WO2021213272A1 - Control method for single-system refrigerator - Google Patents

Control method for single-system refrigerator Download PDF

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Publication number
WO2021213272A1
WO2021213272A1 PCT/CN2021/087777 CN2021087777W WO2021213272A1 WO 2021213272 A1 WO2021213272 A1 WO 2021213272A1 CN 2021087777 W CN2021087777 W CN 2021087777W WO 2021213272 A1 WO2021213272 A1 WO 2021213272A1
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Prior art keywords
refrigerator
yes
ambient temperature
control method
frequency
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PCT/CN2021/087777
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French (fr)
Chinese (zh)
Inventor
许艳青
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青岛海尔电冰箱有限公司
海尔智家股份有限公司
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Publication of WO2021213272A1 publication Critical patent/WO2021213272A1/en

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    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D29/00—Arrangement or mounting of control or safety devices
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D11/00—Self-contained movable devices, e.g. domestic refrigerators
    • F25D11/02—Self-contained movable devices, e.g. domestic refrigerators with cooling compartments at different temperatures
    • F—MECHANICAL ENGINEERING; LIGHTING; HEATING; WEAPONS; BLASTING
    • F25—REFRIGERATION OR COOLING; COMBINED HEATING AND REFRIGERATION SYSTEMS; HEAT PUMP SYSTEMS; MANUFACTURE OR STORAGE OF ICE; LIQUEFACTION SOLIDIFICATION OF GASES
    • F25D—REFRIGERATORS; COLD ROOMS; ICE-BOXES; COOLING OR FREEZING APPARATUS NOT OTHERWISE PROVIDED FOR
    • F25D2600/00—Control issues
    • F25D2600/02—Timing

Definitions

  • the invention relates to refrigerator refrigeration technology, in particular to a control method of a single-system refrigerator.
  • the single-system refrigerator provides cold capacity to the refrigerator compartment and freezer compartment at the same time through a set of refrigeration system.
  • the compressor in the refrigeration system is usually controlled by the temperature of the refrigerating compartment.
  • the temperature of the refrigerator is low, for example, the room temperature in winter is very low and sometimes close to 0 degrees Celsius, in order to avoid being caused by too low room temperature.
  • the refrigerating room temperature is too low to reach the starting point temperature, causing the temperature of the freezer compartment to be too high and causing food deterioration.
  • heating wires are added to the refrigerating room, and the refrigerating room is heated by the heating wire to increase the temperature of the refrigerating room. The temperature at the start-up point is reached.
  • this control method has the following drawbacks: 1.
  • the use of heating wires increases costs, 2 the heating wires may cause fires and increase safety hazards; 3.
  • the heating wires are heated, which increase electrical loss.
  • the present invention aims to solve at least one of the technical problems existing in the prior art, thereby providing a control method of a single-system refrigerator.
  • a control method of a single-system refrigerator characterized in that it comprises the following steps:
  • S1 obtains the ambient temperature Tc of the environment where the refrigerator is located, and obtains the operating time of the refrigerator;
  • S2 controls the working state of the refrigeration system according to the ambient temperature and operating time.
  • step S2 includes the following steps: S21 judges whether the ambient temperature is greater than or equal to T1; if yes, then proceeds to step S22 after turning on; if not, then proceeds to step S23 after turning on; S22 judges whether the single operating time of the refrigerator is greater than or equal to a1*(Kl* Tc/b), if yes, stop; if otherwise, continue to run step S22; S23 judge whether the single running time of the refrigerator is ⁇ a2*(Kl*Tc/b), if yes, stop; if otherwise, continue to run step S23; where, a1, a2, and b are proportional coefficients, and a1>a2, Kl is the refrigerator volume, and Tc is the ambient temperature.
  • step S2 also includes: step S22' after step S22: judging whether the single shutdown time of the refrigerator is ⁇ c1*(Kl*Tc/b); if yes, return to step S1; if not, continue to run step S22'; Step S23' after step S23: judge whether the refrigerator single stop time ⁇ c2*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S23'; where c1 and c2 are coefficients , And c1 ⁇ c2; Kl is the volume of the refrigerator, and Tc is the ambient temperature.
  • step S2 includes the following steps: S24 judges whether the ambient temperature is greater than or equal to T2, and T2 is greater than T1; if yes, proceed to step S25 after turning on the machine; if not, proceed to step S21; S25 judge whether the single operation time of the refrigerator is greater than or equal to a3*( Kl*Tc/b), if yes, stop; if otherwise, continue to run step S25; wherein, a3 is the proportional coefficient, and a3>a1, Kl is the refrigerator volume, and Tc is the ambient temperature.
  • step S2 also includes: step S22' after step S22: judging whether the single shutdown time of the refrigerator is ⁇ c1*(Kl*Tc/b); if yes, return to step S1; if not, continue to run step S22'; Step S23' after step S23: Determine whether the single downtime of the refrigerator is ⁇ c2*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S23'; S25' after step S25, Judge whether the single shutdown time of the refrigerator is ⁇ c3*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S25'; where c1, c2, and c3 are all coefficients, and c3 ⁇ c1 ⁇ c2 ; Kl is the volume of the refrigerator, and Tc is the ambient temperature.
  • T1 is between 1°C and 3°C
  • T2 is between 8°C and 12°C.
  • step S2 includes the following steps: S2a judges whether the ambient temperature is greater than or equal to Ta, if yes, then proceeds to step S2b; if not, then proceeds to step S2c; S2b judges whether the total operating time of the refrigerator is greater than or equal to x1*(Kl*Tc/y), If yes, go to step S2d; if otherwise, the compressor runs at H1 frequency; S2c judges whether the total running time of the refrigerator ⁇ x2*(Kl*Tc/y), if yes, go to step S2e; if otherwise, the compressor runs at H2 frequency; S2d judges whether the total running time of the refrigerator is ⁇ x3*(Kl*Tc/y), if yes, the compressor runs at H3 frequency; if not, the compressor runs at H4 frequency; S2e judges whether the total running time of the refrigerator is ⁇ x4*( Kl*Tc/y), if yes, the compressor runs at H5 frequency; if not, then the compressor runs at H
  • step S2 also includes the following steps: during compressor operation, it is judged whether the single operation time of the refrigerator is greater than (Kl*Tc/y), if yes, return to step S1, if otherwise, the compressor continues to run at the current frequency.
  • step S2 also includes the following steps: S2f judges whether the ambient temperature is greater than or equal to Tb, and Tb is greater than Ta; if yes, proceed to step S2g; if not, proceed to step S2a; S2g judges whether the total operating time of the refrigerator is greater than or equal to x5*(Kl* Tc/y), if yes, go to step S2h; if otherwise, the compressor runs at H7 frequency; S2h judges whether the total running time of the refrigerator is ⁇ x6*(Kl*Tc/y), if yes, the compressor runs at H8 frequency; if No, the compressor runs at H9 frequency; where x5, x6 and y are all proportional coefficients, and x6>x5, x5>x1, x6>x3, Kl is the refrigerator volume, Tc is the ambient temperature, H8 ⁇ H9 ⁇ H7 , H8>H3, H9>H4, H7>H1.
  • Ta is between 1°C and 3°C
  • Tb is between 8°C and 12°C.
  • the beneficial effects of the present invention are: in the refrigerator control method of the present invention, the working state of the refrigeration system is no longer controlled by the refrigeration temperature, and there is no need to increase the refrigeration heating wire, but will be automatically controlled according to the ambient temperature and operating time,
  • the control method of the refrigerator can not only effectively refrigerate, but also realize energy saving and cost reduction, and reduce potential safety hazards.
  • Fig. 1 is a flowchart of a control method of a refrigerator in a preferred embodiment of the present invention
  • FIG. 2 is a flowchart of a control method of a refrigerator according to a specific embodiment of the present invention
  • Fig. 3 is a flow chart of a refrigerator control method according to another preferred embodiment of the present invention.
  • Fig. 4 is a flowchart of a refrigerator control method according to another preferred embodiment of the present invention.
  • FIG. 5 is a flowchart of a refrigerator control method according to another preferred embodiment of the present invention.
  • Fig. 6 is a flowchart of a refrigerator control method according to another preferred embodiment of the present invention.
  • FIGS 1 to 6 are a preferred embodiment of the refrigerator control method of the present invention, including the following steps: S1 obtains the ambient temperature Tc of the environment in which the refrigerator is located, and obtains the operating time of the refrigerator; S2 Time controls the working status of the refrigeration system.
  • S1 obtains the ambient temperature Tc of the environment in which the refrigerator is located, and obtains the operating time of the refrigerator; S2 Time controls the working status of the refrigeration system.
  • the start and stop of the refrigeration system is no longer controlled by the refrigeration temperature, and there is no need to add refrigeration heating wires, but will be automatically controlled according to the ambient temperature and running time.
  • This refrigerator control method can not only effectively refrigerate, but also It can also achieve energy saving and cost reduction, and reduce safety hazards.
  • the size of the ambient temperature Tc determines the heat exchange rate of the refrigerator, and the refrigerator heat exchange rate determines the food temperature cooling rate d/dt. That is to say, the greater the ambient temperature Tc, the slower the refrigerator heat exchange rate, but the lower the food temperature cooling rate d/dt.
  • the refrigerator volume Kl and the ambient temperature Tc are in a logical “AND” relationship, and the change of any one of them can affect the control method of the AC compressor and the DC compressor. Therefore, in step S2, based on the volume K1 of the refrigerator, the operation of the compressor is controlled by detecting the ambient temperature and the operation time of the refrigerator.
