The elastic region curve be a C to D, x is from k _{j λ}change to k, σ _e'/σ _ydrop to 0.304211... from the 0.40335... dullness.

(3) curve B EF:k=k _c(be the k of λ=2 o'clock _{c λ}), k _{j λ}=1.624631....The plastic zone curve is that a B arrives a some E, and x changes to k from 1 _{j λ}, σ _e'/σ _yfrom-0.8 monotone increasing to 0.318043...; The elastic region curve be an E to F, x is from k _{j λ}change to k, σ _e'/σ _ydrop to 0.170561... from the 0.318043... dullness.

(4) curve B GH:k=3, k _{j λ}=1.539944....The plastic zone curve is that a B arrives a some G, and x changes to k from 1 _{j λ}, σ _e'/σ _yfrom-0.8 monotone increasing to 0.240964...; The elastic region curve be a G to H, x is from k _{j λ}change to k=3, σ _e'/σ _ydrop to 0.063492.... from the 0.240964... dullness

(5) curve B MN:k=∞, k _{j λ}=e ^0.4.The plastic zone curve be a B to M, x changes to k from l _{j λ}=e ^0.4=1.491825..., σ _e'/σ _yfrom-0.8 monotone increasing to 1-λ/e ^0.8=0.191208...; The elastic region curve be a M to N (at infinity), x is from k _{j λ}=e ^0.4change to k=∞, σ _e'/σ _yfrom 1-λ/e ^0.8dullness drops to 0.

Point A and some B are the points of stress maximum, all do not reach yield strength.From curve B AA to curve B MN, centre has or not several curves, has sketched wherein several for above.

But, if k _j≠ k _{j λ}, i.e. k and k _jbetween can't help formula (18) while determining, will occur | σ _ei'/σ _y|>1, or bearing capacity decline, or the equivalent stress of total stress can surpass yield strength.

Grasp above characteristic and rule of great advantage for design, manufacture and the maintenance etc. of self-reinforcing pressure vessel, also will construct safe, economic self-reinforcing pressure vessel.

P=λ p _e, k _j=k _{j λ}the time, according to above technical specifications, can obtain the total stress component as follows

Plastic zone: σ _z/ σ _y=3 ^-0.5(lnx ²-λ+1+ λ k ^-2) (IV), σ _z/ σ _y=(lnx ²-λ+1+ λ k ^-2)/2 (III) (24)

σ _r/σ _y＝3 ^-0.5(lnx ²-λ+λk ^-2)(IV)，σ _r/σ _y＝3 ^-0.5(lnx ²-λ+λk ^-2)/2(III) (25)

σ _θ/σ _y＝3 ^-0.5(lnx ²-λ+2+λk ^-2)(IV)，σ _θ/σ _y＝(lnx ²-λ+2+λk ^-2)/2(III) (26)

Equivalent total stress σ _e/ σ _y≡ 1 (III, IV) (27)

Formula (27) shows, k _j=k _{j λ}and p=λ _pethe time, the equivalent stress perseverance of whole plastic zone total stress is σ _y, this has just reached the technique effect of equal strength design.

Elastic region: σ _z/ σ _y=k _{j λ} ²/ (3 ^0.5k ²) (IV), σ _z/ σ _y=k _{j λ} ²/ (2k ²) (III) (28)

σ _r/σ _y＝k _jλ ²(k ^-2-x ^-2)/(3 ^0.5)(IV)，σ _r/σ _y＝k _jλ ²(k ^-2-x ^-2)/(2)(III) (29)

σ _θ/σ _y＝k _jλ ²(k ^-2+λ ^-2)/(3 ^0.5)(IV)，σ _θ/σ _y＝k _jλ ²(k ^-2+x ^-2)/(2)(III) (30)

σ _e/σ _y＝σ _θ/σ _y-σ _r/σ _y＝k _jλ ²/x ²(III、IV) (31)

Can verify, the self-reinforcing pressure vessel of being constructed by technical solution of the present invention, total stress is in safety range, and bearing capacity fully improves and container thickness fully reduces.K=3, λ=1.2 and 1.8 o'clock, the total stress distribution situation is respectively as shown in Figure of description 9,10.Visible, self intensification container plastic zone degree of depth k _j=k _{j λ}and carrying p=λ p _ethe time, the equivalent stress perseverance of whole plastic zone total stress is σ _y, and elastic region total stress perseverance is less than yield strength.Therefore, technological scheme of the present invention has not only guaranteed the Security of container, has also reached the technique effect of equal strength design, and bearing capacity is to maximize, and has greatly improved the Economy of container.And, not according to technological scheme structure self intensification container of the present invention, just do not reach such technique effect.

