CN115146354A - Automatic generation method for column reinforcing bars - Google Patents
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Abstract
The invention relates to the technical field of building design, and discloses an automatic generation method of column reinforcing bars, which comprises the following steps: s1, customizing a hooping allowable diameter table and a longitudinal bar allowable diameter table corresponding to a rectangular column; s2, respectively determining the diameters dj of first angle ribs on the B sides of the rectangular columns 1 And the first fillet diameter dj 1 The corresponding diameter and the number of the first middle longitudinal bars are calculated; s3, determining the number of first middle longitudinal ribs corresponding to the side B of the rectangular column and the number of second middle longitudinal ribs corresponding to the side H, and comparing whether the difference between the number of the first middle longitudinal ribs and the number of the second middle longitudinal ribs exceeds a threshold value; s4, determining the diameter of a first stirrup corresponding to the side B according to the determined diameter and the number of the first middle longitudinal ribs; and S5, calculating the stirrup spacing of the column stirrup non-encryption area through the calculation value of the stirrup non-encryption area, the diameter of the stirrup and the industrial specification requirement. The invention can automatically complete the drawing of the detailed reinforcing bar drawing.
Description
Technical Field
The invention relates to the technical field of building design, in particular to an automatic generation method of column reinforcing bars.
Background
The structural design is generally expressed by adopting a plane integral design method (a flat method) of a construction drawing of a building structure, and the size and reinforcing bars of a structural member are simply expressed in a plane writing mode.
In the design of the construction drawing of the current architectural engineering structure, how to design the structural members efficiently and accurately becomes the key point and the difficulty of the industry. Typically, structural computing software can generate column reinforcements, but the reinforcement accuracy and construction requirements are difficult to meet specification standards and design requirements. In addition, when drawing manually, many strokes of mistakes are inevitably generated, which all need to be avoided and solved urgently.
Disclosure of Invention
The invention provides a method for automatically generating a column reinforcing bar, which can automatically generate a reinforcing bar detailed diagram of a concrete rectangular column based on computer programming, automatically finish the drawing of the reinforcing bar detailed diagram according to parameters such as the size, the position, the elevation, the calculation information, the concrete strength grade, the earthquake resistance grade and the like of a frame column in a concrete structure, meet the national standard requirement of the column reinforcing bar diagram drawn by the method, and give consideration to the economy and the structural design rationality to meet the design requirement.
The invention is realized by the following technical scheme:
an automatic generation method of column reinforcements comprises the following steps:
s1, customizing a stirrup allowable diameter table and a longitudinal bar allowable diameter table corresponding to a rectangular column according to the reinforcing habit of a designer;
s2, respectively determining the diameters dj of first angle ribs on the B sides of the rectangular columns 1 And a second corner rib diameter dj of the H side 2 Taking the diameter dj of the first rib 1 And a second corner bead diameter dj 2 The larger value is the diameter dj of the corner rib corresponding to the rectangular column;
s3, determining the number of first intermediate longitudinal ribs, the corresponding diameter of the first intermediate longitudinal ribs, the number of second intermediate longitudinal ribs and the corresponding diameter of the second intermediate longitudinal ribs according to the determined diameter dj of the angle ribs and the calculated value of the longitudinal ribs, comparing whether the difference between the number of the first intermediate longitudinal ribs and the number of the second intermediate longitudinal ribs exceeds a threshold value, if so, returning to the step, re-determining the number of the first intermediate longitudinal ribs and the number of the second intermediate longitudinal ribs, and otherwise, skipping to S4;
s4, determining a first stirrup diameter corresponding to the B side and a second stirrup diameter corresponding to the H side according to the determined first middle longitudinal bar diameter, the determined first middle longitudinal bar number, the determined second middle longitudinal bar diameter, the determined second middle longitudinal bar number, a stirrup allowable diameter table, a stirrup calculation value and an industry specification requirement, and taking the larger value of the first stirrup diameter and the second stirrup diameter as the stirrup diameter corresponding to the rectangular column;
s5, calculating the stirrup spacing of the column stirrup non-encryption area through the calculated value of the stirrup non-encryption area, the diameter of the stirrup corresponding to the rectangular column and the industry standard requirement;
and S6, drawing a detailed column reinforcement diagram according to the result obtained from the S2-S5.