  • step S2 includes the following steps:
  • step S21 judges whether the ambient temperature is greater than or equal to T1, if yes, then proceed to step S22 after booting; if not, then proceed to step S23 after booting; those skilled in the art can understand that the “boot” mentioned here and later in this article refers to Start the compressor.
  • This method comprehensively considers the overall heat load of the refrigerator through the volume and ambient temperature of the refrigerator.
  • the operating time of the refrigerator is based on a*(Kl*Tc/b), which can more accurately and reasonably control the temperature of the refrigerator;
  • the coefficient a is represented by a1, a2...an, and n is a natural number greater than 1.
  • step S2 also includes: step S22' after step S22: judging whether the single shutdown time of the refrigerator is ⁇ c1*(Kl*Tc/b); if yes, return to step S1; if not, continue to run step S22'; Step S23' after step S23: judge whether the refrigerator single stop time ⁇ c2*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S23'; where c1 and c2 are coefficients , And c2>c1; Kl is the volume of the refrigerator, and Tc is the ambient temperature.
  • This method comprehensively considers the overall heat load of the refrigerator through the volume and ambient temperature of the refrigerator, and the shutdown time of the refrigerator is based on c*(Kl*Tc/b), which can more accurately and reasonably control the temperature of the refrigerator.
  • the coefficient c is represented by c1, c2...cn, and n is a natural number greater than 1.
  • step S2 also includes: S24 judging whether the ambient temperature is greater than or equal to T2, and T2 is greater than T1; if yes, turn on the machine and proceed to step S25; if not, proceed to step S21; S25 judge whether the single operation time of the refrigerator is greater than or equal to a3*(Kl *Tc/b), if yes, stop; if not, continue to run step S25; where a3 is a proportional coefficient, and a3>a1, Kl is the refrigerator volume, and Tc is the ambient temperature.
  • step S2 also includes: S25' located after step S25, judging whether the single downtime of the refrigerator is ⁇ c3*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S25'; where , C1, c2 and c3 are all coefficients, and c3 ⁇ c1 ⁇ c2; Kl is the volume of the refrigerator, and Tc is the ambient temperature.
  • the present invention divides the environment where the refrigerator is located into a plurality of temperature ranges, and sets corresponding coefficients according to different environmental temperatures.
  • T1 is between 1°C and 3°C
  • T2 is between 8°C and 12°C; the operation of the refrigerator can still be effectively controlled at low temperatures without relying on heating wires.
  • the specific reference is as follows:
  • Tc ⁇ 20°C and a is between 1.0 ⁇ 1.2, when the single operation time of the refrigerator is less than A*(Kl*Tc/100), the refrigerator cannot quickly achieve the cooling effect; when the single operation time of the refrigerator is greater than 1.2A *(Kl*Tc/100), the refrigerator has poor energy saving effect.
  • c is between 0.3 and 0.4. When the single downtime of the refrigerator is less than 0.3A*(Kl*Tc/100), the energy saving effect of the refrigerator is poor; when the single downtime of the refrigerator is greater than 0.4A*(Kl*Tc/b) The refrigerator cannot quickly achieve the cooling effect.
  • a is between 0.7 ⁇ 0.9, when the single operation time of the refrigerator is less than 0.7*(Kl*Tc/100), the refrigerator cannot quickly achieve the cooling effect; when the single operation time of the refrigerator is greater than 0.9 *(Kl*Tc/100), the refrigerator has poor energy saving effect.
  • c is between 0.5 and 0.7. When the single downtime of the refrigerator is less than 0.5 (Kl*Tc/100), the refrigerator has a poor energy saving effect; when the single downtime of the refrigerator is greater than 0.7 (Kl*Tc/100), the refrigerator cannot quickly reach Refrigeration effect.
  • a is between 0.2 ⁇ 0.4.
  • the refrigerator cannot quickly achieve the cooling effect; when the single operation time of the refrigerator is greater than 0.4(Kl* At Tc/100), the refrigerator has poor energy-saving effect.
  • c is between 4 and 6.
  • the single downtime of the refrigerator is less than 4Kl*Tc, the refrigerator wastes electricity; when the single downtime of the refrigerator is greater than 6 (Kl*Tc/100), the refrigerator cannot quickly achieve the cooling effect.
  • T1 is 3°C and T2 is 10°C.
  • T2 is 10°C.
  • the operation of the refrigerator can still be effectively controlled at low temperatures without relying on heating wires.
  • step S2 also includes: S26 judges whether the ambient temperature is ⁇ 20°C; if yes, turn on the machine and go to step S27; if not, go to step S24; S27 judge whether the single operation time of the refrigerator is ⁇ (Kl *Tc/b), if yes, stop; if otherwise, continue to run step S27.
  • step S2 also includes: S27' after step S27, judging whether the single shutdown time of the refrigerator is ⁇ 0.3*(Kl*Tc/b); if yes, return to step S1; if not, continue to run step S27'.
  • the start and stop of the refrigeration system can be controlled based on the volume of the refrigerator and the ambient temperature and the running time of the refrigerator, without setting a temperature sensor in the refrigerating compartment.
  • the lower the ambient temperature the shorter the single running time of the refrigerator, the longer the downtime, and the better the energy-saving effect.
  • step S2 includes the following steps: S2a determines whether the ambient temperature is greater than or equal to Ta, if yes, then proceeds to step S2b; if not, then proceeds to step S2c; S2b Judge whether the total running time of the refrigerator is ⁇ x1*(Kl*Tc/y), if yes, go to step S2d; if otherwise, the compressor runs at H1 frequency; S2c judges whether the total running time of the refrigerator is ⁇ x2*(Kl*Tc/y) If yes, go to step S2e; if otherwise, the compressor runs at H2 frequency; S2d judges whether the total running time of the refrigerator is ⁇ x3*(Kl*Tc/y), if yes, then the compressor runs at H3 frequency; if not, then compress The machine runs at H4 frequency; S2e judges whether the total running time of the refrigerator is ⁇ x4*(Kl*Tc/y), if yes, the
  • the operating frequency and operating time of the compressor are used to control the operating frequency of the compressor, and there is no need to set a low-temperature supplementary heating wire. Moreover, at the same temperature, as the total operating time of the compressor is extended, the operating frequency H of the compressor is reduced step by step, which can effectively prevent the refrigeration compartment from being suddenly overcooled, and the control is more precise.
  • step S2 also includes the following steps: during compressor operation, it is judged whether the single operation time of the refrigerator is greater than (Kl*Tc/y), if yes, then return to step S1, if otherwise, the compressor continues to run at the current frequency; To the effect of energy saving and precise temperature control.
  • step S2 includes the following steps: S2f judges whether the ambient temperature is greater than or equal to Tb, and Tb is greater than Ta; if yes, proceed to step S2g; if not, proceed to step S2a; S2g judges whether the total running time of the refrigerator is greater than or equal to x5*(Kl*Tc /y), if yes, go to step S2h; if otherwise, the compressor runs at H7 frequency; S2h judges whether the total running time of the refrigerator is ⁇ x6*(Kl*Tc/y), if yes, then the compressor runs at H8 frequency; if not , The compressor runs at H9 frequency; among them, x5, x6 and y are proportional coefficients, and x6>x5, x5>x1, x6>x3, Kl is the refrigerator volume, Tc is the ambient temperature, H8 ⁇ H9 ⁇ H7, H8>H3, H9>H4, H7>H1.
  • the values of x1 ⁇ x6 and H1 ⁇ H9 are related to the volume of the refrigerator and the ambient temperature. With a certain volume of the refrigerator, the lower the ambient temperature, the shorter the total running time of the refrigerator and the lower the compressor operating frequency, which has a better energy-saving effect.
  • the present invention divides the environment where the refrigerator is located into a plurality of temperature ranges, and sets corresponding coefficients according to different environmental temperatures.
  • T1 is between 1°C and 3°C
  • T2 is between 8°C and 12°C; the operation of the refrigerator can still be effectively controlled at low temperatures without relying on heating wires.
  • the specific reference is as follows:
  • x in the total running time 1 of the refrigerator is between 1.0 and 1.2.
  • the x in the total operating time of the refrigerator 2 is between 2 and 3.
  • the total operating time of the refrigerator 2 is less than 2 (Kl*Tc/10)
  • the refrigerator cannot quickly achieve the cooling effect; when the total operating time of the refrigerator 2 is greater than 3 ( Kl*Tc/10), the refrigerator has poor energy-saving effect.
  • the x in the total running time 1 of the refrigerator is between 0.8 and 0.9.
  • the refrigerator cannot quickly achieve the cooling effect;
  • the total running time 1 of the refrigerator is greater than 0.9 (Kl*Tc/10)
  • the energy saving effect of the refrigerator is poor.
  • the x in the total running time 2 of the refrigerator is between 1.6 and 1.8.
  • the total running time 2 of the refrigerator is less than 1.6 (Kl*Tc/10)
  • the refrigerator cannot quickly achieve the cooling effect; when the total running time 2 of the refrigerator is greater than 1.8 ( Kl*Tc/10), the refrigerator has poor energy-saving effect.
  • the coefficient x of the refrigerator's total operating time 1 is between 0.6 and 0.7.
  • the refrigerator's total operating time 1 is less than 0.6 (Kl*Tc/10)
  • the refrigerator cannot quickly achieve the cooling effect ;
  • the total running time 1 of the refrigerator is greater than 0.7 (Kl*Tc/10)
  • the energy saving effect of the refrigerator is poor.
  • the coefficient x of the total running time 2 of the refrigerator is between 1.2 and 1.4; when the total running time 2 of the refrigerator is less than 1.2 (Kl*Tc/10), the refrigerator cannot quickly achieve the cooling effect; when the total running time 2 of the refrigerator is greater than 1.4 ( Kl*Tc/10), the refrigerator has poor energy-saving effect.
