CN109521333A - The multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis method of shielding action between meter and conducting wire - Google Patents

The multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis method of shielding action between meter and conducting wire Download PDF

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Publication number
CN109521333A
CN109521333A CN201810304556.8A CN201810304556A CN109521333A CN 109521333 A CN109521333 A CN 109521333A CN 201810304556 A CN201810304556 A CN 201810304556A CN 109521333 A CN109521333 A CN 109521333A
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phase conductor
away
shielding
point
circle
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唐凯
保承家
姜文东
谷山强
苏杰
刘岩
万家伟
任华
雷梦飞
章涵
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Wuhan NARI Ltd
State Grid Zhejiang Electric Power Co Ltd
Maintenace Co of State Grid Anhui Electric Power Co Ltd
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Wuhan NARI Ltd
State Grid Zhejiang Electric Power Co Ltd
Maintenace Co of State Grid Anhui Electric Power Co Ltd
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    • GPHYSICS
    • G01MEASURING; TESTING
    • G01RMEASURING ELECTRIC VARIABLES; MEASURING MAGNETIC VARIABLES
    • G01R31/00Arrangements for testing electric properties; Arrangements for locating electric faults; Arrangements for electrical testing characterised by what is being tested not provided for elsewhere
    • G01R31/12Testing dielectric strength or breakdown voltage ; Testing or monitoring effectiveness or level of insulation, e.g. of a cable or of an apparatus, for example using partial discharge measurements; Electrostatic testing

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Abstract

The present invention provides the multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis method of shielding action between meter and conducting wire, electric geometry method based on the analysis of multiple-circuit on same tower Characteristic of Lightning Shielding Failure, conducting wire exposed range, conducting wire are calculated in different exposed range lower critical lightning currents, conducting wire shielding flashover strike, by lightning current size divide 4 kinds of situations to based on and between conducting wire the multiple-circuit on same tower Characteristic of Lightning Shielding Failure of shielding action analyze.The analysis method considers existing mutual shielding shielding action between conducting wire, the multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis model for establishing mutual shielding action between considering phase conductor is effective supplement to the existing Characteristic of Lightning Shielding Failure method for calculating multi-circuit lines on the same tower.