As an optimization, in step S2, a first corner rib diameter dj corresponding to the B side of the rectangular column is determined 1 The specific steps of the value range are as follows:
s2.1, selecting a first minimum angle rib diameter dj meeting the calculated value of the angle rib on the side B in the longitudinal rib allowable diameter table 1min ；
S2.2, based on the first minimum fillet diameter dj 1min The diameter of the angle rib is gradually increased and adjusted, on the premise that the middle longitudinal rib interval meets the requirements of the industry standard, the rib arrangement form of a single row of the angle rib is adopted, the calculation value of B-edge rib arrangement is combined (the calculation value of B-edge rib arrangement = the calculation value of B-edge rib and the calculation value of B-edge middle longitudinal rib), the number of first middle longitudinal ribs and the diameter of first middle longitudinal ribs in the same row corresponding to the B edge are calculated, so that the calculation requirements of 'the area of middle longitudinal ribs and the area of angle ribs larger than or equal to the calculation value of B-edge rib' can be met by arranging the first middle longitudinal ribs of the single row on the B edge in the same row, and at the moment, the minimum angle rib diameter meeting the calculation requirements is the first angle rib diameter dj 1 The value range of (a);
s2.3, if the diameter of the angle rib is increased to the maximum value in the allowed diameter table of the longitudinal rib in the S2.2 and the calculation requirement that the area of the middle longitudinal rib and the area of the angle rib are not larger than or equal to the output calculation value cannot be met, carrying out reinforcement in a mode of combining the angle ribs, wherein the maximum value of the diameter of the longitudinal rib in the allowed diameter table of the longitudinal rib is the first diameter dj of the angle rib 1 。
As an optimization, in step S2, a second corner rib diameter dj corresponding to the H side of the rectangular column is determined 2 The method comprises the following specific steps:
s2.4, selecting the second minimum angle rib diameter dj meeting the calculated value of the angle rib on the H side in the longitudinal rib allowable diameter table 2min ；
S2.5, based on the second minimum fillet diameter dj 2min The diameter of the angle rib is gradually increased and adjusted, on the premise that the intermediate longitudinal rib interval meets the requirement of the industry standard, the rib arrangement form of a single row of angle ribs is adopted, H-edge rib arrangement calculation values are combined, the number of the second intermediate longitudinal ribs and the diameter of the second intermediate longitudinal ribs in the same row corresponding to the H edge are calculated, the calculation requirement that the area of the middle longitudinal rib and the area of the angle rib are larger than or equal to the H-edge rib arrangement calculation value can be met by arranging the single row of second intermediate longitudinal ribs on the H edge in the same row, and at the moment, the minimum angle rib diameter meeting the calculation requirement is the diameter dj of the second angle rib 2 The value range of (a);
s2.6, if the diameter of the angle rib is increased to the maximum value in the allowable diameter table of the longitudinal rib in the S2.5, the calculation that the area of the middle longitudinal rib and the area of the angle rib are larger than or equal to the output calculated value can not be metIf necessary, reinforcing bars are arranged in a mode of combining angle bars and bars, and at the moment, the maximum value of the diameter of the longitudinal bar in the longitudinal bar allowable diameter table is the diameter dj of the second angle bar 2 。
As optimization, the number of the first middle longitudinal ribs, the diameter of the first middle longitudinal ribs and the diameter dj of the first angular ribs 1 The relationship between them is:
wherein, N BM1 The number of the first middle longitudinal ribs, d BM1 Is the diameter of the first intermediate longitudinal rib, A sB Calculating the reinforcement on the side B, A sM Showing the reinforcement area of the middle longitudinal reinforcement;
the number of the second middle longitudinal ribs, the diameter of the second middle longitudinal ribs and the diameter dj of the second corner ribs 2 The relationship between them is:
wherein, N BM2 The number of the second middle longitudinal ribs, d BM2 Is the diameter of the second middle longitudinal rib, A sH Calculated value of reinforcement for the H side, A sM Showing the reinforcement area of the middle longitudinal ribs.
Preferably, the first fillet diameter dj 1 And the first rib diameter dj 1 Corresponding first intermediate longitudinal rib diameter d BM1 The number of the first middle longitudinal bars N BM1 The screening conditions of (1) are as follows:
a1, if the same first middle longitudinal rib number N corresponding to the side B BM1 Corresponding to the diameters d of a plurality of first middle longitudinal ribs BM1 Then selecting the corresponding minimum diameter d of the first intermediate longitudinal bar BM1 Carrying out the next operation;
a2, if the obtained first middle longitudinal rib number N BM1 So that the distance between the first middle longitudinal ribs does not meet the requirement of the industry specification, the number N of the first middle longitudinal ribs is not selected BM1 ；
A3, if no, selectingA middle longitudinal bar number N BM1 If the industrial standard requirement is met, the reinforcement failure is judged; if there is a first middle longitudinal rib number N BM1 If the requirement of the industry standard is met, the number N of the first middle longitudinal bars is selected BM1 And corresponding first intermediate longitudinal rib diameter d BM1 And a first fillet diameter dj 1 (ii) a If there are at least two different first intermediate longitudinal rib numbers N BM1 If the requirements of the industry specifications are met, selecting two first middle longitudinal bar diameters d with the largest diameters BM1 Corresponding first middle longitudinal bar number N BM1 ；
A4, trial calculation is carried out on the basis of the minimum stirrup diameter in the stirrup selection diameter table, and if two first middle longitudinal bar numbers N screened out by A3 BM1 If the calculated values of the hooping encryption areas are met, the first middle longitudinal bar number N with smaller number is selected BM1 (ii) a If two first middle longitudinal bar numbers N screened out by A3 BM1 If only one calculated value satisfying the stirrup encryption area is selected, the first middle longitudinal bar number N satisfying the calculation value of the stirrup encryption area is selected BM1 (ii) a If two first middle longitudinal bar numbers N screened out by A3 BM1 If the calculated values of the stirrup encryption areas are not satisfied, increasing the diameter of the first-stage stirrup and returning to the step for trial calculation continuously;
a5, if the calculated value of the stirrup in the encryption area cannot be met even if the maximum available diameter of the stirrup in the diameter table for stirrup selection is selected in the A4, the number N of the first middle longitudinal bars is not selected BM1 The reinforcement fails.
