JPH0915291A - Fault point locating method for parallel two-line transmission and distribution line - Google Patents
Fault point locating method for parallel two-line transmission and distribution lineInfo
- Publication number
- JPH0915291A JPH0915291A JP16050995A JP16050995A JPH0915291A JP H0915291 A JPH0915291 A JP H0915291A JP 16050995 A JP16050995 A JP 16050995A JP 16050995 A JP16050995 A JP 16050995A JP H0915291 A JPH0915291 A JP H0915291A
- Authority
- JP
- Japan
- Prior art keywords
- terminal
- line
- lines
- parallel
- failure
- Prior art date
- Legal status (The legal status is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the status listed.)
- Granted
Links
Landscapes
- Locating Faults (AREA)
Abstract
Description
【0001】[0001]
【産業上の利用分野】本発明は、2端子系並行2回線送
配電線の片端子で検出される電流電圧情報に基づいて、
両回線にわたる同相異地点に発生する故障点の標定を行
うことができる故障点標定方法に関するものである。送
配電線は、電力供給の信頼度向上のため、一般的に並行
2回線方式で送電されている。前記送配電線は、建物内
で保守管理されている変電所と比較して、落雷、樹木の
接触等の自然環境に起因する故障(地絡・短絡)が不可
避であり、故障発生時には、故障点探索作業が伴う。特
に、山間部における故障点探索は非常に困難な場合があ
る。BACKGROUND OF THE INVENTION The present invention is based on current / voltage information detected at one terminal of a two-terminal parallel two-line transmission / distribution line.
The present invention relates to a fault point locating method capable of locating a fault point that occurs at different points in the same phase across both lines. Transmission and distribution lines are generally transmitted by a parallel two-line system in order to improve the reliability of power supply. Compared to the substations that are maintained and managed in the building, the transmission and distribution lines are inevitable for failures (ground faults / short circuits) due to the natural environment such as lightning strikes and contact with trees. Point search work is involved. In particular, it may be very difficult to search for a failure point in a mountain area.
【0002】前記故障例としては、一地点における一
回線の故障、端子(送電端または受電端)から異なる
地点における一回線の故障、端子から等距離の地点に
おける両回線にわたる故障(例えば、一方の回線のa相
地絡と他方の回線のa相地絡のように同相の地絡故障、
一方の回線のa−b相間短絡と他方の回線のc相地絡等
のように異相の故障)、端子から異なる距離における
両回線の故障(この場合も、同相故障と異相故障とがあ
る)がある。前記の故障は一般に多重故障と言わ
れているが、本願では前記、特に、両回線の異地点に
おける同相故障を取り扱う。Examples of the failure include failure of one line at one point, failure of one line at a point different from a terminal (power transmitting end or power receiving end), and failure of both lines at a point equidistant from the terminal (for example, one of In-phase ground fault such as a-phase ground fault of the line and a-phase ground fault of the other line,
Failure of different phase such as a-b short circuit between one line and c-phase ground fault of the other line), failure of both lines at different distances from terminals (also in this case, common-mode failure and out-of-phase failure) There is. Although the above-mentioned failures are generally referred to as multiple failures, the present application deals with the above-mentioned failures, particularly, common-mode failures at different points on both lines.
【0003】両回線にまたがった異地点における同相故
障は、例えば、1本の雷が空中で枝分かれして異地点に
落ちてともに同相間で短絡する場合、同じ2相が地絡
(2相短絡と等しい)する場合、又は3相とも短絡若し
くは地絡する場合にそれぞれ発生する。本発明は、この
場合に片端の電流電圧情報に基づいて、故障点の標定を
行うことができる故障点標定方法に関するものである。A common-mode fault at a different point across both lines is, for example, when one lightning branches in the air and drops to a different point and short-circuits between the same phases. (Equal to), or when all three phases are short-circuited or grounded. The present invention relates to a fault point locating method capable of locating a fault point based on current / voltage information at one end in this case.