According to above technological scheme, k>=k _{c λ}the time, for the footpath ratio, for k, the plastic zone degree of depth, be k _{j λ}the self intensification container, can make its bearing capacity $\frac{p}{{\mathrm{\&sigma;}}_y}=\mathrm{\&lambda;}\frac{k^2-1}{\sqrt{3}{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}=\mathrm{\&lambda;}\frac{p_e}{{\mathrm{\&sigma;}}_y}\left(\mathrm{IV}\right)$ Or $\frac{p}{{\mathrm{\&sigma;}}_y}=\mathrm{\&lambda;}\frac{k^2-1}{2{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}=\mathrm{\&lambda;}\frac{p_e}{{\mathrm{\&sigma;}}_y}\left(\mathrm{III}\right);$ K≤k _{c λ}the time, the full yield load of bearing capacity

or

the bearing capacity curve is shown in Figure of description 11 (IV), for the 3rd intensity theory, only the data under the corresponding k of Figure 11 need be multiplied by

utilize this figure can determine the optimal load of self intensification container.While not needing the considering compression surrender, allow λ>2, like this, bearing capacity will further improve.

Certain law, relation and the data that obtain in above analytic demonstration process, chart etc. make relation and the Changing Pattern between theoretical each parameter of self intensification more clear, thorough and practical.This is also that prior art is not available.

Implementation methods below is described, overall process first is described.

(1) determine size by known load.Can be determined the internal diameter r of pressurized container by technology Calculation _i, after container material determines, the load p that it is born is converted into n σ _y, i.e. p/ σ _y=n, determine that by formula (17) footpath is than k, by k=r _o/ r _idetermine external diameter r _o, by formula (18), determine k _{j λ}, or determine ε by formula (23) _λ, press k _j=r _j/ r _icalculate r _j, r _jjust can carry out self intensification after determining has processed.Formula (18), (23) can be by explicit $k=\sqrt{\frac{k_{\mathrm{j\&lambda;}}^2-\mathrm{\&lambda;}}{\ln k_{\mathrm{j\&lambda;}}^2-\mathrm{\&lambda;}+1}},k=\sqrt{\frac{{[\mathrm{\&epsiv;}(k-1)+1]}^2-\mathrm{\&lambda;}}{\ln {[\mathrm{\&epsiv;}(k-1)+1]}^2-\mathrm{\&lambda;}+1}}$ Or solve or look into and get with Fig. 3,4 with Excel software.

Suppose that pressurized container intends bearing p=n σ _yload, i.e. p/ σ _y=n, have according to formula (17)

or $\frac{p}{{\mathrm{\&sigma;}}_y}=\mathrm{\&lambda;}\frac{k^2-1}{{2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HSA0000096006680000012.png,HSA0000096006680000013.png"\; state="\{\{state\}\}">k</figure-callout>}}^2}=n\left(\mathrm{III}\right),$ Solution

$k=\sqrt{\frac{\mathrm{\&lambda;}}{\mathrm{\&lambda;}-\sqrt{3}n}}\left(\mathrm{IV}\right)$ Or $k=\sqrt{\frac{\mathrm{\&lambda;}}{\mathrm{\&lambda;}-2n}}\left(\mathrm{III}\right)---\left(32\right)$

or λ>2n (III); λ=1 o'clock, n=3 ^-0.5(IV) or n=0.5 (III), this means n>3 ^-0.5or n>0.5 o'clock, process (being λ=1) without self intensification and can not bear p/ σ _y>3 ^-0.5or p/ σ _y>0.5 load.The image of formula (32) first formulas see Figure of description 12 family of curves (in figure, 1:n=0.005,2:n=0.1,3:n=0.3,4:n=0.4,5:n=0.5,6:n=3 ^-0.5, 7:n=0.6,8:n=0.7,9:n=0.8,10:n=0.9,11:n=1,12:n=1.1 ..., 13:n=1.8 ...).Figure 12 has drawn formula (19) (all take fourth strength theory as example), i.e. curve λ=k in figure simultaneously _{c λ} ²lnk _{c λ} ²/ (k _{c λ} ²-1).By formula (32), known, λ is larger, and k is less.If the definite k by formula (32)≤by the definite k of formula (19), using by formula (19) definite k as the footpath of container than and container is taked entirely to surrender self intensification and processes, its bearing capacity can be full yield load.When the k=definite by formula (32) k definite by formula (19),