  • the coefficient x of the refrigerator's total operating time 1 is between 0.4 and 0.5.
  • the refrigerator's total operating time 1 is less than 0.4 (Kl*Tc/10)
  • the refrigerator cannot quickly achieve the cooling effect;
  • the total running time 1 is greater than 0.5 (Kl*Tc/10)
  • the refrigerator has a poor energy-saving effect.
  • the coefficient x of the total running time 2 of the refrigerator is between 1.0 and 1.1.
  • the total running time 2 of the refrigerator is less than (Kl*Tc/10)
  • the refrigerator cannot quickly achieve the cooling effect; when the total running time 2 of the refrigerator is greater than 1.1 (Kl *Tc/10), the refrigerator has a poor energy-saving effect.
  • Ta is between 1°C and 3°C
  • Tb is between 8°C and 12°C. Refer to Figure 5 for other parameters. It can still be effective at low temperatures without relying on the heating wire. To control the operation of the refrigerator.
  • step S2 further includes the following steps: S2i judges whether the ambient temperature is ⁇ 20°C, if yes, then proceeds to step S2j; if not, then proceeds to step S2f; S2j judges whether the total running time of the refrigerator is ⁇ (Kl *Tc/10)min, if yes, go to step S2k; if otherwise, the compressor runs at 100Hz; S2k judges whether the total running time of the refrigerator is ⁇ 2(Kl*Tc/10)min, if yes, the compressor runs at 60Hz ; If not, the compressor runs at 80Hz.
  • the operating frequency of the compressor can be controlled based on the volume of the refrigerator under the usable ambient temperature of the refrigerator, and the operating frequency of the compressor can be controlled through the ambient temperature and the operating time of the refrigerator, without setting a temperature sensor in the refrigerator compartment. Moreover, the lower the ambient temperature, the lower the operating frequency of the refrigerator, the shorter the operating time, and the better the energy-saving effect.
  • the working state of the refrigeration system is no longer controlled by the refrigeration temperature, and there is no need to increase the refrigeration heating wire, but will automatically control according to the ambient temperature and operating time.
  • the control method can not only effectively refrigerate, but also achieve energy saving and cost reduction, and reduce safety hazards.

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Abstract

Provided is a control method for a single-system refrigerator, the method comprising the following steps: S1, acquiring an environment temperature Tc of the environment where a refrigerator is located, and acquiring the running time of the refrigerator; and S2, controlling an operating state of a refrigerating system according to the environment temperature and the running time. An operating state of a refrigerating system can be automatically controlled according to an environment temperature and a running time, such that effective refrigeration can be realized, energy conservation and cost reduction can also be realized, and potential safety hazards are reduced.

Description

单***冰箱的控制方法Control method of single-system refrigerator 技术领域Technical field
本发明涉及冰箱制冷技术，尤其涉及一种单***冰箱的控制方法。The invention relates to refrigerator refrigeration technology, in particular to a control method of a single-system refrigerator.
背景技术Background technique
单***冰箱通过一套制冷***同时给冷藏室和冷冻室提供冷量。目前单***冰箱中，制冷***中压缩机的开停通常受冷藏室温度的控制，当冰箱所处环境温度较低，例如冬天室温很低有时候会接近0摄氏度，为了避免因室温过低引起的冷藏室温度过低而达不到开机点温度，造成冷冻室的温度过高引起食物变质的问题，一般都会在冷藏室增加加热丝，通过加热丝对冷藏室进行加热从而提高冷藏室温度以达到开机点温度。但是，此种控制方法有以下几点弊端：1.采用加热丝增加成本，2加热丝可能引起火灾，增加安全隐患；3.加热丝加热，增加电损耗。The single-system refrigerator provides cold capacity to the refrigerator compartment and freezer compartment at the same time through a set of refrigeration system. In the current single-system refrigerator, the compressor in the refrigeration system is usually controlled by the temperature of the refrigerating compartment. When the temperature of the refrigerator is low, for example, the room temperature in winter is very low and sometimes close to 0 degrees Celsius, in order to avoid being caused by too low room temperature. The refrigerating room temperature is too low to reach the starting point temperature, causing the temperature of the freezer compartment to be too high and causing food deterioration. Generally, heating wires are added to the refrigerating room, and the refrigerating room is heated by the heating wire to increase the temperature of the refrigerating room. The temperature at the start-up point is reached. However, this control method has the following drawbacks: 1. The use of heating wires increases costs, 2 the heating wires may cause fires and increase safety hazards; 3. The heating wires are heated, which increase electrical loss.
有鉴于此，有必要提供一种新的单***冰箱的控制方法，以解决上述问题。In view of this, it is necessary to provide a new single-system refrigerator control method to solve the above-mentioned problems.
发明内容Summary of the invention
本发明旨在至少解决现有技术存在的技术问题之一，从而提供一种单***冰箱的控制方法。The present invention aims to solve at least one of the technical problems existing in the prior art, thereby providing a control method of a single-system refrigerator.
为实现上述发明目的之一，本发明采用如下技术方案：In order to achieve one of the above-mentioned purposes of the invention, the present invention adopts the following technical solutions:
一种单***冰箱的控制方法，其特征在于，包括如下步骤：A control method of a single-system refrigerator, characterized in that it comprises the following steps:
S1获取冰箱所处环境的环境温度Tc，获取冰箱的运行时间；S1 obtains the ambient temperature Tc of the environment where the refrigerator is located, and obtains the operating time of the refrigerator;
S2根据环境温度和运行时间控制制冷***的工作状态。S2 controls the working state of the refrigeration system according to the ambient temperature and operating time.
进一步地，步骤S2包括如下步骤：S21判断环境温度是否≥T1，若是，则开机后进入步骤S22；若否，则开机后进入步骤S23；S22判断冰箱单次运行时间是否≥a1*(Kl*Tc/b)，若是，则停机；若否则继续运行步骤S22；S23判断冰箱单次运行时间是否≥a2*(Kl*Tc/b)，若是，则停机；若否则继续运行步骤S23；其中，a1、a2和b为比例系数，且a1＞a2，Kl为冰箱容积，Tc为环境温度。Further, step S2 includes the following steps: S21 judges whether the ambient temperature is greater than or equal to T1; if yes, then proceeds to step S22 after turning on; if not, then proceeds to step S23 after turning on; S22 judges whether the single operating time of the refrigerator is greater than or equal to a1*(Kl* Tc/b), if yes, stop; if otherwise, continue to run step S22; S23 judge whether the single running time of the refrigerator is ≥a2*(Kl*Tc/b), if yes, stop; if otherwise, continue to run step S23; where, a1, a2, and b are proportional coefficients, and a1>a2, Kl is the refrigerator volume, and Tc is the ambient temperature.
进一步地，步骤S2还包括：位于步骤S22之后的步骤S22’：判断冰箱单次停机时间是否≥c1*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S22’；位于步骤S23之后的步骤S23’：判断冰箱单次停机时间是否≥c2*(Kl*Tc/b)；若是，则返回步骤S1；若否则继 续运行步骤S23’；其中，c1和c2均为系数，且c1＜c2；Kl为冰箱容积，Tc为环境温度。Further, step S2 also includes: step S22' after step S22: judging whether the single shutdown time of the refrigerator is ≥ c1*(Kl*Tc/b); if yes, return to step S1; if not, continue to run step S22'; Step S23' after step S23: judge whether the refrigerator single stop time ≥ c2*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S23'; where c1 and c2 are coefficients , And c1<c2; Kl is the volume of the refrigerator, and Tc is the ambient temperature.
进一步地，步骤S2包括如下步骤：S24判断环境温度是否≥T2，T2大于T1；若是，则开机后进入步骤S25；若否，则进入步骤S21；S25判断冰箱单次运行时间是否≥a3*(Kl*Tc/b)，若是，则停机；若否则继续运行步骤S25；其中，a3为比例系数，且a3＞a1，Kl为冰箱容积，Tc为环境温度。Further, step S2 includes the following steps: S24 judges whether the ambient temperature is greater than or equal to T2, and T2 is greater than T1; if yes, proceed to step S25 after turning on the machine; if not, proceed to step S21; S25 judge whether the single operation time of the refrigerator is greater than or equal to a3*( Kl*Tc/b), if yes, stop; if otherwise, continue to run step S25; wherein, a3 is the proportional coefficient, and a3>a1, Kl is the refrigerator volume, and Tc is the ambient temperature.
进一步地，步骤S2还包括：位于步骤S22之后的步骤S22’：判断冰箱单次停机时间是否≥c1*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S22’；位于步骤S23之后的步骤S23’：判断冰箱单次停机时间是否≥c2*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S23’；位于步骤S25之后的S25’,判断冰箱单次停机时间是否≥c3*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S25’；其中，c1、c2和c3均为系数，且c3＜c1＜c2；Kl为冰箱容积，Tc为环境温度。Further, step S2 also includes: step S22' after step S22: judging whether the single shutdown time of the refrigerator is ≥ c1*(Kl*Tc/b); if yes, return to step S1; if not, continue to run step S22'; Step S23' after step S23: Determine whether the single downtime of the refrigerator is ≥c2*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S23'; S25' after step S25, Judge whether the single shutdown time of the refrigerator is ≥c3*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S25'; where c1, c2, and c3 are all coefficients, and c3<c1<c2 ; Kl is the volume of the refrigerator, and Tc is the ambient temperature.
进一步地，T1介于1℃～3℃，T2介于8℃～12℃。Further, T1 is between 1°C and 3°C, and T2 is between 8°C and 12°C.