【0004】[0004]
【従来の技術】前記のように、両回線にまたがった異地
点における同相故障の標定をするには、従来では、両端
の電流電圧情報に基づいて故障標定をしていた。図1
は、2端子系並行2回線送配電線で、両回線にまたがっ
た異地点における同相故障が発生したときを示す回路図
であり、故障点の距離は端子1からそれぞれxと、yで
あるとする。配電線の全長をd、端子1の電圧をV1 、
端子2の電圧をV2 、端子1で回線1Lを流れる電流を
I11、端子1で回線2Lを流れる電流をI12、端子2で
回線1Lを流れる電流をI21、端子2 で回線2Lを流れ
る電流をI22とする。線路の単位長さ当たりの自己イン
ピーダンスをZs 、単位長さ当たりの回線間の相互イン
ピーダンスをZm とする。なお、この明細書では、電圧
V、電流Iを表わす記号V,Iは振幅と位相を含んだベ
クトルを表わすものとする。2. Description of the Related Art As described above, in order to locate a common-mode fault at different points across both lines, conventionally, fault localization was performed based on current-voltage information at both ends. FIG.
Is a circuit diagram showing a two-terminal parallel two-line transmission / distribution line when a common-mode fault occurs at different points across both lines, and the distances of the fault points are x and y from terminal 1, respectively. To do. The total length of the distribution line is d, the voltage of terminal 1 is V 1 ,
The voltage of the terminal 2 is V 2 , the current flowing through the line 1L at the terminal 1 is I 11 , the current flowing through the line 2L at the terminal 1 is I 12 , the current flowing through the line 1L at the terminal 2 is I 21 , and the line 2L at the terminal 2 is The flowing current is I 22 . Let Z s be the self-impedance per unit length of the line and Z m be the mutual impedance between the lines per unit length. In this specification, symbols V and I representing voltage V and current I represent vectors including amplitude and phase.
【0005】前記の回路で、故障点の電位を0と近似す
る。この近似は、超高圧送配電線(27.5kV,50
0kVなど)では十分に成立する。キルヒホッフの法則
を適用すれば、 V1 −xZs I11−xZm I12=0 (1) V1 −yZs I12−xZm I11+(y−x)Zm I21=0 (2) V2 −(d−x)Zs I21−(d−y)Zm I22+(y−x)Zm I12=0 (3) V2 −(d−y)Zs I22−(d−y)Zm I21=0 (4) が成立する。前記(1) 式より、 x=V1 /(Zs I11+Zm I12) (5) 前記(2) 式より、 y={V1 −x(Zm I11+Zm I21)}/(Zs I12+Zm I21) (6) が導かれる。In the above circuit, the potential at the fault point is approximated to zero. This approximation is based on ultra high voltage transmission and distribution lines (27.5 kV, 50
0 kV) is sufficient. By applying Kirchhoff's law, V 1 -xZ s I 11 -xZ m I 12 = 0 (1) V 1 -yZ s I 12 -xZ m I 11 + (y-x) Z m I 21 = 0 ( 2) V 2 − (d−x) Z s I 21 − (d−y) Z m I 22 + (y−x) Z m I 12 = 0 (3) V 2 − (d−y) Z s I 22 − (d−y) Z m I 21 = 0 (4) holds. From the equation (1), x = V 1 / (Z s I 11 + Z m I 12 ) (5) From the equation (2), y = {V 1 −x (Z m I 11 + Z m I 21 )} / (Z s I 12 + Z m I 21 ) (6) is derived.
【0006】前記(5) 式を見れば分かるように、回線1
Lの故障距離xは、端子1の電流値I11,I12及び電圧
値V1 を用いて求めることができる。As can be seen from the equation (5), the line 1
The failure distance x of L can be obtained by using the current values I 11 and I 12 of the terminal 1 and the voltage value V 1 .
【0007】[0007]
【発明が解決しようとする課題】しかし、前記(6) 式を
見れば、回線2Lの故障距離yは、端子1の電流値
I11,I12及び電圧値V1 のみでは求めることができ
ず、端子2の電流値I21が必要であることが分かる。こ
の端子2の電流値I21を知ろうとすれば、端子2での測
定値を通信回線を通して端子1に伝送し、伝送遅れを補
正して端子1の測定値との同期をとる必要があった。However, from the equation (6), the failure distance y of the line 2L cannot be obtained only by the current values I 11 , I 12 and the voltage value V 1 of the terminal 1. It is understood that the current value I 21 of the terminal 2 is necessary. In order to know the current value I 21 of the terminal 2, it is necessary to transmit the measured value at the terminal 2 to the terminal 1 through the communication line, correct the transmission delay, and synchronize with the measured value at the terminal 1. .