Preferably, the second corner rib diameter dj 2 And the diameter dj of the second corner rib 2 Corresponding second intermediate longitudinal rib diameter d BM2 Number of second intermediate longitudinal bars N BM2 The screening conditions of (1) are as follows:
b1, if the same second middle longitudinal rib number N corresponding to the H side BM2 Corresponding to the diameters d of a plurality of first middle longitudinal ribs BM2 Selecting the corresponding minimum diameter d of the first middle longitudinal bar BM2 Carrying out the next operation;
b2, obtaining the number N of the second middle longitudinal bars BM2 So that the distance between the second middle longitudinal bars does not meet the industry standard requirement, the second middle longitudinal bars are not selectedNumber of middle longitudinal bars N BM2 ；
B3, if no second middle longitudinal rib number N is screened out BM2 If the industrial standard requirement is met, the reinforcement failure is judged; if there is a second middle longitudinal rib number N BM2 If the requirement of the industry standard is met, the number N of the second middle longitudinal bars is selected BM2 And corresponding second intermediate longitudinal rib diameter d BM2 And a second corner bead diameter dj 2 (ii) a If there are at least two different second intermediate longitudinal rib numbers N BM2 If the requirement of the industry standard is met, the maximum diameter d of two second middle longitudinal bars is selected BM2 Number of second middle longitudinal ribs N BM2 ；
B4, trial calculation is carried out on the basis of the smallest stirrup diameter in the stirrup selection diameter table, and if two second middle longitudinal bar numbers N screened out by the B3 are adopted BM2 If the calculated values of the hooping encryption areas are met, the number N of the second middle longitudinal bars is smaller BM2 (ii) a Number N of second middle longitudinal bars selected from B4 BM2 Only one calculated value satisfying the stirrup encryption area is selected as the second middle longitudinal bar number N satisfying the calculation value of the stirrup encryption area BM2 (ii) a If two second middle longitudinal bar numbers N screened out by B4 BM2 If the calculated value of the stirrup encryption area is not satisfied, increasing the diameter of the first-stage stirrup and returning to the step for trial calculation;
b5, if the calculated value of the stirrups in the encryption area cannot be met even if the maximum available stirrup diameter in the stirrup selection diameter table in the B4 is selected, not selecting the number N of the second middle longitudinal bars BM2 The reinforcement fails.
As optimization, the specific steps of step 3 are:
s3.1, enabling the number of unidirectional hooped limbs in the column encryption area to be equal to the number of middle longitudinal ribs in the direction, wherein the number of the hooped limbs is generally equal to the number of single-row longitudinal ribs;
s3.2, respectively calculating a first minimum stirrup diameter required by the side B and a second minimum stirrup diameter required by the side H according to the set stirrup spacing and the stirrup calculation value of the column encryption area;
s3.3, judging whether the first minimum stirrup diameter and the second minimum stirrup diameter are equal, if not, considering that the difference between the longitudinal bar number in the middle of the first and the longitudinal bar number in the middle of the second is too large, and adjusting the longitudinal bar diameter in the middle of the first and/or the second to adjust the longitudinal bar number in the middle of the first and/or the second until the difference between the longitudinal bar number in the middle of the first and the second is less than a threshold value.
As an optimization, in S4, the specific calculation manner of the first stirrup diameter is as follows: the distance between the program column stirrups is 100, the diameter of the stirrup is
Wherein dv B The first stirrup diameter corresponding to side B, A sv The calculated value of the stirrup for the column node core area and the column stirrup encryption area is larger than the calculated value n B The number of the B-side stirrup limbs is shown.
As an optimization, in S4, the specific calculation manner of the diameter of the second stirrup is as follows: the distance between the program column stirrups is 100, and the program column stirrups have the diameter of the stirrups
Wherein dv H Is the diameter of the second stirrup on the H side, A sv The calculated value of the stirrup for the column node core area and the column stirrup encryption area is larger than the calculated value n H The number of the hoops is H.
As optimization, in S5, the specific calculation mode of the stirrup spacing of the column stirrup non-encryption region is as follows: under normal conditions, the diameters of stirrups in the encrypted region and the unencrypted region are equal, the distance between stirrups in the unencrypted region is half of the distance between stirrups in the encrypted region, namely the distance between stirrups in the encrypted region is 100, the distance between stirrups in the unencrypted region is 200, and the industrial specification requirements are met, for example, the first-level frame column and the second-level frame column are not more than 10 times of the diameter of the longitudinal steel bar, and the third-level frame column and the fourth-level frame column are not more than 15 times of the diameter of the longitudinal steel bar.
Compared with the prior art, the invention has the following advantages and beneficial effects:
the method can automatically generate the detailed reinforcing steel bar diagram of the rectangular concrete column, automatically finish the drawing of the detailed reinforcing steel bar diagram according to the parameters of the size, the position, the elevation, the calculation information, the concrete strength grade, the earthquake resistance grade and the like of the frame column in the concrete structure, meet the national standard requirements of the column reinforcing steel bar diagram drawn by the method, and give consideration to the economy and the structural design rationality to the greatest extent so as to meet the design requirements, improve the drawing efficiency of the column reinforcing steel bar diagram, and reduce the errors possibly generated in the aspects of the specification and the marking by manual drawing.
Drawings
In order to more clearly illustrate the technical solutions of the exemplary embodiments of the present invention, the drawings that are required in the embodiments will be briefly described below, it should be understood that the following drawings only illustrate some embodiments of the present invention and therefore should not be considered as limiting the scope, and that those skilled in the art may also derive other related drawings based on these drawings without inventive effort. In the drawings:
FIG. 1 is a flow chart of an automatic generation method of a column reinforcement bar according to the present invention;
FIG. 2 is an exemplary table of allowable stirrup diameter and allowable longitudinal bar diameter;
FIG. 3 is a graph showing the calculated value of KZ180 in the column of the example;
FIG. 4 is a schematic representation of the results of the reinforcement automatically generated by column KZ180 by the present invention.
Detailed Description
In order to make the objects, technical solutions and advantages of the present invention more apparent, the present invention is further described in detail below with reference to examples and the accompanying drawings, and the exemplary embodiments and descriptions thereof are only used for explaining the present invention and are not used as limiting the present invention.
Examples
As shown in fig. 1, a flowchart of an automatic generation method for a column reinforcement according to the present invention specifically includes:
s1, customizing a hooping allowable diameter table and a longitudinal bar allowable diameter table corresponding to the rectangular column according to the reinforcing habit of a designer.
As shown in fig. 2, an example table of the hoop allowable diameter table and the longitudinal allowable diameter table is shown. According to the reinforcing habit of the designer, different hoop allowable diameter tables and longitudinal bar allowable diameter tables are defined. The parameters in the hoop allowable diameter table and the longitudinal bar allowable diameter table represent the used values of the diameter of the hoop and the diameter of the longitudinal bar respectively.