(IV) or n=p/ σ y=lnk be k=exp (n)=exp (p/ σ _y) (III), this is the minimum k of formula (32) gained, now k must be arranged _j=k, just can bear respective loads, and λ reaches maximum simultaneously

${\mathrm{\&lambda;}}_{\max }=\frac{{\sqrt{3}\mathrm{ne}}^{\sqrt{3}n}}{e^{\sqrt{3}n}-1}\left(\mathrm{IV}\right)$ Or ${\mathrm{\&lambda;}}_{\max }=\frac{{2\mathrm{ne}}^{2n}}{e^{2n}-1}\left(\mathrm{III}\right)---\left(33\right)$ Utilize formula (32) or Figure 12, to certain load (embodying with n), can do flexible configuration and adjustment between λ and k, this has just reached the technique effect that forms flexible and changeable design proposal.

(2) determine by known dimensions the load that container can bear.From 1～k _{e λ}get different k _{j λ}, by k (size does not turn to the footpath ratio with footpath than appearance), according to the same form after formula (18), calculate to obtain λ, bearing capacity is λ pe.

In following examples, the content in bracket is the result by the 3rd intensity theory.

Embodiment 1, supposes that certain pressurized container intends bearing 0.5 σ _yload, i.e. n=0.5<3 ^-0.5, 3 ^-0.5n=0.866<1, allow λ=1 (minimum).According to above analysis, the time, by formula (19), definite footpath ratio equals the footpath ratio definite by formula (32).K=1.541896 (e ^0.5) time, all obtained λ=1.494745 (1.581977) (the highest) by formula (33), (32), (19).

(1) λ=1, obtain k=2.732051 (∞, meaningless) by formula (32).And according to formula (19), λ=1 o'clock, k=1<2.732051.Therefore get k=2.732051.K _j=1, do not carry out the self intensification processing.The container of this structural parameter is non-self intensification container.Thickness is larger.

(2) λ=1.2, obtain k=1.895544 (2.44949) by formula (32).And according to formula (19), λ=1.2 o'clock, k=1.208<1.895544.Therefore get k=1.895544 (2.44949).When λ=1.2, k=1.895544 (2.44949), by formula (18), obtain k _{j λ}=1.11018 (1.10765).The structural parameter that are container are k=1.895544 (2.44949), k _{j λ}=1.11018 (1.10765).This is than the thickness reduction in situation (1)

k wherein ₁, k ₂be respectively and reduce forward and backward footpath ratio.

The equivalent residual stress obtains respectively by formula (4a) with (8a)

Plastic zone [1≤x≤1.11018 (1.10765)]: σ _e'/σ _y=1-λ/x ²=1-1.2/x ².σ _e'/σ _yfrom-0.2 monotone increasing of internal face to 0.026 (0.022) of elastoplasticity interface, safety.

Elastic region [1.11018 (1.10765)≤x≤1.895544 (2.44949)]: σ _e'/σ _y=(k _{j λ} ²-λ)/x ²=(1.11018 ²-1.2)/x ².

σ _e'/σ _ybe reduced to 0.009 (0.0045) of outer wall, safety from 0.026 (0.022) dullness at elastoplasticity interface.

The equivalent total stress is obtained respectively by formula (27) and (31)

Plastic zone [1≤x≤1.11018 (1.10765)]: σ _e≡ σ _y, safety.

Elastic region [1.11018 (1.10765)≤x≤1.895544 (2.44949)]: σ _e/ σ _y=k _{j λ} ²/ x ².σ _e/ σ _ybe reduced to 0.343 (0.204) of outer wall, safety from 1 dullness at elastoplasticity interface.