进一步地，步骤S2包括如下步骤：S2a判断环境温度是否≥Ta，若是，则进入步骤S2b；若否，则进入步骤S2c；S2b判断冰箱总运行时间是否≥x1*(Kl*Tc/y)，若是，则进入步骤S2d；若否则压缩机以H1频率运行；S2c判断冰箱总运行时间是否≥x2*(Kl*Tc/y)，若是，则进入步骤S2e；若否则压缩机以H2频率运行；S2d判断冰箱总运行时间是否≥x3*(Kl*Tc/y)，若是，则压缩机以H3频率运行；若否，则压缩机以H4频率运行；S2e判断冰箱总运行时间是否≥x4*(Kl*Tc/y)，若是，则压缩机以H5频率运行；若否，则压缩机以H6频率运行；其中，x1、x2、x3、x4和y均为比例系数，且x1＞x2，x3＞x4，x3＞x1，x4＞x2，Kl为冰箱容积，Tc为环境温度，H1＞H2，H3＞H5，H4＞H6，H1＞H4＞H3，H2＞H6＞H5。Further, step S2 includes the following steps: S2a judges whether the ambient temperature is greater than or equal to Ta, if yes, then proceeds to step S2b; if not, then proceeds to step S2c; S2b judges whether the total operating time of the refrigerator is greater than or equal to x1*(Kl*Tc/y), If yes, go to step S2d; if otherwise, the compressor runs at H1 frequency; S2c judges whether the total running time of the refrigerator ≥ x2*(Kl*Tc/y), if yes, go to step S2e; if otherwise, the compressor runs at H2 frequency; S2d judges whether the total running time of the refrigerator is ≥ x3*(Kl*Tc/y), if yes, the compressor runs at H3 frequency; if not, the compressor runs at H4 frequency; S2e judges whether the total running time of the refrigerator is ≥ x4*( Kl*Tc/y), if yes, the compressor runs at H5 frequency; if not, then the compressor runs at H6 frequency; where x1, x2, x3, x4 and y are all proportional coefficients, and x1>x2, x3 >x4, x3>x1, x4>x2, Kl is the refrigerator volume, Tc is the ambient temperature, H1>H2, H3>H5, H4>H6, H1>H4>H3, H2>H6>H5.
进一步地，步骤S2还包括如下步骤：压缩机运行过程中，判断冰箱单次运行时间是否大于(Kl*Tc/y)，若是则返回步骤S1，若否则压缩机继续以当前频率运行。Further, step S2 also includes the following steps: during compressor operation, it is judged whether the single operation time of the refrigerator is greater than (Kl*Tc/y), if yes, return to step S1, if otherwise, the compressor continues to run at the current frequency.
进一步地，步骤S2还包括如下步骤：S2f判断环境温度是否≥Tb，Tb大于Ta；若是，则进入步骤S2g；若否，则进入步骤S2a；S2g判断冰箱总运行时间是否≥x5*(Kl*Tc/y)，若是，则进入步骤S2h；若否则压缩机以H7频率运行；S2h判断冰箱总运行时间是否≥x6*(Kl*Tc/y)，若是，则压缩机以H8频率运行；若否，则压缩机以H9频率运行；其中，x5、 x6和y均为比例系数，且x6＞x5，x5＞x1，x6＞x3，Kl为冰箱容积，Tc为环境温度，H8＜H9＜H7，H8＞H3，H9＞H4,H7＞H1。Further, step S2 also includes the following steps: S2f judges whether the ambient temperature is greater than or equal to Tb, and Tb is greater than Ta; if yes, proceed to step S2g; if not, proceed to step S2a; S2g judges whether the total operating time of the refrigerator is greater than or equal to x5*(Kl* Tc/y), if yes, go to step S2h; if otherwise, the compressor runs at H7 frequency; S2h judges whether the total running time of the refrigerator is ≥ x6*(Kl*Tc/y), if yes, the compressor runs at H8 frequency; if No, the compressor runs at H9 frequency; where x5, x6 and y are all proportional coefficients, and x6>x5, x5>x1, x6>x3, Kl is the refrigerator volume, Tc is the ambient temperature, H8<H9<H7 , H8>H3, H9>H4, H7>H1.
进一步地，Ta介于1℃～3℃，Tb介于8℃～12℃。Further, Ta is between 1°C and 3°C, and Tb is between 8°C and 12°C.
本发明的有益效果是：本发明的冰箱的控制方法，制冷***的工作状态不再受冷藏温度的控制，并且不需要增加冷藏加热丝，而是会根据环境温度和运行时间来进行自动控制，此冰箱的控制方法不仅能有效制冷，还能实现节能降成本，减少安全隐患。The beneficial effects of the present invention are: in the refrigerator control method of the present invention, the working state of the refrigeration system is no longer controlled by the refrigeration temperature, and there is no need to increase the refrigeration heating wire, but will be automatically controlled according to the ambient temperature and operating time, The control method of the refrigerator can not only effectively refrigerate, but also realize energy saving and cost reduction, and reduce potential safety hazards.
附图说明Description of the drawings
为了更清楚地说明本发明实施例或现有技术中的技术方案，下面将对实施例或现有技术描述中所需要使用的附图作简单地介绍，显而易见地，下面描述中的附图仅仅是本发明的实施例，对于本领域普通技术人员来讲，在不付出创造性劳动的前提下，还可以根据提供的附图获得其他的附图。In order to explain the embodiments of the present invention or the technical solutions in the prior art more clearly, the following will briefly introduce the drawings that need to be used in the description of the embodiments or the prior art. Obviously, the drawings in the following description are only It is an embodiment of the present invention. For those of ordinary skill in the art, other drawings can be obtained based on the provided drawings without creative work.
图1为本发明一较佳实施例中的冰箱的控制方法流程图；Fig. 1 is a flowchart of a control method of a refrigerator in a preferred embodiment of the present invention;
图2为本发明一具体实施例的冰箱的控制方法流程图；FIG. 2 is a flowchart of a control method of a refrigerator according to a specific embodiment of the present invention;
图3本发明另一较佳实施例的冰箱的控制方法流程图；Fig. 3 is a flow chart of a refrigerator control method according to another preferred embodiment of the present invention;
图4是本发明另一较佳实施例的冰箱的控制方法流程图；Fig. 4 is a flowchart of a refrigerator control method according to another preferred embodiment of the present invention;
图5是本发明另一较佳实施例的冰箱的控制方法流程图；Figure 5 is a flowchart of a refrigerator control method according to another preferred embodiment of the present invention;
图6是本发明另一较佳实施例的冰箱的控制方法流程图。Fig. 6 is a flowchart of a refrigerator control method according to another preferred embodiment of the present invention.
具体实施方式Detailed ways
下面将结合本发明实施例中的附图，对本发明实施例中的技术方案进行清楚、完整地描述，显然，所描述的实施例仅仅是本发明一部分实施例，而不是全部的实施例。基于本发明中的实施例，本领域普通技术人员在没有做出创造性劳动前提下所获得的所有其他实施例，都属于本发明保护的范围。The technical solutions in the embodiments of the present invention will be clearly and completely described below in conjunction with the accompanying drawings in the embodiments of the present invention. Obviously, the described embodiments are only a part of the embodiments of the present invention, rather than all the embodiments. Based on the embodiments of the present invention, all other embodiments obtained by those of ordinary skill in the art without creative work shall fall within the protection scope of the present invention.
请参阅图1～图6所示，为本发明较佳实施例的冰箱的控制方法，包括如下步骤：S1获取冰箱所处环境的环境温度Tc，获取冰箱的运行时间；S2根据环境温度和运行时间控制制冷***的工作状态。该控制方法中，制冷***的启停不再受冷藏温度的控制，并且不需要增加冷藏加热丝，而是会根据环境温度和运行时间来进行自动控制，此冰箱的控制方法不仅能有效制冷，还能实现节能降成本，减少安全隐患。Please refer to Figures 1 to 6, which are a preferred embodiment of the refrigerator control method of the present invention, including the following steps: S1 obtains the ambient temperature Tc of the environment in which the refrigerator is located, and obtains the operating time of the refrigerator; S2 Time controls the working status of the refrigeration system. In this control method, the start and stop of the refrigeration system is no longer controlled by the refrigeration temperature, and there is no need to add refrigeration heating wires, but will be automatically controlled according to the ambient temperature and running time. This refrigerator control method can not only effectively refrigerate, but also It can also achieve energy saving and cost reduction, and reduce safety hazards.
发明人在研究中发现，冰箱容积Kl的大小决定食物存放量大小，食物存放量大小决定食物温度冷却率d/dt；冰箱容积Kl越大，食物存放量也就越大，食物温度冷却率d/dt却越小。The inventor found in the research that the size of the refrigerator volume Kl determines the food storage volume, and the food storage volume determines the food temperature cooling rate d/dt; the larger the refrigerator volume Kl, the greater the food storage volume, and the food temperature cooling rate d /dt is smaller.
环境温度Tc大小决定冰箱热交换速度，冰箱热交换速度决定食物温度冷却率d/dt，也就是说环境温度Tc越大，冰箱热交换速度越慢，食物温度冷却率d/dt却越小。The size of the ambient temperature Tc determines the heat exchange rate of the refrigerator, and the refrigerator heat exchange rate determines the food temperature cooling rate d/dt. That is to say, the greater the ambient temperature Tc, the slower the refrigerator heat exchange rate, but the lower the food temperature cooling rate d/dt.
冰箱容积Kl与环境温度Tc为逻辑“与”关系，其中任何一方的变动都能影响交流压缩机、直流压缩机的控制方法。因此，步骤S2基于冰箱的容积Kl，通过检测环境温度和冰箱运行时间对压缩机的运行进行控制。The refrigerator volume Kl and the ambient temperature Tc are in a logical “AND” relationship, and the change of any one of them can affect the control method of the AC compressor and the DC compressor. Therefore, in step S2, based on the volume K1 of the refrigerator, the operation of the compressor is controlled by detecting the ambient temperature and the operation time of the refrigerator.