S2, respectively determining the diameters dj of first corner ribs on the B side of the rectangular column 1 And a second corner rib diameter dj of the H side 2 Taking the diameter dj of the first rib 1 And a second corner rib diameter dj 2 The larger value is the diameter dj of the corner rib corresponding to the rectangular column; for example, the smallest first rib diameter dj that meets the calculation requirements 1 22, second corner rib diameter dj 2 18, the diameter dj of the corner rib corresponding to the rectangular column is 22.
1. First consider the reinforcement scheme (B1) for one pair of sides (B-sides) of a rectangular column:
in this embodiment, the diameter dj of the first corner rib corresponding to the B side of the rectangular column is determined 1 The method comprises the following specific steps:
s2.1, selecting a first minimum angle rib diameter dj meeting the calculated value of the angle rib on the side B in the longitudinal rib allowable diameter table 1min 。
In an available 'longitudinal rib allowable diameter table' defined by a user, the smallest corner rib diameter meeting the requirement of the calculated value of the corner rib on the side B is selected in an attempt. The calculation software (the conventional software for calculating structures such as PKPM or YJK, and the like, which is the prior art) can output the calculated value of the column corner rib (obtained according to the stress condition, the mechanical principle and the industry specification), and the actual area of the corner rib is not less than the calculated value of the corner rib on the side B.
S2.2, based on the first minimum corner rib diameter dj 1min The diameter of the angle rib is gradually increased and adjusted, on the premise that the middle longitudinal rib interval meets the requirements of the industry standard, the rib arrangement form of a single row of the angle rib is adopted, the calculation value of B-edge rib arrangement is combined (the calculation value of B-edge rib arrangement = the calculation value of B-edge rib and the calculation value of B-edge middle longitudinal rib), the number of first middle longitudinal ribs and the diameter of first middle longitudinal ribs in the same row corresponding to the B edge are calculated, so that the calculation requirements of 'the area of middle longitudinal ribs and the area of angle ribs larger than or equal to the calculation value of B-edge rib' can be met by arranging the first middle longitudinal ribs of the single row on the B edge in the same row, and at the moment, the minimum angle rib diameter meeting the calculation requirements is the first angle rib diameter dj 1 The value range of (a).
S2.3, if the diameter of the angle rib is increased to the maximum value in the allowable diameter table of the longitudinal ribs in the S2.2 and the calculation requirement that the area of the middle longitudinal rib and the area of the angle rib are larger than or equal to an output calculation value (calculated value of the rib on the side B) cannot be met, performing rib distribution in a rib combining mode by adopting the angle rib, wherein the maximum value of the diameter of the longitudinal rib in the allowable diameter table of the longitudinal rib is the first diameter dj of the angle rib 1 And then, the number of the first middle longitudinal ribs on the side B in the same row is recalculated.
Assuming that the diameter of the angle bar is larger than or equal to the diameter of the first middle longitudinal bar, under the condition that the distance between the first middle longitudinal bars meets the industry standard requirements (the industry standard requirements include but are not limited to building earthquake design specifications GB50011-2010, high-rise building concrete structure technical specifications JGJ3-2010 and concrete structure design specifications GB 50010-2010), the diameter of the angle bar is adjusted, so that the calculation requirements can be met only by arranging single rows (the same row) of the first middle longitudinal bars on the side B (the area of the middle longitudinal bar is larger than or equal to the area of the angle bar in a software output calculated value, the diameter of the middle steel bar cannot be larger than the diameter of the angle bar, if the diameter of the angle bar is 16, the diameter of the middle steel bar can be 16 at the maximum, and if the calculated value of the middle steel bar is 10, but because of the standard distance limit exists, the diameter of the angle bar cannot be arranged in one row, the diameter of the angle bar is increased to 18, the diameter of the middle steel bar can be selected only 8, if the diameter of the angle bar is not arranged in the row, the other row, the experiment is continued, and the diameter of the angle bar is increased to the maximum value of the angle bar, and the diameter of the angle bar can not be selected, and the requirement can be met, if the diameter of the angle bar, the diameter of the angle bar is allowed in the table, and the angle bar, the angle bar diameter of the angle bar is still found.
In this embodiment, the number of the first middle longitudinal ribs, the diameter of the first middle longitudinal ribs and the diameter dj of the first corner ribs 1 The relationship between them is:
wherein, N BM1 The number of the first middle longitudinal ribs, d BM1 Is a first middle longitudinalDiameter of the ribs, A sB Calculate the reinforcement for side B, A sM Showing the reinforcement area of the middle longitudinal reinforcement.
According to the diameter and the form (parallel ribs or non-parallel ribs) of the arranged corner ribs and the calculated value of the B-side reinforcing ribs (obtained by outputting calculation software), the configuration scheme of the first middle longitudinal rib on the B side is back calculated by combining the requirements of industry specifications (building earthquake-resistant design specifications GB50011-2010, high-rise building concrete structure technical specifications JGJ3-2010 and concrete structure design specifications GB 50010-2010) (the calculated value of the B-side reinforcing ribs is assumed as A) sB The diameter of the first fillet is dj 1 When the angle bars are parallel bars, dj 1 The equivalent diameter of the first intermediate longitudinal rib is
N BM The number of the first middle longitudinal ribs on the side B (N is rounded upwards), d BM The diameter of the first middle longitudinal rib on the side B.
1. Calculating the diameter d of each first intermediate longitudinal rib according to the formula BM1 The number N of the first middle longitudinal bars corresponding to the requirement BM1 A group of d-N (d) BM1 -N BM1 ) Is a reinforcement scheme of a first middle longitudinal reinforcement.