【0008】このため、通信回線を布設して同期をとる
ための装置が必要となり、システム構成が複雑化しコス
ト高になるので、2端子系並行2回線送配電線の片端子
で検出される電流電圧情報のみに基づいて、両回線にわ
たる同相異地点に発生する故障点の標定を正確に行う方
法の実現が求められていた。そこで、本発明は、上述の
技術的課題を解決し、2端子系並行2回線送配電線の片
端子で検出される電流電圧情報に基づいて、両回線にわ
たる同相異地点に発生する故障点の標定を正確にするこ
とのできる故障点標定方法を提供することを目的とす
る。Therefore, a device for laying a communication line for synchronization is required, and the system configuration becomes complicated and the cost becomes high. Therefore, the current detected at one terminal of the two-terminal parallel two-line transmission / distribution line There has been a demand for realization of a method for accurately locating a failure point that occurs at different points in the same phase on both lines based only on voltage information. Therefore, the present invention solves the above-mentioned technical problem, and based on the current-voltage information detected at one terminal of a two-terminal system parallel two-line transmission / distribution line, the failure point occurring at the common point on both lines It is an object of the present invention to provide a fault point locating method capable of accurately locating.
【0009】[0009]
【課題を解決するための手段】前記の目的を達成するた
めの請求項1記載の故障点標定方法は、2端子系並行2
回線送配電線の一端子で検出される電流電圧情報に基づ
いて、両回線にわたる異地点に発生する同相故障点の標
定を行う方法であって、回線1L,2Lからなる並行2
回線送配電線の一端子における電流値、電圧値として、
故障に係わる相の電流値I11,I12、電圧値V1 を取得
し、これらの取得された電流値I11,I12、電圧値V1
にもとづいて、下記演算式(7) (8) を用いて、当該端子
から短いほうの故障点までの距離x、及び当該端子から
長いほうの故障点までの距離yを求める方法である。A fault point locating method according to claim 1 for achieving the above object is a two-terminal system parallel 2
A method of locating a common-mode fault point that occurs at different points across both lines based on current / voltage information detected at one terminal of the line transmission / distribution line.
As the current value and voltage value at one terminal of the line transmission and distribution line,
Phase current value I 11 according to the fault, I 12, and acquires the voltage value V 1, these acquired current value I 11, I 12, the voltage value V 1
Based on the above, the following formulas (7) and (8) are used to obtain the distance x from the relevant terminal to the shorter failure point and the distance y from the relevant terminal to the longer failure point.
【0010】 x=V1 /(Zs I11+Zm I12) (7) y={V1 −xZm (I11−I12)}/(Zs −Zm )I12 (8) また、請求項2記載の故障点標定方法は、前記請求項1
記載の故障点標定方法において、2端子系並行2回線送
配電線の線路の配置が回線相互で対称となっていること
を前提とする。X = V 1 / (Z s I 11 + Z m I 12 ) (7) y = {V 1 −xZ m (I 11 −I 12 )} / (Z s −Z m ) I 12 (8) The fault point locating method according to claim 2 is the method according to claim 1.
In the fault location method described, it is assumed that the lines of the two-terminal parallel two-line transmission / distribution line are arranged symmetrically with each other.
【0011】[0011]
【作用】本発明の作用を説明する。図1は、2端子系並
行2回線送配電線で、両回線にまたがった異地点におけ
る同相故障が発生したときを示す回路図であり、故障点
の距離は端子1からそれぞれxの地点と、yの地点であ
るとする。配電線の全長をd、端子1の電圧をV1、端
子2の電圧をV2 、端子1で回線1Lを流れる電流をI
11、端子1で回線2Lを流れる電流をI12、端子2で回
線1Lを流れる電流をI21、端子2 で回線2Lを流れる
電流をI22とする。線路の単位長さ当たりの自己インピ
ーダンスをZ s ,単位長さ当たりの回線間の相互インピ
ーダンスをZm とする。The operation of the present invention will be described. Fig. 1 is the same as a 2-terminal system
Line 2 lines Transmission and distribution lines at different points across both lines
Is a circuit diagram showing when a common mode failure occurs.