请参阅图1～图3所示，当制冷***中的压缩机为交流压缩机时，步骤S2包括如下步骤：Please refer to Figures 1 to 3, when the compressor in the refrigeration system is an AC compressor, step S2 includes the following steps:
S21判断环境温度是否≥T1，若是，则开机后进入步骤S22；若否，则开机后进入步骤S23；本领域技术人员可以理解的是，此处以及本文后续提及的“开机”指的是启动压缩机。S21 judges whether the ambient temperature is greater than or equal to T1, if yes, then proceed to step S22 after booting; if not, then proceed to step S23 after booting; those skilled in the art can understand that the “boot” mentioned here and later in this article refers to Start the compressor.
S22判断冰箱单次运行时间是否≥a1*(Kl*Tc/b)，若是，则停机；若否则继续运行步骤S22；本领域技术人员可以理解的是，此处以及本文后续提及的“停机”指的是关闭压缩机，制冷***不再工作。S22 judge whether the single running time of the refrigerator is ≥a1*(Kl*Tc/b), if yes, stop; if otherwise, continue to run step S22; those skilled in the art can understand that the “stop” mentioned here and later in this article "It means that the compressor is turned off and the refrigeration system is no longer working.
S23判断冰箱单次运行时间是否≥a2*(Kl*Tc/b)，若是，则停机；若否则继续运行步骤S23；其中，a1、a2和b为比例系数，且a1＞a2，Kl为冰箱容积，Tc为环境温度。S23 judge whether the single operation time of the refrigerator is ≥ a2*(Kl*Tc/b), if yes, stop; if otherwise, continue to run step S23; where a1, a2, and b are proportional coefficients, and a1>a2, Kl is the refrigerator Volume, Tc is the ambient temperature.
该方法通过冰箱的容积、环境温度综合考虑冰箱的整体热负荷，冰箱的运行时间以a*(Kl*Tc/b)为参考，更能够精确且合理地控制冰箱的温度；其中，在不同的步骤中，系数a以a1，a2……an表示，n为大于1的自然数。This method comprehensively considers the overall heat load of the refrigerator through the volume and ambient temperature of the refrigerator. The operating time of the refrigerator is based on a*(Kl*Tc/b), which can more accurately and reasonably control the temperature of the refrigerator; In the step, the coefficient a is represented by a1, a2...an, and n is a natural number greater than 1.
进一步地，步骤S2还包括：位于步骤S22之后的步骤S22’：判断冰箱单次停机时间是否≥c1*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S22’；位于步骤S23之后的步骤S23’：判断冰箱单次停机时间是否≥c2*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S23’；其中，c1和c2均为系数，且c2＞c1；Kl为冰箱容积，Tc为环境温度。Further, step S2 also includes: step S22' after step S22: judging whether the single shutdown time of the refrigerator is ≥ c1*(Kl*Tc/b); if yes, return to step S1; if not, continue to run step S22'; Step S23' after step S23: judge whether the refrigerator single stop time ≥ c2*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S23'; where c1 and c2 are coefficients , And c2>c1; Kl is the volume of the refrigerator, and Tc is the ambient temperature.
该方法通过冰箱的容积、环境温度综合考虑冰箱的整体热负荷，冰箱的停机时间以c*(Kl*Tc/b)为参考，更能够精确且合理地控制冰箱的温度。其中，在不同的步骤中，系数c以 c1，c2……cn表示，n为大于1的自然数。This method comprehensively considers the overall heat load of the refrigerator through the volume and ambient temperature of the refrigerator, and the shutdown time of the refrigerator is based on c*(Kl*Tc/b), which can more accurately and reasonably control the temperature of the refrigerator. Among them, in different steps, the coefficient c is represented by c1, c2...cn, and n is a natural number greater than 1.
进一步地，步骤S2还包括：S24判断环境温度是否≥T2，T2大于T1；若是，则开机并进入步骤S25；若否，则进入步骤S21；S25判断冰箱单次运行时间是否≥a3*(Kl*Tc/b)，若是，则停机；若否则继续运行步骤S25；其中，a3为比例系数，且a3＞a1，Kl为冰箱容积，Tc为环境温度。Further, step S2 also includes: S24 judging whether the ambient temperature is greater than or equal to T2, and T2 is greater than T1; if yes, turn on the machine and proceed to step S25; if not, proceed to step S21; S25 judge whether the single operation time of the refrigerator is greater than or equal to a3*(Kl *Tc/b), if yes, stop; if not, continue to run step S25; where a3 is a proportional coefficient, and a3>a1, Kl is the refrigerator volume, and Tc is the ambient temperature.
进一步地，步骤S2还包括：位于步骤S25之后的S25’,判断冰箱单次停机时间是否≥c3*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S25’；其中，c1、c2和c3均为系数，且c3＜c1＜c2；Kl为冰箱容积，Tc为环境温度。Further, step S2 also includes: S25' located after step S25, judging whether the single downtime of the refrigerator is ≥c3*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S25'; where , C1, c2 and c3 are all coefficients, and c3<c1<c2; Kl is the volume of the refrigerator, and Tc is the ambient temperature.
该方法中，环境温度越低，压缩机单次运行的时间越短，单次停机的时间越长，依此实现对比冰箱的温度控制。In this method, the lower the ambient temperature, the shorter the compressor single operation time, and the longer the single shutdown time, so that the temperature control of the comparative refrigerator is realized.
本发明将冰箱所处的环境分为多个温度区间，且根据不同的环境温度设置相应的系数。一具体实施例中，请参考图2所示，T1介于1℃～3℃，T2介于8℃～12℃；在低温下不依赖于加热丝仍然能有效地控制冰箱的运行。The present invention divides the environment where the refrigerator is located into a plurality of temperature ranges, and sets corresponding coefficients according to different environmental temperatures. In a specific embodiment, please refer to FIG. 2 where T1 is between 1°C and 3°C, and T2 is between 8°C and 12°C; the operation of the refrigerator can still be effectively controlled at low temperatures without relying on heating wires.
相邻的两个温度区间之间的控制方法与上述T1和T2温度下的控制方法相类似，根据实际情况b＝100，系数a，c会根据所处环境温度做相应的调整。具体参考如下：The control method between two adjacent temperature ranges is similar to the above-mentioned control method at T1 and T2 temperatures. According to the actual situation, b=100, and the coefficients a and c will be adjusted accordingly according to the ambient temperature. The specific reference is as follows:
当Tc≥20℃，a介于1.0～1.2之间，当冰箱单次运行时间小于A*(Kl*Tc/100)时，冰箱不能快速地达到制冷效果；当冰箱单次运行时间大于1.2A*(Kl*Tc/100)时冰箱节能效果差。c介于0.3～0.4之间，当冰箱单次停机时间小于0.3A*(Kl*Tc/100)时，冰箱节能效果差；当冰箱单次停机时间大于0.4A*(Kl*Tc/b)时冰箱不能快速地达到制冷效果。When Tc≥20℃ and a is between 1.0～1.2, when the single operation time of the refrigerator is less than A*(Kl*Tc/100), the refrigerator cannot quickly achieve the cooling effect; when the single operation time of the refrigerator is greater than 1.2A *(Kl*Tc/100), the refrigerator has poor energy saving effect. c is between 0.3 and 0.4. When the single downtime of the refrigerator is less than 0.3A*(Kl*Tc/100), the energy saving effect of the refrigerator is poor; when the single downtime of the refrigerator is greater than 0.4A*(Kl*Tc/b) The refrigerator cannot quickly achieve the cooling effect.
当10℃≤Tc＜20℃，a介于0.7～0.9，当冰箱单次运行时间小于0.7*(Kl*Tc/100)时，冰箱不能快速地达到制冷效果；当冰箱单次运行时间大于0.9*(Kl*Tc/100)时冰箱节能效果差。c介于0.5～0.7，当冰箱单次停机时间小于0.5(Kl*Tc/100)时，冰箱节能效果差；当冰箱单次停机时间大于0.7(Kl*Tc/100)时冰箱不能快速地达到制冷效果。When 10℃≤Tc＜20℃, a is between 0.7～0.9, when the single operation time of the refrigerator is less than 0.7*(Kl*Tc/100), the refrigerator cannot quickly achieve the cooling effect; when the single operation time of the refrigerator is greater than 0.9 *(Kl*Tc/100), the refrigerator has poor energy saving effect. c is between 0.5 and 0.7. When the single downtime of the refrigerator is less than 0.5 (Kl*Tc/100), the refrigerator has a poor energy saving effect; when the single downtime of the refrigerator is greater than 0.7 (Kl*Tc/100), the refrigerator cannot quickly reach Refrigeration effect.
当3℃≤Tc＜10℃，a介于0.5～0.6，当冰箱单次运行时间小于0.5(Kl*Tc/100)时，冰箱不能快速地达到制冷效果；当冰箱单次运行时间大于0.6(Kl*Tc/100)时冰箱节能效果差。c介于1.0～1.5，当冰箱单次停机时间小于(Kl*Tc/100)时，冰箱节能效果差；当冰箱单次停机 时间大于1.5(Kl*Tc/100)时冰箱不能快速地达到制冷效果。When 3℃≤Tc＜10℃ and a is between 0.5～0.6, when the single operation time of the refrigerator is less than 0.5 (Kl*Tc/100), the refrigerator cannot quickly achieve the cooling effect; when the single operation time of the refrigerator is greater than 0.6( Kl*Tc/100), the refrigerator has a poor energy-saving effect. c is between 1.0 and 1.5. When the single downtime of the refrigerator is less than (Kl*Tc/100), the refrigerator has a poor energy-saving effect; when the single downtime of the refrigerator is greater than 1.5 (Kl*Tc/100), the refrigerator cannot quickly achieve cooling Effect.