(3) λ=1.4, obtain k=1.619212 (1.870829) by formula (32).And according to formula (19) λ=1.4 o'clock, k=1.43005<1.619212.Therefore get k=1.619212 (1.870829).When λ=1.4, k=1.619212 (1.870829), by formula (18), obtain k _{j λ}=1.27527 (1.25016).Being that extracting container footpath ratio is k=1.619212 (1.870829), is k and make the plastic zone degree of depth _{j λ}=1.27527 (1.25016) self intensification is processed.This has reduced again 30.9% (82.7%) than the thickness in situation (2).

The equivalent residual stress

Plastic zone [1≤x≤1.27527 (1.25016)]: σ _e'/σ _yfrom-0.4 monotone increasing of internal face to 0.139 (0.104) of elastoplasticity interface, safety.

Elastic region [1.27527 (1.25016)≤x≤1.619212 (1.870829)]: σ _e'/σ _ybe reduced to 0.086 (0.0465) of outer wall, safety from 0.139 (0.104) dullness at elastoplasticity interface.

The equivalent total stress

Plastic zone [1≤x≤1.27527 (1.25016)]: σ _e≡ σ _y, safety.

Elastic region [1.27527 (1.25016)≤x≤1.619212 (1.870829)]: σ _e/ σ _ybe reduced to 0.62 (0.4465) of outer wall, safety from 1 dullness at elastoplasticity interface.

(4) λ=1.494745 (1.581977), obtain k=1.541896 (e by formula (32) ^0.5), with by formula (19), calculated k identical.Do full surrender and process, be i.e. k=k _{j λ}=1.541896 (e ^0.5) time, can bear 0.5 σ _yload.This has reduced again 12.5% (25.5%) than the thickness in situation (3).

The equivalent residual stress

Plastic zone [1≤x≤1.541896 (e ^0.5)]: σ _e'/σ _yfrom-0.49 (0.58) monotone increasing of internal face to 0.37 (0.418) of elastoplasticity interface, safety.Nonelastic district.

The equivalent total stress

Plastic zone [1≤x≤1.541896 (e ^0.5)]: σ _e≡ σ _y, safety.

Embodiment 2, establish certain container and intend the load of bearing 0.8 σ y, or λ>=2n=1.6 (III) (minimum).According to above analysis,

the time, by formula (19), definite footpath ratio equals the footpath ratio definite by formula (33).K=1.999346 (e ^0.8) time, all obtained λ=1.847923 (2.004753) (the highest) by formula (33), (32), (19).

(1) λ=1.4 (the theoretical palpus of the 3rd intensity λ >=1.6, λ=1.4 o'clock no third theory of strength result), obtain k=9.874078 by formula (32).And according to formula (19), λ=1.4 o'clock, k=1.430048 (seeing the b point of Figure of description 3)<9.874078.Therefore get k=9.874078.When λ=1.4, k=9.874078, by formula (18), obtain k _{j λ}=1.221987.The structural parameter that are container are k=9.874078, k _{j λ}=1.221987.

The equivalent residual stress

Plastic zone (1≤x≤1.221987): σ _e'/σ _yfrom-0.4 monotone increasing of internal face to 0.062 of elastoplasticity interface, safety.

Elastic region (1.221987≤x≤9.874078): σ _e'/σ _ybe reduced to 0.00096 of outer wall, safety from 0.062 dullness at elastoplasticity interface.

The equivalent total stress

Plastic zone (1≤x≤1.27527): σ _e≡ σ _y, safety.

Elastic region (1.27527≤x≤1.619212): σ _e/ σ _ybe reduced to 0.015 of outer wall, safety from 1 dullness at elastoplasticity interface.

(2) λ=1.5, obtain k=3.621678 by formula (32).And according to formula (19) λ=1.5 o'clock, k=1.548222<3.621678.Therefore get k=3.621678.When λ=1.5, k=3.621678, by formula (18), obtain k _{j λ}=1.292386.The structural parameter that are container are k=3.621678, k _{j λ}=1.292386.This than the thickness reduction in situation (1) 70.5%, and the plastic zone degree of depth is more or less the same.

The equivalent residual stress

Plastic zone (1≤x≤1.292386) :-0.6≤σ _e'/σ _y≤ 0.042, safety.

Elastic region (1.292386≤x≤3.621678): 0.005≤σ _e'/σ _y≤ 0.042, safety.

The equivalent total stress

Plastic zone (1≤x≤1.292386): σ _e≡ σ _y, safety.