The distances from the terminal 1 are x and y respectively.
And The total length of the distribution line is d and the voltage of terminal 1 is V1,end
The voltage of child 2 is VTwo, The current flowing through the line 1L at the terminal 1 is I
11, The current flowing through line 2L at terminal 1 is I12, Terminal 2 times
The current flowing through the line 1L is Itwenty one, TerminalTwoFlows through line 2L
Current Itwenty twoAnd Self-impedance per unit length of track
-Dance Z s, Mutual impedance between lines per unit length
-Dance ZmAnd
【0012】前記の回路で、故障点の電位を0と近似す
る。この近似は、超高圧送配電線(27.5kV,50
0kVなど)では十分に成立する。キルヒホッフの法則
を適用すれば、 V1 −xZs I11−xZm I12=0 (9) V1 −yZs I12−xZm I11+(y−x)Zm I21=0 (10) V2 −(d−x)Zs I21−(d−y)Zm I22+(y−x)Zm I12=0 (11) V2 −(d−y)Zs I22−(d−y)Zm I21=0 (12) が成立する。前記(9) 式より、 x=V1 /(Zs I11+Zm I12) (13) 前記(10)式より、 y={V1 −x(Zm I11+Zm I21)}/(Zs I12+Zm I21) (14) が導かれる。In the above circuit, the potential at the fault point is approximated to zero. This approximation is based on ultra high voltage transmission and distribution lines (27.5 kV, 50
0 kV) is sufficient. Applying Kirchhoff's law, V 1 -xZ s I 11 -xZ m I 12 = 0 (9) V 1 -yZ s I 12 -xZ m I 11 + (y-x) Z m I 21 = 0 ( 10) V 2 − (d−x) Z s I 21 − (d−y) Z m I 22 + (y−x) Z m I 12 = 0 (11) V 2 − (d−y) Z s I 22 − (d−y) Z m I 21 = 0 (12) holds. From the equation (9), x = V 1 / (Z s I 11 + Z m I 12 ) (13) From the equation (10), y = {V 1 −x (Z m I 11 + Z m I 21 )} / (Z s I 12 + Z m I 21 ) (14) is derived.
【0013】また、(11)式から(12)式を引くと、 (d−y)Zs I22+(d−y)Zm I21−(d−x)Zs I21 −(d−y)Zm I22+(y−x)Zm I12=0 (15) が導かれる。Further, by subtracting the expression (12) from the expression (11), (d−y) Z s I 22 + (d−y) Z m I 21 − (d−x) Z s I 21 − (d -y) Z m I 22 + ( y-x) Z m I 12 = 0 (15) is derived.
【0014】ここで、本発明では、端子2の電流I21と
I22とは、端子2から故障距離x,yまでの距離に逆比
例して分流すると考える。すなわち、 I22=(d−x)I21/(d−y) (16) が成立すると考える。この仮定は、故障点から端子2ま
での間では、相互インピーダンスZm の影響を無視する
ことと同じである。In the present invention, it is considered that the currents I 21 and I 22 of the terminal 2 are shunted in inverse proportion to the distance from the terminal 2 to the failure distances x and y. That is, it is considered that I 22 = (d−x) I 21 / (d−y) (16) holds. This assumption is the same as ignoring the influence of the mutual impedance Z m from the fault point to the terminal 2.
【0015】故障相に係わる電線を流れる電流は、図2
に示すように、回線1Lでは互いに逆方向に流れて合計
0となり、回線2Lでも互いに逆方向に流れて合計0と
なるが、このような近似が成り立つには、回線1Lから
の回線2Lへの影響を無視できることが必要である。こ
のためには、図3(a) に示すように、1回線あたり3本
の線路、2回線で6本の線路を配設する鉄塔が、各線路
及び各相を対称に配置していることが必要である。図3
(b) に示すように、線路が対称に配置されていても各相
が対称に配置されていない場合は、この近似を適用する
ことはできない。The current flowing through the electric wire related to the failure phase is shown in FIG.