当Tc＜3℃时，a介于0.2～0.4，当冰箱单次运行时间小于0.2(Kl*Tc/100)时，冰箱不能快速地达到制冷效果；当冰箱单次运行时间大于0.4(Kl*Tc/100)时冰箱节能效果差。c介于4～6，当冰箱单次停机时间小于4Kl*Tc时，冰箱浪费电量；当冰箱单次停机时间大于6(Kl*Tc/100)时冰箱不能快速地达到制冷效果。When Tc<3℃, a is between 0.2～0.4. When the single operation time of the refrigerator is less than 0.2(Kl*Tc/100), the refrigerator cannot quickly achieve the cooling effect; when the single operation time of the refrigerator is greater than 0.4(Kl* At Tc/100), the refrigerator has poor energy-saving effect. c is between 4 and 6. When the single downtime of the refrigerator is less than 4Kl*Tc, the refrigerator wastes electricity; when the single downtime of the refrigerator is greater than 6 (Kl*Tc/100), the refrigerator cannot quickly achieve the cooling effect.
一具体实施例中，请参考图2所示，T1为3℃，T2为10℃，其他参数请参考图2所示，在低温下不依赖于加热丝仍然能有效地控制冰箱的运行。In a specific embodiment, please refer to Figure 2. T1 is 3°C and T2 is 10°C. For other parameters, please refer to Figure 2. The operation of the refrigerator can still be effectively controlled at low temperatures without relying on heating wires.
另请参考图3所示，步骤S2还包括：S26判断环境温度是否≥20℃；若是，则开机并进入步骤S27；若否，则进入步骤S24；S27判断冰箱单次运行时间是否≥(Kl*Tc/b)，若是，则停机；若否则继续运行步骤S27。Please also refer to Fig. 3, step S2 also includes: S26 judges whether the ambient temperature is ≥20°C; if yes, turn on the machine and go to step S27; if not, go to step S24; S27 judge whether the single operation time of the refrigerator is ≥(Kl *Tc/b), if yes, stop; if otherwise, continue to run step S27.
进一步地，步骤S2还包括：位于步骤S27之后的S27’,判断冰箱单次停机时间是否≥0.3*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S27’。Further, step S2 also includes: S27' after step S27, judging whether the single shutdown time of the refrigerator is ≥0.3*(Kl*Tc/b); if yes, return to step S1; if not, continue to run step S27'.
因此在冰箱的可使用环境温度下，均可以基于冰箱容积，并通过环境温度和冰箱运行时间来控制制冷***的启停，无需在冷藏室设置温度传感器。并且，环境温度越低，冰箱的单次运行时间越短，停机时间越长，节能效果好。Therefore, under the usable ambient temperature of the refrigerator, the start and stop of the refrigeration system can be controlled based on the volume of the refrigerator and the ambient temperature and the running time of the refrigerator, without setting a temperature sensor in the refrigerating compartment. In addition, the lower the ambient temperature, the shorter the single running time of the refrigerator, the longer the downtime, and the better the energy-saving effect.
另请参考图4～图6所示，当压缩机为直流压缩机时，步骤S2包括如下步骤：S2a判断环境温度是否≥Ta，若是，则进入步骤S2b；若否，则进入步骤S2c；S2b判断冰箱总运行时间是否≥x1*(Kl*Tc/y)，若是，则进入步骤S2d；若否则压缩机以H1频率运行；S2c判断冰箱总运行时间是否≥x2*(Kl*Tc/y)，若是，则进入步骤S2e；若否则压缩机以H2频率运行；S2d判断冰箱总运行时间是否≥x3*(Kl*Tc/y)，若是，则压缩机以H3频率运行；若否，则压缩机以H4频率运行；S2e判断冰箱总运行时间是否≥x4*(Kl*Tc/y)，若是，则压缩机以H5频率运行；若否，则压缩机以H6频率运行；其中，x1、x2、x3、x4和y均为比例系数，且x1＞x2，x3＞x4，x3＞x1，x4＞x2，Kl为冰箱容积，Tc为环境温度，H1＞H2，H3＞H5，H4＞H6，H1＞H4＞H3，H2＞H6＞H5。Please also refer to Figures 4 to 6, when the compressor is a DC compressor, step S2 includes the following steps: S2a determines whether the ambient temperature is greater than or equal to Ta, if yes, then proceeds to step S2b; if not, then proceeds to step S2c; S2b Judge whether the total running time of the refrigerator is ≥x1*(Kl*Tc/y), if yes, go to step S2d; if otherwise, the compressor runs at H1 frequency; S2c judges whether the total running time of the refrigerator is ≥ x2*(Kl*Tc/y) If yes, go to step S2e; if otherwise, the compressor runs at H2 frequency; S2d judges whether the total running time of the refrigerator is ≥ x3*(Kl*Tc/y), if yes, then the compressor runs at H3 frequency; if not, then compress The machine runs at H4 frequency; S2e judges whether the total running time of the refrigerator is ≥ x4*(Kl*Tc/y), if yes, the compressor runs at H5 frequency; if not, the compressor runs at H6 frequency; among them, x1, x2 , X3, x4 and y are all proportional coefficients, and x1>x2, x3>x4, x3>x1, x4>x2, Kl is the refrigerator volume, Tc is the ambient temperature, H1>H2, H3>H5, H4>H6, H1>H4>H3, H2>H6>H5.
该方法中，基于冰箱的容积，通过压缩机运行频率和运行时间控制压缩机的运行频率，无需设置低温补充加热丝。并且，在同一温度下，随着压缩机运行总时间的延长，逐级降低 压缩机运行的频率H，可以有效防止制冷间室突然过冷，且控制更精确。In this method, based on the volume of the refrigerator, the operating frequency and operating time of the compressor are used to control the operating frequency of the compressor, and there is no need to set a low-temperature supplementary heating wire. Moreover, at the same temperature, as the total operating time of the compressor is extended, the operating frequency H of the compressor is reduced step by step, which can effectively prevent the refrigeration compartment from being suddenly overcooled, and the control is more precise.
进一步地，步骤S2还包括如下步骤：压缩机运行过程中，判断冰箱单次运行时间是否大于(Kl*Tc/y)，若是则返回步骤S1，若否则压缩机继续以当前频率运行；进一步起到节能且精确控温的效果。Further, step S2 also includes the following steps: during compressor operation, it is judged whether the single operation time of the refrigerator is greater than (Kl*Tc/y), if yes, then return to step S1, if otherwise, the compressor continues to run at the current frequency; To the effect of energy saving and precise temperature control.
进一步地，步骤S2包括如下步骤：S2f判断环境温度是否≥Tb，Tb大于Ta；若是，则进入步骤S2g；若否，则进入步骤S2a；S2g判断冰箱总运行时间是否≥x5*(Kl*Tc/y)，若是，则进入步骤S2h；若否则压缩机以H7频率运行；S2h判断冰箱总运行时间是否≥x6*(Kl*Tc/y)，若是，则压缩机以H8频率运行；若否，则压缩机以H9频率运行；其中，x5、x6和y均为比例系数，且x6＞x5，x5＞x1，x6＞x3，Kl为冰箱容积，Tc为环境温度，H8＜H9＜H7，H8＞H3，H9＞H4,H7＞H1。其中x1～x6,H1～H9的数值与冰箱的容积和环境温度有关，在冰箱容积一定的情况下，环境温度越低，冰箱总运行时间越短，压缩机运行频率越小，节能效果好。Further, step S2 includes the following steps: S2f judges whether the ambient temperature is greater than or equal to Tb, and Tb is greater than Ta; if yes, proceed to step S2g; if not, proceed to step S2a; S2g judges whether the total running time of the refrigerator is greater than or equal to x5*(Kl*Tc /y), if yes, go to step S2h; if otherwise, the compressor runs at H7 frequency; S2h judges whether the total running time of the refrigerator is ≥ x6*(Kl*Tc/y), if yes, then the compressor runs at H8 frequency; if not , The compressor runs at H9 frequency; among them, x5, x6 and y are proportional coefficients, and x6>x5, x5>x1, x6>x3, Kl is the refrigerator volume, Tc is the ambient temperature, H8<H9<H7, H8>H3, H9>H4, H7>H1. Among them, the values of x1～x6 and H1～H9 are related to the volume of the refrigerator and the ambient temperature. With a certain volume of the refrigerator, the lower the ambient temperature, the shorter the total running time of the refrigerator and the lower the compressor operating frequency, which has a better energy-saving effect.
本发明将冰箱所处的环境分为多个温度区间，且根据不同的环境温度设置相应的系数。一具体实施例中，请参考图2所示，T1介于1℃～3℃，T2介于8℃～12℃；在低温下不依赖于加热丝仍然能有效地控制冰箱的运行。The present invention divides the environment where the refrigerator is located into a plurality of temperature ranges, and sets corresponding coefficients according to different environmental temperatures. In a specific embodiment, please refer to FIG. 2 where T1 is between 1°C and 3°C, and T2 is between 8°C and 12°C; the operation of the refrigerator can still be effectively controlled at low temperatures without relying on heating wires.