Elastic region (1.292386≤x≤3.621678): 0.127≤σ _e/ σ _y≤ 1, safety.

(3) λ=1.7, obtain k=2.325473 (4.123106) by formula (32).And according to formula (19), λ=1.7 o'clock, k=1.799499<2.325473.Therefore get k=2.325473 (4.123106).When λ=1.7, k=2.325473 (4.123106), by formula (18), obtain k _{j λ}=1.488262 (1.434022).Being that extracting container footpath ratio is k=2.325473 (4.123106), is k and make the plastic zone degree of depth _{j λ}=1.488262 (1.434022) self intensification is processed.This has reduced again 49.4% than the thickness in situation (2).

The equivalent residual stress

Plastic zone [1≤x≤1.488262 (1.434022)] :-0.7≤σ _e'/σ _y≤ 0.23 (0.17), safety.

Elastic region [1.488262 (1.434022)≤x≤2.325473 (4.123106)]: 0.095 (0.021)≤σ _e'/σ _y≤ 0.23 (0.17), safety.

The equivalent total stress

Plastic zone [1≤x≤1.488262 (1.434022)]: σ _e≡ σ _y, safety.

Elastic region [1.488262 (1.434022)≤x≤2.325473 (4.123106)]: 0.41 (0.121)≤σ _e/ σ _y≤ 1, safety.

(4) λ=1.847923 (2.004753), by formula (32) k=1.999346 (2.22554), with by formula (19), calculated k identical.Do full surrender and process, be i.e. k=k _{j λ}in the time of=1.999346 (2.22554), can bear 0.8 σ _yload.This has reduced again 24.6% (60.8%) than the thickness in situation (3).

The equivalent residual stress

Plastic zone [1≤x≤1.999346 (2.22554)]: σ _e'/σ _yfrom-0.85 (1.005) monotone increasing of internal face to 0.54 (0.6) of elastoplasticity interface, safety.Nonelastic district.

The equivalent total stress

Plastic zone [1≤x≤1.999346 (2.22554)]: σ _e≡ σ _y, safety.

Embodiment 3, suppose that pressurized container intends bearing σ _yload, i.e. n=1>3 ^-0.5, should have

or λ>=2n=2 (III) (minimum).According to above analysis,

the time, by formula (19), definite footpath ratio equals the footpath ratio definite by formula (32).During k=2.377443 (e), all obtained λ=2.104356 (2.313035) (the highest) by formula (33), (32), (19).

(1) λ=1.8 (no third theory of strength result), obtain k=5.146881 by formula (32).And according to formula (19), λ=1.8 o'clock, k=1.93322<5.146881.Therefore get k=5.146881.When λ=1.8, k=5.146881, by formula (18), obtain k _{j λ}=1.504974.The structural parameter that are container are k=5.146881, k _{j λ}=1.504974.

The equivalent residual stress

Plastic zone (1≤x≤1.504974) :-0.8≤σ _e'/σ _y≤ 0.21, safety.

Elastic region (1.504974≤x≤5.146881): 0.018≤σ _e'/σ _y≤ 0.21, safety.

The equivalent total stress

Plastic zone (1≤x≤1.504974): σ _e≡ σ _y, safety.

Elastic region (1.504974≤x≤≤ 5.146881): 0.086≤σ _e/ σ _y≤ 1, safety.

(2) λ=2, obtain k=2.732051 (∞, meaningless) by formula (32).And according to formula (19) λ=2 o'clock, k=2.2184574899167... (=k _c)<2.732051.Therefore get k=2.732051.When λ=2, k=2.732051, by formula (18), obtain k _{j λ}=1.785136.The structural parameter that are container are k=2.732051, k _{j λ}=1.785136.This than the thickness reduction in situation (1) 58.2%.

The equivalent residual stress

Plastic zone (1≤x≤1.785136) :-1≤σ _e'/σ _y≤ 0.37, safety.

Elastic region (1.785136≤x≤2.732051): 0.16≤σ _e'/σ _y≤ 0.37, safety.

The equivalent total stress

Plastic zone (1≤x≤1.785136): σ _e≡ σ _y, safety.

Elastic region (1.785136≤x≤2.732051): 0.43≤σ _e/ σ _y≤ 1, safety.