As shown in, the line 1L flows in the opposite directions to give a total of 0, and the line 2L also flows in the opposite directions to give a total of 0. However, in order to make such an approximation, the line 1L to the line 2L It is necessary to be able to ignore the impact. To do this, as shown in Fig. 3 (a), a steel tower with 3 lines per line and 6 lines with 2 lines should have each line and each phase symmetrically arranged. is required. FIG.
As shown in (b), if the lines are arranged symmetrically but the phases are not arranged symmetrically, this approximation cannot be applied.
【0016】前記(16)式を(15)式に代入して展開する
と、 (d−y)Zm I21−(d−x)Zm I21+(y−x)Zm I12=0 (17) よって、I12=I21となるから、これを(14)式に代入す
ると、 y={V1 −x(Zm I11−Zm I12)}/(Zs I12−Zm I12) (18) が得られる。この(18)式は、端子1での電流電圧情報の
みを含んでいるから、端子2での情報を使わずに、故障
点までの距離yを求めることができることを示してい
る。By substituting the equation (16) into the equation (15) and expanding it, (d−y) Z m I 21 − (d−x) Z m I 21 + (y−x) Z m I 12 = 0 (17) Therefore, I 12 = I 21 , so if this is substituted into the equation (14), y = {V 1 −x (Z m I 11 −Z m I 12 )} / (Z s I 12 -Z m I 12 ) (18) is obtained. Since the equation (18) includes only the current-voltage information at the terminal 1, it indicates that the distance y to the failure point can be obtained without using the information at the terminal 2.
【0017】[0017]
【実施例】以下、図面を参照しながら、本発明の並行2
回線送配電線おける故障点標定方法を詳細に説明する。
図4は、一般的な2端子並行2回線送配電線に、本発明
に係る故障点標定方法に適用される故障点算出装置2を
接続した図であり、送電端Aには、回線1Lのa相,b
相,c相の電流I1a,I1b,I1cを検出する変流器CT
1 と、回線2Lのa相,b相,c相の電流I2a,I2b,
I2cを検出する変流器CT2 と、母線のa相,b相,c
相の電圧V1a,V1b,V1c検出する計器用変圧器PTと
が備えられている。DETAILED DESCRIPTION OF THE PREFERRED EMBODIMENTS The parallel 2 of the present invention will now be described with reference to the drawings.
The fault location method for the line transmission / distribution line will be described in detail.
FIG. 4 is a diagram in which a fault point calculation device 2 applied to the fault point locating method according to the present invention is connected to a general 2-terminal parallel 2-line transmission / distribution line. Phase a, b
Current transformer CT for detecting currents I 1a , I 1b , and I 1c of phase I and phase C
1 and the currents I 2a , I 2b of the a-phase, b-phase, and c-phase of the line 2L,
Current transformer CT 2 for detecting I 2c and a-phase, b-phase, c of the busbar
An instrument transformer PT for detecting the phase voltages V 1a , V 1b and V 1c is provided.
【0018】故障点算出装置2は、変流器CT1 ,CT
2 により検出された各相の電流I1a,I1b,I1c,
I2a,I2b,I2cと、計器用変圧器PTにより検出され
た各相の電圧V1a,V1b,V1cを入力とし、これらを所
定のレベルの電圧信号に変換する入力部3と、所定の電
気角でサンプリングするサンプルホールド部4と、サン
プルホールド部4からの所定レベルの電圧信号をディジ
タルデータに変換するA/D変換部5と、A/D変換部
5により変換されたディジタルデータを格納するデータ
メモリ6と、送電端Aで検出した前記電流データ、電圧
データに基づいて、並行2回線に短絡故障が発生してい
るかどうかを検出する短絡故障検出部7と、該データメ
モリ6に格納されている回線1L,2Lの電流データ、
電圧データに基づいて送電端Aから故障点までの距離を
算出する故障点標定部8と、故障点標定部8により算出
された送電端Aから故障点までの距離等の情報を表示す
る表示部9とを備えている。The fault point calculation device 2 includes current transformers CT 1 and CT.