2. Screening above-mentioned scheme, it is 100mm here to assume that the post encryption district stirrup interval is, and one-way stirrup limb number equals this direction first middle longitudinal bar root number:
(1) And if the same first middle longitudinal rib number N corresponding to the side B corresponds to a plurality of first middle longitudinal rib diameters d, selecting the corresponding minimum first middle longitudinal rib diameter d to perform the next operation.
That is, if there are two sets of solutions, N1= N2 and d1 < d2, then solution 2 is deleted, i.e. the solution with the first intermediate longitudinal rib diameter d smaller is retained.
(2) In the scheme, if the number of the first intermediate longitudinal bars N is such that the distance between the first intermediate longitudinal bars does not meet the requirements of the specifications GB50011-2010 of building earthquake-resistant design specifications, JGJ3-2010 of high-rise building concrete structure technical specifications and GB50010-2010 of concrete structure design specifications, the scheme is deleted. The relationship between the number N of the first intermediate longitudinal ribs and the first intermediate longitudinal rib pitch is that the first intermediate longitudinal ribs are equally distributed in the same row within a predetermined length, and the pitch between the adjacent first intermediate longitudinal ribs is the first intermediate longitudinal rib pitch.
(3) If no residual scheme exists, the reinforcement fails; if one scheme is left, the scheme is selected; if two or more than two schemes (the number N of the first middle longitudinal ribs of the two schemes is different), two schemes (called scheme A and scheme B) with the largest diameter d of the first middle longitudinal ribs are selected. Two schemes with the largest diameter of the first middle longitudinal bars are selected to reduce the number of the longitudinal bars, so that the total number of the steel bars on the section of the column is reduced, and construction is facilitated.
(3.1) trial calculation is carried out by selecting different stirrup diameters according to the following formula:
pi.dv.dv/4. N is not less than Asv, wherein dv is the diameter of the stirrup, n is the number of the stirrup limbs, and Asv is a calculated value output by software; starting from the minimum value of the optional stirrups, if the schemes A and B meet the calculated value of the stirrup encryption area, selecting the scheme with a smaller N value (the number of the first middle longitudinal reinforcements); if only one of the schemes A and B meets the calculated value of the stirrup encryption area, the scheme is selected; if the schemes A and B do not meet the calculated value of the stirrup encryption area, increasing the diameter of the first-stage stirrup and continuing trial calculation;
(3.2) if the first middle longitudinal rib number N in a certain scheme cannot meet the calculated value of the stirrups in the encryption region even if the maximum available stirrup diameter is selected, deleting the scheme, namely, the number of the stirrups limbs is too small, namely, the number of the longitudinal ribs is too small.
2. Secondly, consider the reinforcement scheme (H1) of the other opposite side (H side) of the rectangular column, the method is the same as B side, and will not be described here again. Schemes B1 and H1 are then coordinated so that both share one corner rib configuration (taking the corner rib configuration with the larger total corner rib area in both as the shared configuration).
S3, according to the determined diameter dj of the angle rib and the calculated value of the longitudinal rib, determining the number of longitudinal ribs in the middle of the first, the corresponding diameter of the longitudinal rib in the middle of the first, the number of longitudinal ribs in the middle of the second and the corresponding diameter of the longitudinal rib in the middle of the second, comparing whether the difference between the number of longitudinal ribs in the middle of the first and the second exceeds a threshold value, if so, returning to the step, re-determining the number of longitudinal ribs in the middle of the first and the second, and otherwise, skipping to S4.
In this embodiment, the specific steps of step 3 are:
s3.1, enabling the number of unidirectional hooped limbs in the column encryption area to be equal to the number of middle longitudinal ribs in the direction, wherein the number of the hooped limbs is generally equal to the number of single-row longitudinal ribs;
s3.2, respectively calculating a first minimum stirrup diameter required by the side B and a second minimum stirrup diameter required by the side H according to the set stirrup spacing and the stirrup calculation value of the column encryption area;
s3.3, judging whether the first minimum stirrup diameter and the second minimum stirrup diameter are equal, if not, considering that the difference between the longitudinal bar number in the middle of the first and the longitudinal bar number in the middle of the second is too large, and adjusting the longitudinal bar diameter in the middle of the first and/or the second to adjust the longitudinal bar number in the middle of the first and/or the second until the difference between the longitudinal bar number in the middle of the first and the second is less than a threshold value. The threshold value is determined according to the actual situation, and is not described in detail.
Assuming that the distance between stirrups in a column encryption area is 100mm and the number of unidirectional stirrups limbs is equal to the number of longitudinal reinforcements in the direction, respectively calculating the minimum stirrup diameter required by the schemes B1 and H1 reversely according to the calculated value of the stirrups in the encryption area, and if the calculated minimum stirrup diameters of the schemes B1 and H1 are unequal, considering that the difference between the number of longitudinal reinforcements in the middle of the schemes B1 and H1 is too large and needing to be coordinated. The specific method comprises the following steps: if the number of the first middle longitudinal bars of the B1 is more than that of the second middle longitudinal bars of the H1, the number of the first middle longitudinal bars of the B1 scheme is reduced by using larger-diameter steel bars (the diameter of the angle bars cannot be exceeded), and the number of the first middle longitudinal bars of the B1 scheme is not less than that of the corresponding H1 scheme, and vice versa.
S4, determining a first stirrup diameter corresponding to the side B and a second stirrup diameter corresponding to the side H according to the determined first middle longitudinal rib diameter, the determined first middle longitudinal rib number, the determined second middle longitudinal rib diameter, the determined second middle longitudinal rib number, the determined stirrup allowable diameter table, the calculated stirrup value and the industry standard requirement, and taking the larger value of the first stirrup diameter and the second stirrup diameter as the stirrup diameter corresponding to the rectangular column.