(3) λ=2.104356 (2.313035) (if considering compression surrender), by formula (32) k=2.377443 (e), with by formula (19), calculated k identical.Do full surrender and process, be i.e. k=k _{j λ}when=2.377443 (e), can bear σ _yload.This has reduced again 20.5% than the thickness in situation (2).

Equivalent residual stress: plastic zone [1≤x≤2.377443 (e)] :-1.1 (1.31)≤σ _e'/σ _y≤ 0.63 (o.69), safety.Nonelastic district.Equivalent total stress: plastic zone [1≤x≤2.377443 (e)]: σ _e≡ σ _y, safety.

Embodiment 4, suppose the load that a pressurized container plan is born p=200MPa, adopt the 0Cr19Ni9 steel, the yield strength σ of this steel grade _y=206MPa, so n=p/ σ _y=0.970874>3 ^-0.5, should have

or λ>=2n=1.941748 (III) (minimum).

the time, by formula (19), definite footpath ratio equals the footpath ratio definite by formula (32).During k=2.318224 (2.64025), all obtained λ=2.066043 (2.266948) (the highest) by formula (33), (32), (19).

(1), must there be k=∞ λ=1.681603 o'clock, therefore get λ=1.7, by formula (32), obtains k=9.612848.And according to formula (19) λ=1.7 o'clock, k=1.799499<9.612848.Therefore get k=9.612848.When λ=1.7, k=9.612848, by formula (18), obtain k _{j λ}=1.421533.The structural parameter that are container are k=9.612848, k _{j λ}=1.421533.

The equivalent residual stress

Plastic zone (1≤x≤1.421533) :-0.7≤σ _e'/σ _y≤ 0.16, safety.

Elastic region (1.421533≤x≤9.612848): 0.0035≤σ _e'/σ _y≤ 0.16, safety.

The equivalent total stress

Plastic zone (1≤x≤1.421533): σ _e≡ σ _y, safety.

Elastic region (1.421533≤x≤9.612848): 0.022≤σ _e/ σ _y≤ 1, safety.

(2) λ=2, obtain k=2.506286 (5.859) by formula (32).And according to formula (19), λ=2 o'clock, k=2.2184574899167... (=k _c)<2.506286.Therefore get k=2.506286 (5.859).When λ=2, k=2.506286 (5.859), by formula (18), obtain k _{j λ}=1.842108 (1.667579).The structural parameter that are container are k=2.506286 (5.859), k _{j λ}=1.842108 (1.667579).This than the thickness reduction in situation (1) 82.5%.

The equivalent residual stress

Plastic zone [1≤x≤1.842108 (1.816631)] :-1≤σ _e'/σ _y≤ 0.41 (0.39), safety.

Elastic region [1.842108 (1.816631)≤x≤2.506286 (2.589)]: 0.22 (0.19)≤σ _e'/σ _y≤ 0.41 (0.39), safety.

The equivalent total stress

Plastic zone [1≤x≤1.842108 (1.816631)]: σ _e≡ σ _y, safety.

Elastic region [1.842108 (1.816631)≤x≤2.506286 (2.589)]: 0.54 (0.49)≤σ _e/ σ _y≤ 1, safety.

(3) λ=2.066043 (2.266948) (the highest) (if not considering compression surrender), all obtain k=2.318224 (2.64025) by formula (32) and formula (19).Do full surrender and process, be i.e. k=k _{j λ}in the time of=2.318224 (2.64025), can bear the load of 200MPa.This has reduced again 12.5% (66.24%) than the thickness in situation (2).

Plastic zone (1≤x≤2.318224 (2.64025)) equivalent residual stress :-1.07 (1.27)≤σ _e'/σ _y≤ 0.62 (0.67), safety.

Nonelastic district.Total stress: σ _e≡ σ _y, safety.

Embodiment 5, k=1.5<k _c.

(1) k _j=1, λ=1, do not do self intensification and process, and directly by formula (21), can obtain p/ σ _y=0.32 (0.28).

(2) k _jmax=1.5 (full surrenders), obtain p/ σ by formula (20) _y=0.48 (0.41).

Embodiment 6, k=2.5>k _c.

(1) k _j=1, λ=1, do not do self intensification and process, and directly by formula (20), can obtain p/ σ _y=p _e/ σ _y=0.48 (0.42).

(2) k _j=1.2, obtain λ=1.350289, p=λ p by formula (18) _e=0.655 (0.567) σ _y.