相邻的两个温度区间之间的控制方法与上述Ta和Tb温度下的控制方法相类似，根据实际情况b＝10，系数a，和压缩机的运行频率H会根据实际环境温度做相应的调整。具体参考如下：The control method between two adjacent temperature ranges is similar to the above-mentioned control method at Ta and Tb temperature. According to the actual situation, b=10, the coefficient a, and the operating frequency H of the compressor will be based on the actual ambient temperature. Adjustment. The specific reference is as follows:
当Tc≥20℃时，冰箱总运行时间1中的x介于1.0～1.2之间，当冰箱总运行时间1小于(Kl*Tc/10)时，冰箱不能快速地达到制冷效果；当冰箱总运行时间1大于1.2(Kl*Tc/10)时冰箱节能效果差。冰箱总运行时间2中的x介于2～3之间，当冰箱总运行时间2小于2(Kl*Tc/10)时，冰箱不能快速地达到制冷效果；当冰箱总运行时间2大于3(Kl*Tc/10)时冰箱节能效果差。When Tc≥20℃, x in the total running time 1 of the refrigerator is between 1.0 and 1.2. When the total running time 1 of the refrigerator is less than (Kl*Tc/10), the refrigerator cannot quickly achieve the cooling effect; When the running time 1 is greater than 1.2 (Kl*Tc/10), the refrigerator has a poor energy-saving effect. The x in the total operating time of the refrigerator 2 is between 2 and 3. When the total operating time of the refrigerator 2 is less than 2 (Kl*Tc/10), the refrigerator cannot quickly achieve the cooling effect; when the total operating time of the refrigerator 2 is greater than 3 ( Kl*Tc/10), the refrigerator has poor energy-saving effect.
当10℃≤Tc＜20℃时，冰箱总运行时间1中的x介于0.8～0.9之间，当冰箱总运行时间1小于0.8(Kl*Tc/10)，冰箱不能快速地达到制冷效果；当冰箱总运行时间1大于0.9(Kl*Tc/10)时冰箱节能效果差。冰箱总运行时间2中的x介于1.6～1.8之间，当冰箱总运 行时间2小于1.6(Kl*Tc/10)时，冰箱不能快速地达到制冷效果；当冰箱总运行时间2大于1.8(Kl*Tc/10)时冰箱节能效果差。When 10℃≤Tc＜20℃, the x in the total running time 1 of the refrigerator is between 0.8 and 0.9. When the total running time 1 of the refrigerator is less than 0.8 (Kl*Tc/10), the refrigerator cannot quickly achieve the cooling effect; When the total running time 1 of the refrigerator is greater than 0.9 (Kl*Tc/10), the energy saving effect of the refrigerator is poor. The x in the total running time 2 of the refrigerator is between 1.6 and 1.8. When the total running time 2 of the refrigerator is less than 1.6 (Kl*Tc/10), the refrigerator cannot quickly achieve the cooling effect; when the total running time 2 of the refrigerator is greater than 1.8 ( Kl*Tc/10), the refrigerator has poor energy-saving effect.
当3℃≤Tc＜10℃时，冰箱总运行时间1的系数x介于0.6～0.7之间，当冰箱总运行时间1小于0.6(Kl*Tc/10)时，冰箱不能快速地达到制冷效果；当冰箱总运行时间1大于0.7(Kl*Tc/10)时冰箱节能效果差。冰箱总运行时间2的系数x介于1.2～1.4之间；当冰箱总运行时间2小于1.2(Kl*Tc/10)时，冰箱不能快速地达到制冷效果；当冰箱总运行时间2大于1.4(Kl*Tc/10)时冰箱节能效果差。When 3℃≤Tc＜10℃, the coefficient x of the refrigerator's total operating time 1 is between 0.6 and 0.7. When the refrigerator's total operating time 1 is less than 0.6 (Kl*Tc/10), the refrigerator cannot quickly achieve the cooling effect ; When the total running time 1 of the refrigerator is greater than 0.7 (Kl*Tc/10), the energy saving effect of the refrigerator is poor. The coefficient x of the total running time 2 of the refrigerator is between 1.2 and 1.4; when the total running time 2 of the refrigerator is less than 1.2 (Kl*Tc/10), the refrigerator cannot quickly achieve the cooling effect; when the total running time 2 of the refrigerator is greater than 1.4 ( Kl*Tc/10), the refrigerator has poor energy-saving effect.
当Tc＜3℃时，冰箱总运行时间1的系数x介于0.4～0.5之间，当冰箱总运行时间1小于0.4(Kl*Tc/10)时，冰箱不能快速地达到制冷效果；当冰箱总运行时间1大于0.5(Kl*Tc/10)时冰箱节能效果差。冰箱总运行时间2的系数x介于1.0～1.1之间，当冰箱总运行时间2小于(Kl*Tc/10)时，冰箱不能快速地达到制冷效果；当冰箱总运行时间2大于1.1(Kl*Tc/10)时冰箱节能效果差。When Tc<3℃, the coefficient x of the refrigerator's total operating time 1 is between 0.4 and 0.5. When the refrigerator's total operating time 1 is less than 0.4 (Kl*Tc/10), the refrigerator cannot quickly achieve the cooling effect; When the total running time 1 is greater than 0.5 (Kl*Tc/10), the refrigerator has a poor energy-saving effect. The coefficient x of the total running time 2 of the refrigerator is between 1.0 and 1.1. When the total running time 2 of the refrigerator is less than (Kl*Tc/10), the refrigerator cannot quickly achieve the cooling effect; when the total running time 2 of the refrigerator is greater than 1.1 (Kl *Tc/10), the refrigerator has a poor energy-saving effect.
一具体实施例中，请参阅图5所示，Ta介于1℃～3℃，Tb介于8℃～12℃，其他参数参考图5所示，在低温下不依赖于加热丝仍然能有效地控制冰箱的运行。In a specific embodiment, please refer to Figure 5. Ta is between 1°C and 3°C, and Tb is between 8°C and 12°C. Refer to Figure 5 for other parameters. It can still be effective at low temperatures without relying on the heating wire. To control the operation of the refrigerator.
另请参阅图6所示，步骤S2进一步还包括如下步骤：S2i判断环境温度是否≥20℃，若是，则进入步骤S2j；若否，则进入步骤S2f；S2j判断冰箱总运行时间是否≥(Kl*Tc/10)min，若是，则进入步骤S2k；若否则压缩机以100Hz频率运行；S2k判断冰箱总运行时间是否≥2(Kl*Tc/10)min，若是，则压缩机以60Hz频率运行；若否，则压缩机以80Hz频率运行。Please also refer to Fig. 6, step S2 further includes the following steps: S2i judges whether the ambient temperature is ≥20°C, if yes, then proceeds to step S2j; if not, then proceeds to step S2f; S2j judges whether the total running time of the refrigerator is ≥(Kl *Tc/10)min, if yes, go to step S2k; if otherwise, the compressor runs at 100Hz; S2k judges whether the total running time of the refrigerator is ≥2(Kl*Tc/10)min, if yes, the compressor runs at 60Hz ; If not, the compressor runs at 80Hz.
因此在冰箱的可使用环境温度下，均可以基于冰箱容积，并通过环境温度和冰箱运行时间来控制压缩机的运行频率，无需在冷藏室设置温度传感器。并且，环境温度越低，冰箱的运行频率越低，运行时间越短，节能效果好。Therefore, the operating frequency of the compressor can be controlled based on the volume of the refrigerator under the usable ambient temperature of the refrigerator, and the operating frequency of the compressor can be controlled through the ambient temperature and the operating time of the refrigerator, without setting a temperature sensor in the refrigerator compartment. Moreover, the lower the ambient temperature, the lower the operating frequency of the refrigerator, the shorter the operating time, and the better the energy-saving effect.
综上所述，本发明的冰箱的控制方法，制冷***的工作状态不再受冷藏温度的控制，并且不需要增加冷藏加热丝，而是会根据环境温度和运行时间来进行自动控制，此冰箱的控制方法不仅能有效制冷，还能实现节能降成本，减少安全隐患。To sum up, in the refrigerator control method of the present invention, the working state of the refrigeration system is no longer controlled by the refrigeration temperature, and there is no need to increase the refrigeration heating wire, but will automatically control according to the ambient temperature and operating time. The control method can not only effectively refrigerate, but also achieve energy saving and cost reduction, and reduce safety hazards.
应当理解，虽然本说明书按照实施方式加以描述，但并非每个实施方式仅包含一个独立的技术方案，说明书的这种叙述方式仅仅是为清楚起见，本领域技术人员应当将说明书作 为一个整体，各实施方式中的技术方案也可以经适当组合，形成本领域技术人员可以理解的其他实施方式。It should be understood that although this specification is described in accordance with the implementation manners, not each implementation manner only includes an independent technical solution. This narration in the specification is only for the sake of clarity, and those skilled in the art should regard the specification as a whole. The technical solutions in the embodiments can also be appropriately combined to form other embodiments that can be understood by those skilled in the art.
上文所列出的一系列的详细说明仅仅是针对本发明的可行性实施方式的具体说明，它们并非用以限制本发明的保护范围，凡未脱离本发明技艺精神所作的等效实施方式或变更均应包含在本发明的保护范围之内。The series of detailed descriptions listed above are only specific descriptions of the feasible implementations of the present invention. They are not intended to limit the scope of protection of the present invention. Any equivalent implementations or implementations made without departing from the technical spirit of the present invention All changes shall be included in the protection scope of the present invention.

Claims (10)

  1. 一种单***冰箱的控制方法，其特征在于，包括如下步骤：A control method of a single-system refrigerator, characterized in that it comprises the following steps:
    S1获取冰箱所处环境的环境温度Tc，获取冰箱的运行时间；S1 obtains the ambient temperature Tc of the environment where the refrigerator is located, and obtains the operating time of the refrigerator;
    S2根据环境温度和运行时间控制制冷***的工作状态。S2 controls the working state of the refrigeration system according to the ambient temperature and operating time.