The currents I 1a , I 1b , I 1c of the respective phases detected by 2 ,
I 2a , I 2b , I 2c, and the input unit 3 which receives the voltages V 1a , V 1b , V 1c of the respective phases detected by the transformer PT for an instrument and converts them into voltage signals of a predetermined level. , A sample and hold unit 4 for sampling at a predetermined electrical angle, an A / D converter 5 for converting a voltage signal of a predetermined level from the sample and hold unit 4 into digital data, and a digital signal converted by the A / D converter 5. A data memory 6 that stores data, a short-circuit fault detection unit 7 that detects whether or not a short-circuit fault has occurred in two parallel lines based on the current data and voltage data detected at the power transmission end A, and the data memory Current data of lines 1L and 2L stored in 6,
A failure point locating unit 8 that calculates the distance from the power transmission end A to the failure point based on the voltage data, and a display unit that displays information such as the distance from the power transmission end A to the failure point calculated by the failure point locating unit 8. 9 and 9.
【0019】前記構成の故障点算出装置2の動作を、図
1の故障例に基づいて説明する。図1では、故障は両回
線の異地点で発生し、それらの地点は送電端Aからx及
びyの距離とする。変流器CT1 ,CT2 により検出さ
れた端子Aの回線1L,2Lの各相の電流、電圧は、入
力部3において、所定のレベルの電圧信号に変換され
る。該所定のレベルの電圧信号は、サンプルホールド部
4、A/D変換部5において、所定のサンプリング周期
でディジタルデータに変換され、短絡故障検出部7に取
込まれる。The operation of the fault point calculation device 2 having the above configuration will be described based on the fault example of FIG. In FIG. 1, the failure occurs at different points on both lines, and those points are distances x and y from the power transmission end A. The current and voltage of each phase of the lines 1L and 2L of the terminal A detected by the current transformers CT 1 and CT 2 are converted into a voltage signal of a predetermined level in the input section 3. The voltage signal of the predetermined level is converted into digital data by the sample hold unit 4 and the A / D conversion unit 5 at a predetermined sampling period, and taken into the short-circuit failure detection unit 7.
【0020】短絡故障検出部7は、各相電流I1a,
I1b,I1c,I2a,I2b,I2cの値を整定値と比較する
ことで短絡故障の発生を知り、故障相を検出する。そし
て、故障点標定部8は、故障が発生すると、データメモ
リ6に格納された、判定された故障相についての電流デ
ータ、電圧データを読み出し、下記演算式 x=V1 /(Zs I11+Zm I12) (19) y={V1 −x(Zm I11−Zm I12)}/(Zs I12−Zm I12) (20) を適用して、故障距離x,yを算出する。ここで、
V1 ,I11,I12は、故障相の電圧、電流データであ
り、故障相が例えばab相間短絡ならば、V1 はab相
間電圧Vb −Va 、I11は回線1Lのab相間差電流I
b −Ia 、I12は回線2Lのab相間差電流Ib −Ia
となる。具体的には、 x=(Vb −Va )/〔Zs (I1b−I1a)+Zm (I2b−I2a)〕 (21) y={(Vb −Va )−x〔Zm (I1b−I1a)−Zm (I2b−I2a)〕} /〔(Zs −Zm )(I2b−I2a)〕 (22) となる。The short-circuit failure detection unit 7 is configured to detect the phase currents I 1a ,
By comparing the values of I 1b , I 1c , I 2a , I 2b , and I 2c with the set values, it is possible to know the occurrence of a short-circuit fault and detect the fault phase. Then, when a failure occurs, the failure point locating unit 8 reads out the current data and voltage data stored in the data memory 6 for the determined failure phase, and the following arithmetic expression x = V 1 / (Z s I 11 + Z m I 12 ) (19) y = {V 1 −x (Z m I 11 −Z m I 12 )} / (Z s I 12 −Z m I 12 ) (20) to apply the failure distance x , Y is calculated. here,
V 1 , I 11 , and I 12 are voltage and current data of the fault phase. If the fault phase is, for example, an ab phase short circuit, V 1 is an ab phase voltage V b −V a , and I 11 is a line 1L between the ab phases. Difference current I
b -I a, I 12 ab phase between differential current of the line 2L I b -I a
Becomes Specifically, x = (V b -V a ) / [Z s (I 1b -I 1a) + Z m (I 2b -I 2a) ] (21) y = {(V b -V a) -x the [Z m (I 1b -I 1a) -Z m (I 2b -I 2a) ]} / [(Z s -Z m) (I 2b -I 2a) ] (22).