Equivalent residual stress (third and fourth theory of strength comes to the same thing, lower same)

Plastic zone (1≤x≤1.2) :-0.35≤σ _e'/σ _y≤ 0.06, safety.

Elastic region (1.2≤x≤2.5): 0.01≤σ _e'/σ _y≤ 0.06, safety.

The equivalent total stress

Plastic zone (1≤x≤1.2): σ _e≡ σ _y, safety.

Elastic region (1.2≤x≤2.5): 0.23≤σ _e/ σ _y≤ 1, safety.

(3) k _j=1.5, obtain λ=1.727298 by formula (18), p=λ= _e=0.838 (0.725) σ _y.

The equivalent residual stress

Plastic zone (1≤x≤1.5) :-0.727≤σ _e'/σ _y≤ 0.232, safety.

Elastic region (1.5≤x≤2.5): 0.083≤σ _e'/σ _y≤ 0.232, safety.

The equivalent total stress

Plastic zone (1≤x≤1.5): σ _e≡ σ _y, safety.

Elastic region (1.5≤x≤2.5): 0.358≤σ _e/ σ _y≤ 1, safety.

(4) k _j=1.8, obtain λ=1.972825, p=λ p by formula (18) _e=0.957 (0.829) σ _y.

The equivalent residual stress

Plastic zone (1≤x≤1.8) :-0.97≤σ _e'/σ _y≤ 0.39, safety.

Elastic region (1.8≤x≤2.5): 0.2≤σ _e'/σ _y≤ 0.39, safety.

The equivalent total stress

Plastic zone (1≤x≤1.8): σ _e≡ σ _y, safety.

Elastic region (1.8≤x≤2.5): 0.52≤σ _e/ σ _y≤ 1, safety.

(5) k _j=1.844363, obtain λ=2, p=λ p by formula (18) _e=0.97 (0.84) σ _y.

The equivalent residual stress

Plastic zone (1≤x≤1.844363) :-1≤σ _e'/σ _y≤ 0.41, safety.

Elastic region (1.844363≤x≤2.5): 0.22≤σ _e'/σ _y≤ 0.41, safety.

The equivalent total stress

Plastic zone (1≤x1.844363): σ _e≡ σ _y, safety.

Elastic region (1.844363≤x≤2.5): 0.54≤σ _e/ σ _y≤ 1, safety.

(6) k _j=1.9, obtain λ=2.031081, p=λ p by formula (18) _e=0.985 (0.853) σ _y.

The equivalent residual stress

Plastic zone (1≤x≤1.9) :-1.03≤ _e'/σ _y≤ 0.44, safety.

Elastic region (1.9≤x≤2.5): 0.25≤σ _e'/σ _y≤ 0.44, safety.

The equivalent total stress

Plastic zone (1≤x≤1.9): σ _e≡ σ _y, safety.

Elastic region (1.9≤x≤2.5): 0.57≤σ _e/ σ _y≤ 1, safety.

Above example shows, technological scheme of the present invention can construct the self-reinforcing pressure vessel of Different structural parameters.

Claims (5)

1. the equal strength self-reinforcing pressure vessel that physical dimension is variable is characterized in that: the physical dimension of this self-reinforcing pressure vessel and bearing capacity determine by particular requirement, and specifically: (1) footpath is greater than by formula than k

definite k _{c λ}the self-reinforcing pressure vessel of value, its superstrain degree is determined by following formula:

k ²ln[ε _λ(k-1)+1] ²-(λ-1)k ²-[ε _λ(k-1)+1] ²+λ＝0，

Its bearing capacity p/ σ _ydetermine as follows:

(fourth strength theory) or

(the 3rd intensity theory), its calculated thickness t determines as follows:

(fourth strength theory) or

(the 3rd intensity theory):

Wherein

K be footpath than (characterizing the physical dimension of this kind of self-reinforcing pressure vessel), equal self-reinforcing pressure vessel outer radius r _owith inside radius r _jratio, k=r _o/ r _i,

K _{c λ}for relatively critical footpath ratio, corresponding to the footpath ratio of λ,

λ is that bearing capacity strengthens coefficient, λ=p/p _e, the scope of λ is 1～+ ∞,

P is the interior pressure that self-reinforcing pressure vessel bears, or the title calculating pressure,