  2. 根据权利要求1所述的冰箱的控制方法，其特征在于，步骤S2包括如下步骤：The refrigerator control method according to claim 1, wherein step S2 includes the following steps:
    S21判断环境温度是否≥T1，若是，则开机后进入步骤S22；若否，则开机后进入步骤S23；S21 judge whether the ambient temperature is greater than or equal to T1, if yes, then proceed to step S22 after booting; if not, then proceed to step S23 after booting;
    S22判断冰箱单次运行时间是否≥a1*(Kl*Tc/b)，若是，则停机；若否则继续运行步骤S22；S22 judge whether the single running time of the refrigerator is ≥a1*(Kl*Tc/b), if yes, stop; if not, continue to run step S22;
    S23判断冰箱单次运行时间是否≥a2*(Kl*Tc/b)，若是，则停机；若否则继续运行步骤S23；S23 judge whether the single running time of the refrigerator is ≥a2*(Kl*Tc/b), if yes, stop; if not, continue to run step S23;
    其中，a1、a2和b为比例系数，且a1＞a2，Kl为冰箱容积，Tc为环境温度。Among them, a1, a2, and b are proportional coefficients, and a1>a2, Kl is the refrigerator volume, and Tc is the ambient temperature.
  3. 根据权利要求2所述的单***冰箱的控制方法，其特征在于，步骤S2还包括：位于步骤S22之后的步骤S22’：判断冰箱单次停机时间是否≥c1*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S22’；The control method of a single-system refrigerator according to claim 2, wherein step S2 further comprises: step S22' after step S22: judging whether a single shutdown time of the refrigerator is greater than or equal to c1*(Kl*Tc/b); If yes, return to step S1; if otherwise, continue to run step S22';
    位于步骤S23之后的步骤S23’：判断冰箱单次停机时间是否≥c2*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S23’；Step S23' after step S23: Determine whether the single shutdown time of the refrigerator ≥ c2*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S23';
    其中，c1和c2均为系数，且c1＜c2；Kl为冰箱容积，Tc为环境温度。Among them, c1 and c2 are coefficients, and c1<c2; Kl is the volume of the refrigerator, and Tc is the ambient temperature.
  4. 根据权利要求2所述的单***冰箱的控制方法，其特征在于，步骤S2包括如下步骤：The control method of a single-system refrigerator according to claim 2, wherein step S2 includes the following steps:
    S24判断环境温度是否≥T2，T2大于T1；若是，则开机后进入步骤S25；若否，则进入步骤S21；S24 judge whether the ambient temperature is greater than or equal to T2, and T2 is greater than T1; if it is, then go to step S25 after booting; if not, go to step S21;
    S25判断冰箱单次运行时间是否≥a3*(Kl*Tc/b)，若是，则停机；若否则继续运行步骤S25；其中，a3为比例系数，且a3＞a1，Kl为冰箱容积，Tc为环境温度。S25 judge whether the single operation time of the refrigerator is ≥ a3*(Kl*Tc/b), if yes, stop; if otherwise, continue to run step S25; where a3 is the proportional coefficient, and a3>a1, Kl is the refrigerator volume, and Tc is Ambient temperature.
  5. 根据权利要求4所述的单***冰箱的控制方法，其特征在于，步骤S2还包括：The control method of a single-system refrigerator according to claim 4, wherein step S2 further comprises:
    位于步骤S22之后的步骤S22’：判断冰箱单次停机时间是否≥c1*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S22’；Step S22' after step S22: judge whether the single stop time of the refrigerator is ≥ c1*(Kl*Tc/b); if yes, go back to step S1; if otherwise, continue to run step S22';
    位于步骤S23之后的步骤S23’：判断冰箱单次停机时间是否≥c2*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S23’；Step S23' after step S23: Determine whether the single shutdown time of the refrigerator ≥ c2*(Kl*Tc/b); if yes, return to step S1; if otherwise, continue to run step S23';
    位于步骤S25之后的S25’,判断冰箱单次停机时间是否≥c3*(Kl*Tc/b)；若是，则返回步骤S1；若否则继续运行步骤S25’；In S25' after step S25, it is judged whether the single downtime of the refrigerator is ≥ c3*(Kl*Tc/b); if yes, return to step S1; if not, continue to run step S25';
    其中，c1、c2和c3均为系数，且c3＜c1＜c2；Kl为冰箱容积，Tc为环境温度。Among them, c1, c2, and c3 are all coefficients, and c3<c1<c2; Kl is the volume of the refrigerator, and Tc is the ambient temperature.
  6. 根据权利要求4所述的单***冰箱的控制方法，其特征在于，T1介于1℃～3℃，T2介于8℃～12℃。The control method of a single-system refrigerator according to claim 4, wherein T1 is between 1°C and 3°C, and T2 is between 8°C and 12°C.
  7. 根据权利要求1所述的冰箱的控制方法，其特征在于，步骤S2包括如下步骤：The refrigerator control method according to claim 1, wherein step S2 includes the following steps:
    S2a判断环境温度是否≥Ta，若是，则进入步骤S2b；若否，则进入步骤S2c；S2a judges whether the ambient temperature is greater than or equal to Ta, if yes, go to step S2b; if not, go to step S2c;
    S2b判断冰箱总运行时间是否≥x1*(Kl*Tc/y)，若是，则进入步骤S2d；若否则压缩机以H1频率运行；S2b judges whether the total running time of the refrigerator is ≥x1*(Kl*Tc/y), if yes, go to step S2d; if otherwise, the compressor runs at H1 frequency;
    S2c判断冰箱总运行时间是否≥x2*(Kl*Tc/y)，若是，则进入步骤S2e；若否则压缩机以H2频率运行；S2c judges whether the total running time of the refrigerator is ≥ x2*(Kl*Tc/y), if yes, go to step S2e; if otherwise, the compressor runs at H2 frequency;
    S2d判断冰箱总运行时间是否≥x3*(Kl*Tc/y)，若是，则压缩机以H3频率运行；若否，则压缩机以H4频率运行；S2d judges whether the total running time of the refrigerator is ≥x3*(Kl*Tc/y), if yes, the compressor runs at H3 frequency; if not, the compressor runs at H4 frequency;
    S2e判断冰箱总运行时间是否≥x4*(Kl*Tc/y)，若是，则压缩机以H5频率运行；若否，则压缩机以H6频率运行；S2e judges whether the total running time of the refrigerator is ≥ x4*(Kl*Tc/y), if yes, the compressor runs at H5 frequency; if not, the compressor runs at H6 frequency;
    其中，x1、x2、x3、x4和y均为比例系数，且x1＞x2，x3＞x4，x3＞x1，x4＞x2，Kl为冰箱容积，Tc为环境温度，H1＞H2，H3＞H5，H4＞H6，H1＞H4＞H3，H2＞H6＞H5。Among them, x1, x2, x3, x4 and y are all proportional coefficients, and x1>x2, x3>x4, x3>x1, x4>x2, Kl is the refrigerator volume, Tc is the ambient temperature, H1>H2, H3>H5 , H4>H6, H1>H4>H3, H2>H6>H5.
  8. 根据权利要求7所述的单***冰箱的控制方法，其特征在于，步骤S2还包括如下步骤：压缩机运行过程中，判断冰箱单次运行时间是否大于(Kl*Tc/y)，若是则返回步骤S1，若否则压缩机继续以当前频率运行。The control method of a single-system refrigerator according to claim 7, wherein step S2 further comprises the following steps: during the operation of the compressor, it is determined whether the single operation time of the refrigerator is greater than (Kl*Tc/y), and if so, it returns Step S1, if otherwise, the compressor continues to run at the current frequency.
  9. 根据权利要求7所述的单***冰箱的控制方法，其特征在于，步骤S2还包括如下步骤：The control method of a single-system refrigerator according to claim 7, wherein step S2 further comprises the following steps:
    S2f判断环境温度是否≥Tb，Tb大于Ta；若是，则进入步骤S2g；若否，则进入步骤 S2a；S2f judges whether the ambient temperature is greater than or equal to Tb, and Tb is greater than Ta; if yes, go to step S2g; if not, go to step S2a;
    S2g判断冰箱总运行时间是否≥x5*(Kl*Tc/y)，若是，则进入步骤S2h；若否则压缩机以H7频率运行；S2g judges whether the total running time of the refrigerator ≥ x5*(Kl*Tc/y), if yes, go to step S2h; if otherwise, the compressor runs at H7 frequency;
    S2h判断冰箱总运行时间是否≥x6*(Kl*Tc/y)，若是，则压缩机以H8频率运行；若否，则压缩机以H9频率运行；S2h judges whether the total running time of the refrigerator is ≥x6*(Kl*Tc/y), if yes, the compressor runs at H8 frequency; if not, the compressor runs at H9 frequency;
    其中，x5、x6和y均为比例系数，且x6＞x5，x5＞x1，x6＞x3，Kl为冰箱容积，Tc为环境温度，H8＜H9＜H7，H8＞H3，H9＞H4,H7＞H1。Among them, x5, x6 and y are proportional coefficients, and x6>x5, x5>x1, x6>x3, Kl is the refrigerator volume, Tc is the ambient temperature, H8<H9<H7, H8>H3, H9>H4, H7 >H1.
  10. 根据权利要求9所述的单***冰箱的控制方法，其特征在于，Ta介于1℃～3℃，Tb介于8℃～12℃。The control method of a single-system refrigerator according to claim 9, wherein Ta is between 1°C and 3°C, and Tb is between 8°C and 12°C.
PCT/CN2021/087777 2020-08-04 2021-04-16 Control method for single-system refrigerator WO2021213272A1 (en)

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