In this embodiment, the specific calculation manner of the diameter of the first stirrup is as follows: the distance between the program column stirrups is 100, the diameter of the stirrup is
Wherein dv B The first stirrup diameter corresponding to side B, A sv The calculated value of the stirrup in the column node core area and the column stirrup encryption area is larger, n B The number of the hoops on the B side is shown.
In this embodiment, the specific calculation manner of the diameter of the second stirrup is as follows: the distance between the program column stirrups is 100, the diameter of the stirrup is
Wherein dv H Is the diameter of the second stirrup on the H side, A sv The calculated value of the stirrup for the column node core area and the column stirrup encryption area is larger than the calculated value n H The number of the hoops is H.
S5, calculating the stirrup spacing of the column stirrup non-encryption area through the calculation value of the stirrup non-encryption area, the diameter of the stirrup and the industrial specification requirement;
in this embodiment, the specific calculation method of the stirrup spacing in the column stirrup non-encryption region is as follows: in S5, the specific calculation mode of the stirrup spacing of the column stirrup non-encryption area is as follows: under normal conditions, the diameters of stirrups in the encrypted region and the unencrypted region are equal, the distance between stirrups in the unencrypted region is half of the distance between stirrups in the encrypted region, namely the distance between stirrups in the encrypted region is 100, the distance between stirrups in the unencrypted region is 200, and the industrial specification requirements are met, for example, the first-level frame column and the second-level frame column are not more than 10 times of the diameter of the longitudinal steel bar, and the third-level frame column and the fourth-level frame column are not more than 15 times of the diameter of the longitudinal steel bar.
And S6, drawing a detailed column reinforcement diagram according to the result obtained from the S2-S5.
As shown in FIG. 3, it can be seen that the calculated value of column KZ180, the longitudinal rib at side B is 12cm 2 H edge longitudinal rib calculation value is 19cm 2 Calculated value of angle rib is 2.6cm 2 The calculated value of the stirrup in the core area of the column node is 1.2cm 2 The calculated value of the stirrup encryption area is 1.1cm 2 The calculated value of the non-encrypted area of the stirrup is 0.7cm 2 。
As shown in fig. 4, is the reinforcement result automatically generated by the present invention for column KZ 180.
As can be seen in FIG. 4, the actual reinforcement value 2D25+2D20=16 > 12 on the B side, the actual reinforcement value 2D25+3D22=21 > 19 on the H side, the diameter D25=4.9 > 2.6 of the angle rib, the hooping encryption region C8@150 limb hoop, the actual reinforcement value 1.3 > max (1.2, 1.1), the hooping non-encryption region C8@200 limb hoop, the actual reinforcement value 1.0 > 0.7, and all the actual reinforcement values meet the calculated value requirements, so that the reliability of the method is verified.
The above-mentioned embodiments are intended to illustrate the objects, technical solutions and advantages of the present invention in further detail, and it should be understood that the above-mentioned embodiments are merely exemplary embodiments of the present invention, and are not intended to limit the scope of the present invention, and any modifications, equivalent substitutions, improvements and the like made within the spirit and principle of the present invention should be included in the scope of the present invention.
Claims (10)
1. An automatic generation method of column reinforcing bars is characterized by comprising the following steps:
s1, customizing a hooping allowable diameter table and a longitudinal bar allowable diameter table corresponding to a rectangular column;
s2, respectively determining the diameters dj of first angle ribs on the B sides of the rectangular columns 1 And a second corner rib diameter dj of the H side 2 Taking the diameter dj of the first rib 1 And a second corner bead diameter dj 2 The larger value is the diameter dj of the corner rib corresponding to the rectangular column;
s3, determining the number of first middle longitudinal ribs, the corresponding diameter of the first middle longitudinal ribs, the number of second middle longitudinal ribs and the corresponding diameter of the second middle longitudinal ribs according to the determined diameter dj of the angle ribs and the calculated value of the longitudinal ribs, comparing whether the difference between the number of the first middle longitudinal ribs and the number of the second middle longitudinal ribs exceeds a threshold value, if so, returning to the step, re-determining the number of the first middle longitudinal ribs and the number of the second middle longitudinal ribs, and otherwise, skipping to S4;
s4, determining a first stirrup diameter corresponding to the B side and a second stirrup diameter corresponding to the H side according to the determined first middle longitudinal bar diameter, the determined first middle longitudinal bar number, the determined second middle longitudinal bar diameter, the determined second middle longitudinal bar number, a stirrup allowable diameter table, a stirrup calculation value and an industry specification requirement, and taking the larger value of the first stirrup diameter and the second stirrup diameter as the stirrup diameter corresponding to the rectangular column;
s5, calculating the stirrup spacing of the column stirrup non-encryption area through the calculated value of the stirrup non-encryption area, the diameter of the stirrup corresponding to the rectangular column and the industry standard requirement;
and S6, drawing a detailed column reinforcement diagram according to the result obtained from the S2-S5.