P _efor the maximum flexibility bearing capacity of non-self-reinforcing pressure vessel under same size (initial yield load),

ε _λfor the superstrain degree,

σ _yyield strength for the material of manufacturing self-reinforcing pressure vessel;

When this kind of self-reinforcing pressure vessel bears p=n σ _yload the time (wherein n is the scaling factor of load to yield strength), its footpath is than by formula

(fourth strength theory), or (the 3rd intensity theory) determined, different λ obtains different footpaths than k, thereby obtains different wall thickness, to form motor-driven design proposal; (2) k is less than or equal to by formula

definite k _{c λ}the self-reinforcing pressure vessel of value, its plastic zone scope allows for whole wall thickness, and now its maximum load-carrying capacity is full yield pressure,

(fourth strength theory), or (the 3rd intensity theory); Its footpath ratio is

(fourth strength theory), or

(the 3rd intensity theory); Its calculated thickness is (fourth strength theory), or

(the 3rd intensity theory).

2. the variable equal strength self-reinforcing pressure vessel of physical dimension according to claim 1, is characterized in that: physical dimension (k, the k of every stress at any point place and container in wall _{j λ}), magnitude of load (λ) is by following relation constraint:

(1) press fourth strength theory, its residual stress relation is:

Plastic zone: axial residual stress

Residual stress radially

The hoop residual stress

The equivalent residual stress

Elastic region: axial residual stress

Residual stress radially

The hoop residual stress

The equivalent residual stress

(2) press fourth strength theory, its total stress relation is:

Plastic zone: axial total stress

Total stress radially

The hoop total stress

Equivalent total stress σ _e≡ σ _y;

Elastic region: axial total stress

Total stress radially

The hoop total stress

The equivalent total stress

(3) by the 3rd intensity theory, its residual stress relation is:

Plastic zone: axial residual stress

Residual stress radially

The hoop residual stress

The equivalent residual stress

Elastic region: axial residual stress

Residual stress radially

The hoop residual stress

The equivalent residual stress

(4) by the 3rd intensity theory, its total stress relation is:

Plastic zone: axial total stress

Total stress radially

The hoop total stress

Equivalent total stress σ _e≡ σ _y;

Elastic region: axial total stress

Total stress radially

The hoop total stress

The equivalent total stress

X=r/r wherein _i, r be container any point place radius, k _{j λ}for the plastic zone degree of depth of container corresponding to λ, it equals container plastic zone radius r _jwith inside radius r _iratio, all the other symbols as claimed in claim 1.

3. the variable equal strength self-reinforcing pressure vessel of physical dimension according to claim 1 and 2, is characterized in that: with allowable stress [σ], replace described yield strength σ _y, all the other feature invariants; And [σ]=min{ σ _b/ n _b, σ _y/ n _y, σ _0.2/ n _y, σ _y ^t/ n _y ^t, σ _0.2 ^t/ n _y ^t, σ _d ^t/ n _d, σ _n ^t/ n _n, σ wherein _bfor tensile strength, n _bfor corresponding to σ _bsafety coefficient (design of material coefficient), σ _0.2be 0.2% Non-proportional extension intensity, n _yfor corresponding to σ _ywith σ _0.2safety coefficient (design of material coefficient), σ _y ^tfor the yield strength under design temperature, σ _0.2 ^tfor 0.2% Non-proportional extension intensity, the n under design temperature _y ^tfor corresponding to σ _y ^twith σ _0.2 ^tsafety coefficient (design of material coefficient), σ _d ^tfor the creep rupture strength under design temperature, n _dfor corresponding to σ _d ^tsafety coefficient (design of material coefficient), σ _n ^tfor the creep limit under design temperature, n _nfor corresponding to σ _n ^tsafety coefficient (design of material coefficient).

4. the variable equal strength self-reinforcing pressure vessel of physical dimension according to claim 1 and 2, is characterized in that: with [σ] φ, replace σ _y, all the other feature invariants; Wherein [σ] is welded joint coefficient with claim 3, φ.

5. the variable equal strength self-reinforcing pressure vessel according to the described physical dimension of one of claim 1 to 4, is characterized in that: the blank thickness of such pressurized container=described calculated thickness+thickness tolerance+corrosion allowance+processing attenuate amount+thickness rounding value.

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