【0021】以上の(19)式と(20)式を用いて標定された
結果は、表示部9に表示されるので、管理者は故障の起
こった地点を知ることができる。次に、本実施例の式
((22)式参照)と、従来の近似的な方法、すなわち、前
記(6) 式で端子2の電流値I21を0とおいた式 y={(Vb −Va )−x(Zm (I1b−I1a)+Zm (I2b−I2a))} /Zs (I2b−I2a) (23) とを用いて、回線2Lの2相短絡故障距離yを算出し、
プロットた結果を図5に示す。Since the results of the above-mentioned orientations using the equations (19) and (20) are displayed on the display unit 9, the administrator can know the location of the failure. Next, the equation of this embodiment (see the equation (22)) and the conventional approximate method, that is, the equation (6) in which the current value I 21 of the terminal 2 is set to 0, y = {(V b -V a) -x (Z m ( I 1b -I 1a) + Z m (I 2b -I 2a))} / Z s (I 2b -I 2a) (23) and using a 2-phase circuits 2L Calculate the short circuit fault distance y,
The plotted result is shown in FIG.
【0022】このときの計算は、回線の全長を52k
m、回線1Lの故障距離xを5kmに固定し、回線2L
の故障点を10kmから50kmまで5kmごとに移動
させて行った。図5によれば、(23)式を用いて算出した
故障距離yは、真の故障距離よりも常に大き目に表れる
が、本発明の(20)式を用いて算出した故障距離yは、真
の故障距離に非常に近い値になっていることが分かる。
例えば、真の故障距離が50kmの点では、従来の方式
では57.5kmとなり、本発明の方式では49.3k
mとなっている。その誤差は、従来の方式では15%も
あるのに対して、本発明の方式では1.4%に抑えられ
ている。At this time, the total length of the line is 52k.
m, the failure distance x of the line 1L is fixed at 5 km, and the line 2L
The failure point was moved from 10 km to 50 km in steps of 5 km. According to FIG. 5, the failure distance y calculated using the equation (23) always appears larger than the true failure distance, but the failure distance y calculated using the equation (20) of the present invention is true. It can be seen that the value is very close to the failure distance of.
For example, when the true failure distance is 50 km, it is 57.5 km in the conventional method and 49.3 k in the method of the present invention.
m. The error is 15% in the conventional method, but is 1.4% in the method of the present invention.
【0023】[0023]
【発明の効果】以上のように本発明の故障点標定方法に
よれば、2端子系並行2回線送配電線の両回線にわたる
異地点に同相故障が発生した場合に、一端子で検出され
る電流電圧情報に基づいて、当該端子から短いほうの故
障点までの距離xを求めることができるのみならず、従
来正確に求めることができなかった当該端子から長いほ
うの故障点までの距離yも正確に求めることができる。As described above, according to the fault point locating method of the present invention, when a common mode fault occurs at different points across both lines of a two-terminal parallel two-line transmission / distribution line, it is detected by one terminal. Based on the current / voltage information, not only the distance x from the relevant terminal to the shorter failure point can be obtained, but also the distance y from the relevant terminal to the longer failure point, which could not be accurately determined in the past. Can be accurately determined.
【図1】2端子系並行2回線送配電線で、両回線にまた
がった異地点における同相故障が発生したときの解析方
法を解説するための回路図である。FIG. 1 is a circuit diagram for explaining an analysis method when a common mode failure occurs at different points across both lines in a two-terminal parallel two-line transmission / distribution line.
【図2】端子2で、故障相に係わる電線を流れる電流の
方向を示す図である。FIG. 2 is a diagram showing a direction of a current flowing through an electric wire related to a failure phase at a terminal 2.
【図3】鉄塔における線路の断面配置例を示す図であ
り、図3(a) は各相を対称に配置していることを示す
図、図3(b) は各相を非対称に配置していることを示す
図である。FIG. 3 is a diagram showing a cross-sectional layout example of a line in a tower, FIG. 3 (a) shows that each phase is symmetrically arranged, and FIG. 3 (b) shows that each phase is asymmetrically arranged. FIG.