2. The method as claimed in claim 1, wherein in step S2, the first corner rib diameter dj corresponding to the B side of the rectangular column is determined 1 The method comprises the following specific steps:
s2.1, selecting a first minimum angle rib diameter dj meeting the calculated value of the angle rib on the side B in the longitudinal rib allowable diameter table 1min ；
S2.2, based on the first minimum fillet diameter dj 1min The diameter of the angle rib is gradually increased and adjusted, on the premise that the intermediate longitudinal rib interval meets the requirement of the industry standard, the single-row reinforcement arrangement form of the angle rib is adopted, the calculation value of the reinforcement arrangement at the B edge is combined, the number of the first intermediate longitudinal ribs and the diameter of the first intermediate longitudinal ribs in the same row corresponding to the B edge are calculated, so that the calculation requirement that the area of the middle longitudinal rib and the area of the angle rib are more than or equal to the calculation value of the reinforcement arrangement at the B edge in the same row are met by only arranging the first intermediate longitudinal ribs in the single row is met, and at the moment, the minimum angle rib diameter meeting the calculation requirement is the first angle rib diameter dj 1 ；
S2.3, if the diameter of the angle rib is increased to the maximum value in the allowed diameter table of the longitudinal rib in the S2.2 and the calculation requirement that the area of the middle longitudinal rib and the area of the angle rib are not larger than or equal to the output calculation value cannot be met, carrying out reinforcement in a mode of combining the angle ribs, wherein the maximum value of the diameter of the longitudinal rib in the allowed diameter table of the longitudinal rib is the first diameter dj of the angle rib 1 。
3. The method of claim 2, wherein the method comprisesIn step S2, a second corner rib diameter dj corresponding to the H side of the rectangular column is determined 2 The method comprises the following specific steps:
s2.4, selecting the second minimum angle rib diameter dj meeting the calculated value of the angle rib on the H side in the longitudinal rib allowable diameter table 2min ；
S2.5, based on the second minimum fillet diameter dj 2min Gradually increasing and adjusting the diameter of the angle rib, adopting a single-row rib arrangement form of the angle rib on the premise of ensuring that the space between the middle longitudinal ribs meets the requirement of the industry standard, combining a calculated value of H-edge rib arrangement, and calculating the number of second middle longitudinal ribs and the diameter of the second middle longitudinal ribs in the same row corresponding to the H edge, so that the calculation requirement that the area of the middle longitudinal rib and the area of the angle rib are more than or equal to the calculated value of the H-edge rib arrangement can be met by only arranging the single-row second middle longitudinal ribs on the H edge in the same row, and at the moment, the minimum diameter of the angle rib meeting the calculation requirement is the diameter dj of the second angle rib 2 ；
S2.6, if the diameter of the angle rib is increased to the maximum value in the allowed diameter table of the longitudinal rib in the S2.5 and the calculation requirement that the area of the middle longitudinal rib and the area of the angle rib are not larger than or equal to the output calculation value cannot be met, carrying out reinforcement in a mode of combining the angle ribs, wherein the maximum value of the diameter of the longitudinal rib in the allowed diameter table of the longitudinal rib is the diameter dj of the second angle rib 2 。
4. The method as claimed in claim 3, wherein the number of the first intermediate longitudinal ribs, the diameter of the first intermediate longitudinal ribs and the diameter dj of the first corner ribs are equal to or greater than the number of the first intermediate longitudinal ribs 1 The relationship between them is:
wherein N is BM1 The number of the first middle longitudinal ribs, d BM1 Is the diameter of the first intermediate longitudinal rib, A sB Calculate the reinforcement for side B, A sM Showing the reinforcement area of the middle longitudinal reinforcement;
the number of the second middle longitudinal ribs, the diameter of the second middle longitudinal ribs and the diameter dj of the second corner ribs 2 The relationship between is：
Wherein N is BM2 The number of the second middle longitudinal ribs, d BM2 Is the diameter of the second intermediate longitudinal rib, A sH Calculated value of reinforcement for the H side, A sM Showing the reinforcement area of the middle longitudinal ribs.
5. The method as claimed in claim 4, wherein the first rib diameter dj is set to be larger than the first rib diameter dj 1 And the first fillet diameter dj 1 Corresponding first intermediate longitudinal rib diameter d BM1 The number of the first middle longitudinal bars N BM1 The screening conditions of (1) are as follows:
a1, if the same first middle longitudinal rib number N corresponding to the side B BM1 Corresponding to the diameters d of a plurality of first middle longitudinal bars BM1 Selecting the corresponding minimum diameter d of the first middle longitudinal bar BM1 Carrying out the next operation;
a2, obtaining the first intermediate longitudinal rib number N BM1 So that the distance between the first middle longitudinal bars does not meet the requirement of the industry specification, the number N of the first middle longitudinal bars is not selected BM1 ；
A3, if the screened out has no first middle longitudinal rib number N BM1 If the industrial standard requirement is met, the reinforcement failure is judged; if there is a first middle longitudinal rib number N BM1 If the requirement of the industry standard is met, the number N of the first middle longitudinal bars is selected BM1 And corresponding first intermediate longitudinal rib diameter d BM1 And a first fillet diameter dj 1 (ii) a If there are at least two different first intermediate longitudinal rib numbers N BM1 If the requirements of the industry specifications are met, selecting two first middle longitudinal bar diameters d with the largest diameters BM1 Corresponding first middle longitudinal bar number N BM1 ；
A4, trial calculation is carried out on the basis of the minimum stirrup diameter in the stirrup selection diameter table, and if two first middle longitudinal bar numbers N screened out by A3 BM1 All satisfy the calculated value of the stirrup encryption area, then the selection is performedNumber of first small intermediate longitudinal ribs N BM1 (ii) a If two first middle longitudinal bar numbers N screened out by A3 BM1 If only one calculated value satisfying the stirrup encryption area is selected, the first middle longitudinal bar number N satisfying the calculation value of the stirrup encryption area is selected BM1 (ii) a If two first middle longitudinal bar numbers N screened out by A3 BM1 If the calculated value of the stirrup encryption area is not satisfied, increasing the diameter of the first-stage stirrup and returning to the step for trial calculation;
a5, if the calculated value of the stirrup in the encryption area cannot be met even if the maximum available diameter of the stirrup in the diameter table for stirrup selection is selected in the A4, the number N of the first middle longitudinal bars is not selected BM1 The reinforcement fails.