【図4】一般的な2端子並行2回線送配電線に、本発明
に係る故障点標定方法に適用される故障点算出装置2を
接続した回路構成を示す図である。FIG. 4 is a diagram showing a circuit configuration in which a fault point calculation device 2 applied to a fault point locating method according to the present invention is connected to a general 2-terminal parallel 2-line transmission / distribution line.
【図5】異地点2相短絡故障をシミュレーションし、本
発明の方法と、従来の近似的な方法とを用いて故障距離
yをそれぞれ求めた結果を示すグラフである。FIG. 5 is a graph showing a result of simulating a two-phase short-circuit fault at different points and determining a fault distance y using the method of the present invention and the conventional approximate method.
1L,2L 並行2回線送配電線 2 故障点算出装置 3 入力部 4 サンプルホールド部 5 A/D変換部 6 データメモリ 7 短絡故障検出部 8 故障点標定部 CT1 ,CT2 変流器 PT 計器用変圧器1L, 2L Parallel 2 lines Transmission / Distribution line 2 Fault point calculation device 3 Input section 4 Sample hold section 5 A / D conversion section 6 Data memory 7 Short circuit fault detection section 8 Fault point location section CT 1 , CT 2 Current transformer PT Meter Transformer
Claims (2)
出される電流電圧情報に基づいて、両回線にわたる異地
点に発生する同相故障点の標定を行う方法であって、 回線1L,2Lからなる並行2回線送配電線の一端子に
おける電流値、電圧値として、故障に係わる相の電流値
I11,I12、電圧値V1 を取得し、 これらの取得された電流値I11,I12、電圧値V1 にも
とづいて、下記演算式を用いて、当該端子から短いほう
の故障点までの距離x、及び当該端子から長いほうの故
障点までの距離yを求めることを特徴とする並行2回線
送配電線の故障点標定方法。 x=V1 /(Zs I11+Zm I12) y={V1 −xZm (I11−I12)}/(Zs −Zm )
I12 (ただし、Zs は線路の単位長さ当たりの自己インピー
ダンス、Zm は単位長さ当たりの回線間の相互インピー
ダンスである。)1. A method for locating a common-mode fault point occurring at different points across both lines based on current-voltage information detected at one terminal of a two-terminal parallel two-line transmission / distribution line, which is a line 1L. , 2L, current values and voltage values at one terminal of the parallel two-line transmission / distribution line, current values I 11 , I 12 and voltage value V 1 of the phase related to the failure are acquired, and these acquired current values I are acquired. Based on 11 and I 12 and the voltage value V 1 , the distance x from the relevant terminal to the shorter failure point and the distance y from the relevant terminal to the longer failure point are calculated using the following arithmetic expressions. A method for locating failure points of parallel 2-line transmission / distribution lines. x = V 1 / (Z s I 11 + Z m I 12) y = {V 1 -xZ m (I 11 -I 12)} / (Z s -Z m)
I 12 (where Z s is the self-impedance per unit length of line, and Z m is the mutual impedance between lines per unit length.)
が回線相互に対称となっていることを特徴とする請求項
1記載の並行2回線送配電線の故障点標定方法。2. The fault locating method for a parallel 2-line transmission / distribution line according to claim 1, wherein the lines of the 2-terminal parallel 2-line transmission / distribution line are symmetrical to each other.
Priority Applications (1)
Application Number | Priority Date | Filing Date | Title |
---|---|---|---|
JP16050995A JP3503274B2 (en) | 1995-06-27 | 1995-06-27 | Fault location method for two parallel transmission and distribution lines |
Applications Claiming Priority (1)
Application Number | Priority Date | Filing Date | Title |
---|---|---|---|
JP16050995A JP3503274B2 (en) | 1995-06-27 | 1995-06-27 | Fault location method for two parallel transmission and distribution lines |
Publications (2)
Publication Number | Publication Date |
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JPH0915291A true JPH0915291A (en) | 1997-01-17 |
JP3503274B2 JP3503274B2 (en) | 2004-03-02 |
Family
ID=15716495
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JP16050995A Expired - Fee Related JP3503274B2 (en) | 1995-06-27 | 1995-06-27 | Fault location method for two parallel transmission and distribution lines |
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JP (1) | JP3503274B2 (en) |
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1995
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