6. The method as claimed in claim 5, wherein the second angle bead diameter dj is set to be smaller than the first angle bead diameter dj 2 And the second corner rib diameter dj 2 Corresponding second intermediate longitudinal rib diameter d BM2 Number of second intermediate longitudinal bars N BM2 The screening conditions of (1) are as follows:
b1, if the number N of the same second middle longitudinal ribs corresponding to the H side BM2 Corresponding to the diameters d of a plurality of first middle longitudinal ribs BM2 Selecting the corresponding minimum diameter d of the first middle longitudinal bar BM2 Carrying out the next operation;
b2, obtaining the number N of the second middle longitudinal bars BM2 So that the distance between the second middle longitudinal ribs does not meet the requirement of the industry specification, the number N of the second middle longitudinal ribs is not selected BM2 ；
B3, if no second middle longitudinal rib number N is screened out BM2 If the industrial standard requirement is met, the reinforcement failure is judged; if there is a second middle longitudinal rib number N BM2 If the requirement of the industry standard is met, the number N of the second middle longitudinal bars is selected BM2 And corresponding second intermediate longitudinal rib diameter d BM2 And a second corner rib diameter dj 2 (ii) a If there are at least two different second intermediate longitudinal rib numbers N BM2 If the requirement of the industry standard is met, the maximum diameter d of two second middle longitudinal bars is selected BM2 Number of second middle longitudinal ribs N BM2 ；
B4, trial calculation is carried out on the basis of the smallest stirrup diameter in the stirrup selection diameter table, and if two second middle longitudinal bar numbers N screened out by the B3 are adopted BM2 If the calculated values of the hooping encryption areas are met, the number N of the second middle longitudinal bars is smaller BM2 (ii) a Number N of second middle longitudinal bars selected from B4 BM2 If only one calculated value satisfying the stirrup encryption area is selected, the number N of the second middle longitudinal bars satisfying the calculated value of the stirrup encryption area is selected BM2 (ii) a Number N of second middle longitudinal bars selected from B4 BM2 If the calculated values of the stirrup encryption areas are not satisfied, increasing the diameter of the first-stage stirrup and returning to the step for trial calculation continuously;
b5, if the calculated value of the stirrups in the encryption area cannot be met even if the maximum available stirrup diameter in the stirrup selection diameter table in the B4 is selected, not selecting the number N of the second middle longitudinal bars BM2 The reinforcement fails.
7. The automatic generation method of the column reinforcement according to claim 6, characterized in that the concrete steps of step 3 are:
s3.1, making the number of unidirectional hooped limbs in the column encryption area equal to the number of middle longitudinal bars in the direction;
s3.2, respectively calculating a first minimum stirrup diameter required by the B side and a second minimum stirrup diameter required by the H side according to the set stirrup spacing and the stirrup calculation value of the column encryption region;
s3.3, judge first minimum stirrup diameter and second minimum stirrup diameter and whether equal, if the inequality, then think in the middle of the first indulge muscle radical and the second indulge muscle radical disparity too big, indulge muscle diameter in the middle of the first and/or the second and adjust muscle diameter to indulge muscle radical in the middle of the first to indulge muscle radical in the middle of the adjustment first and/or the second, indulge muscle radical in the middle of the adjustment first, until indulge muscle radical in the middle of the first and the second and indulge the difference between the muscle radical and be less than the threshold value.
8. The automatic generation method of column reinforcement according to claim 1, characterized in that in S4, the specific calculation manner of the diameter of the first stirrup is: the column stirrup spacing is made to be 100,then there is the diameter of the stirrup
Wherein dv B The first stirrup diameter corresponding to side B, A sv The calculated value of the stirrup for the column node core area and the column stirrup encryption area is larger than the calculated value n B The number of the hoops on the B side is shown.
9. The automatic generation method of column reinforcement according to claim 1, characterized in that in S4, the specific calculation manner of the diameter of the second stirrup is: the distance between the program column stirrups is 100, and the program column stirrups have the diameter of the stirrups
Wherein dv H Is the diameter of the second stirrup on the H side, A sv The calculated value of the stirrup of the core area of the column node and the calculated value of the stirrup of the encryption area of the column stirrup are larger, n H The number of the hoops is H.
10. The automatic generation method of column reinforcement according to claim 1, characterized in that in S5, the specific calculation manner of the stirrup spacing of the column stirrup non-encryption area is as follows: the diameters of the stirrups in the encryption area and the noncryption area are equal, the distance between the stirrups in the noncryption area is half of the distance between the stirrups in the encryption area, namely the distance between the stirrups in the encryption area is 100, the distance between the stirrups in the noncryption area is 200, and the distance between the stirrups in the encryption area, the diameter of the stirrups in the noncryption area and the diameter of the stirrups in the noncryption area meet the requirements of industrial specifications.
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| Publication number | Priority date | Publication date | Assignee | Title |
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| CN106326556A (en) * | 2016-08-24 | 2017-01-11 | 广州地铁设计研究院有限公司 | Calculation and three-dimensional modeling method of structural reinforcing bars |
| CN108532953A (en) * | 2018-05-18 | 2018-09-14 | 宝业湖北建工集团有限公司 | Overhanging board construction method based on BIM and construction techniques |
| CN109344506A (en) * | 2018-09-30 | 2019-02-15 | 深圳市华阳国际建筑产业化有限公司 | In-depth figure automatic generation method, equipment and the storage medium of BIM threedimensional model |
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| Publication number | Priority date | Publication date | Assignee | Title |
|---|---|---|---|---|
| CN106326556A (en) * | 2016-08-24 | 2017-01-11 | 广州地铁设计研究院有限公司 | Calculation and three-dimensional modeling method of structural reinforcing bars |
| CN108532953A (en) * | 2018-05-18 | 2018-09-14 | 宝业湖北建工集团有限公司 | Overhanging board construction method based on BIM and construction techniques |
| CN109344506A (en) * | 2018-09-30 | 2019-02-15 | 深圳市华阳国际建筑产业化有限公司 | In-depth figure automatic generation method, equipment and the storage medium of BIM threedimensional model |
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