Description

The multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis method of shielding action between meter and conducting wire
Technical field
The invention belongs to transmission line of electricity anti-thunder technical fields, more particularly to the resistance to thunder of shielding of same tower double back transmission line The multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis method of shielding action between energy analysis field more particularly to a kind of meter and conducting wire.
Background technique
Overhead transmission line be power grid construction basis, since overhead transmission line is distributed in field, be continuous it is thousands of in, passed through Regional topography and geomorphology is intricate, and geographical conditions and meteorological condition are also varied, easily causes failure by lightning stroke, and lightning stroke is The main factor for causing transmission line of electricity to trip, lightning stroke route cause electric network fault to be always to perplex system stable operation and safety The problem of power supply.China's power system development is rapid, and power system capacity increases year by year, and rack is closer and closer, and overhead line structures are increasingly Height, transmission line of electricity trip accident caused by being struck by lightning is also increasing, how to prevent and reduce lightning stroke route damage caused by power grid Evil, is the Important Problems that power network safety operation must be taken into consideration.
Currently, the method for research route shielding performance mainly has with China power industry standard DL/T620-1997 " exchange The overvoltage protection and Insulation Coordination of electric device " Characteristic of Lightning Shielding Failure is calculated as the empirical model represented, i.e. regular method;With electricity Gas geometrical model (EGM) is the semiempirical model of representative, i.e., classical electric geometry method and improved EGM;With thunder and lightning The leader propagation model (LPM) that development mechanism is derived, the fractal method and shielding to grow up on the basis of first inducing defecation by enema and suppository are general Rate model etc..
Regular method thinks that thunder and lightning attacks the probability of conducting wire and shielding angle, the shaft tower of lightning conducter opposite side phase conductor directly around lightning conducter Height and route institute are related through factors such as regional topography and geomorphology, geological conditions, unrelated with amplitude of lightning current.It will in regular method Route through area topography and geomorphology be simply divided into two class of Plain and mountain area, the risk of shielding failure of route under different terrain conditions It is as follows with the relationship of shielding angle and the family of shaft tower height three:
Plain route:
Mountain route:
In formula, α is the shielding angle (°) of lightning conducter opposite side phase conductor;H is shaft tower height (m);Pa is route thunderbolt Rate.
Electric geometry method is to connect the structure size of the flash-over characteristic of thunder and lightning and route and establish a kind of several What analysis calculation method, the basic principle is that: the pilot discharge channel head developed to the ground by thundercloud reaches and is hit object Critical striking distance-is hit away from former, and it is a little uncertain for hitting, and first reaches hitting away within for which object, i.e., puts to the object Electricity.Hit away from size and the current potential on guide head it is related thus related with the charge in leader channel, the latter determines thunder and lightning again The amplitude of stream.Therefore, it hits away from r and amplitude of lightning current ImThere is direct relation, and it is unrelated with other factors, and W ' S EGM assumes guide To hitting away from equal for shaft tower, lightning conducter, conducting wire and the earth.
First inducing defecation by enema and suppository calculates the sense of object on ground using the method for analysis of electric field by charge simulation descending leader channel Voltage or electric field are answered, after object reaches the critical initial conditions of upward leader on ground, ground object generates upward leader, first The developing direction led is the maximum direction of electric field.Sky when electric field reaches breakdown condition, between descending leader and upward leader Between gap puncture, formed lightning stroke.Therefore the thunderbolt failure analysis of transmission line of electricity approximate can use horizontal conductor structure It is analyzed.According to first inducing defecation by enema and suppository basic principle, shielding flashover strike calculated result mainly by simulation descending leader channel charge model, The criterion of the generation of the uplink and downlink guide speed of development, the direction of motion of uplink and downlink guide, upward leader and breakdown sentence away from It influences.
Point shape pilot model analyzes the influence to leader development model such as different fractal parameters, random factor, solves Fractal Simulation of having determined is applied to the starting of the upward leader in transmission line of electricity lightning protection criterion, relationship and FRACTAL DIMENSION with amplitude of lightning current The major issues such as several calculating and control, while by being compared with thunder discharge in nature and simulation result, it obtains The conclusion for using fractal coefficient to be most consistent for 2 model with actual conditions.
Thunderbolt probabilistic model uses stick-sheet separation structural simulation lightning stroke process final stage, is powered on using long stick Extremely simulate the descending leader close to last transition.The model can calculate located space by the transmission line of electricity of arbitrary structures parameter Shielding probability distribution, and successfully illustrate that classical electrical geometric method is difficult to the field accident reason explained, but should Model is built upon on the basis of laboratory simulation test, and practical application waits further to study.
Summary of the invention
The technical problems to be solved by the present invention are: solving existing electric geometry method (EGM) is calculating multiple-loop line line When the Characteristic of Lightning Shielding Failure on road, the problem of having ignored the mutual shielding action between phase conductor.
To achieve the goals above, The technical solution adopted by the invention is as follows:
The multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis method of shielding action between meter and conducting wire, which is characterized in that be based on The electric geometry method of multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis, to conducting wire exposed range, conducting wire in different exposed ranges Lower critical lightning current, conducting wire shielding flashover strike are calculated, and formula is based onWherein SFFORC For shielding probability of flashover, NgFor CG lightning density, IcmaxFor maximum shielding lightning current, IcFor the resistance to Lei Shuiping of shielding, Z is exposed range, P (I) is amplitude of lightning current cumulative probability density function, divides 4 kinds of situation shielding actions to based on and between conducting wire by lightning current size Multiple-circuit on same tower Characteristic of Lightning Shielding Failure is analyzed, and the analysis method includes:
(1) it is based on same tower double back transmission line EGM model, calculates the exposed range of each phase conductor;
(2) according to the calculated result of exposed range, corresponding critical lightning current is calculated;
(3) according to the segmentation calculation formula of each phase conductor exposed range, in conjunction with different segmentation exposed ranges under corresponding it is upper, The critical amplitude of lightning current of lower limit calculates the shielding probability of flashover of each phase conductor.
Further, it is based on same tower double back transmission line EGM model, calculates the exposed range of each phase conductor, wherein upper phase The exposed range of conducting wire calculates
(1) situation 1: lightning current is smaller, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There is no intersection points, or deposit In intersection point P1And P1Point ordinate yP1The vertical tangent point S away from circle ⊙ S is hit less than ground wire1Ordinate yP1<yS1;It is mutually led in simultaneously Line is hit away from circle ⊙ C2It hits with upper phase conductor away from circle ⊙ C1Without intersection point, or there are intersection point P2And P2Point ordinate yP2Less than upper phase conductor It hits away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1;In addition it is hit over the ground away from rgLess than D1The ordinate r of pointg<yD1, i.e. yP1< yS1、yP2<yD1、rg<yD1When, upper phase conductor C1Exposed range Z11:
Z11=xD1-xS1=d1sinθ1+rC1-rs
In formula, xD1For D1Point abscissa, xS1For S1Point abscissa, d1For ⊙ S and ⊙ C1Distance, θ1For ⊙ S point vertical line with ⊙ S to ⊙ C1Between line angle, rc1For conducting wire C1Hit away from rsFor ground wire hit away from;
yP1<yS1、yP2<yD1、rg>yD1When, upper phase conductor C1Exposed range Z12:
In formula, xE1For E1Point abscissa, rgTo be hit over the ground away from hc1For conducting wire C1Distance away the ground;
(2) situation 2: lightning current is larger, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point Ordinate yP1Meet yP1>yS1;Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1Without intersection point, or there are intersection points P2And P2Point ordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1;In addition it is hit over the ground away from rgIt is small In D1Point ordinate rg<yD1, i.e. yP1>yS1、 yP2<yD1、rg<yD1When, upper phase conductor C1Exposed range Z13:
In formula, xP1For P1Point abscissa.
yP1>yS1、yP2<yD1、rg>yD1When, upper phase conductor C1Exposed range Z14:
In formula, xE1For E1Point abscissa;
(3) situation 3: lightning current is larger, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point Ordinate yP1Meet yP1<yS1;Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1There are intersection point P2And P2Point Ordinate yP2Greater than D1Point ordinate yP2>yD1, in addition hit over the ground away from rgLess than D1Point ordinate rg<yD1, i.e. yP1<yS1、yP2> yD1、rg<yD1When, upper phase conductor C1Exposed range Z15:
In formula, xP2For P2Point abscissa, θ2For ⊙ C1Point vertical line and ⊙ C1To ⊙ C2Between line angle, rc2For conducting wire C2 Hit away from d2For ⊙ C1With ⊙ C2Between distance;
yP1<yS1、yP2>yD1、rg>yP2When, upper phase conductor C1Exposed range Z16:
(4) situation 4: lightning current continues to increase, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point ordinate yP1Meet yP1>yS1;Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1There are intersection point P2And P2 Point ordinate yP2Greater than D1Point ordinate yP2>yD1;In addition it is hit over the ground away from rgLess than P2Point ordinate rg<yP2, i.e. yP1>yS1、yP2> yD1、rg<yP2When, upper phase conductor C1Exposed range Z17:
yP1>yS1、yP2>yD1、rg>yP2When, upper phase conductor C1Exposed range Z18:
Further, it is based on same tower double back transmission line EGM model, calculates the exposed range of each phase conductor, wherein middle phase The exposed range of conducting wire calculates
(1) situation 1: lightning current is smaller, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There is no intersection point, Or there are intersection point P2And P2Point ordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1;Together At present phase conductor is hit away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2Without intersection point, or there are intersection point P3And P3Point ordinate yP3It is less than Middle phase conductor is hit away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2;In addition it is hit over the ground away from rgLess than D2The ordinate r of pointg< yD2, i.e. yP2<yD1、yP3<yD2、rg<yD2When, middle phase conductor C2Exposed range Z21:
Z21=xD2-xD1=d2sinθ2+rC2-rC1
In formula, xD2For D2Point abscissa;
yP2<yD1、yP3<yD2、rg>yD2When, middle phase conductor C2Exposed range Z22:
In formula, xE2For E2Point abscissa, hc2For conducting wire C2Distance away the ground;
(2) situation 2: lightning current is larger, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point ordinate yP2Meet yP2>yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2Without intersection point, or exist Intersection point P3And P3Point ordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2;In addition it hits over the ground Away from rgLess than D2Point ordinate rg<yD2, i.e. yP2>yD1、yP3<yD2、rg<yD2When, middle phase conductor C2Exposed range Z23:
yP2>yD1、yP3<yD2、rg>yD2When, middle phase conductor C2Exposed range Z24:
(3) situation 3: lightning current is larger, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point ordinate yP2Meet yP2<yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2There are intersection point P3And P3 Point ordinate yP3Greater than D2Point ordinate yP3>yD2, in addition hit over the ground away from rgLess than D2Point ordinate rg<yD2, i.e. yP2<yD1、yP3> yD2、rg<yD2When, middle phase conductor C2Exposed range Z25:
In formula, xP3For P3Point abscissa, θ3For ⊙ C2Point vertical line and ⊙ C2To ⊙ C3Between line angle, rc3For conducting wire C3 Hit away from d3For ⊙ C2With ⊙ C3Between distance;
yP2<yD1、yP3>yD2、rg>yD2When, middle phase conductor C2Exposed range Z26:
In formula, xE2For E2Point abscissa;
(4) situation 4: lightning current continues to increase, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are friendships Point P2And P2Point ordinate yP2Meet yP2>yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2There are friendships Point P3And P3Point ordinate yP3Greater than D2Point ordinate yP3>yD2;In addition it is hit over the ground away from rgLess than P3Point ordinate rg<yP3, i.e. yP2> yD1、yP3>yD2、rg<yP3When, middle phase conductor C2Exposed range Z27:
In formula, xP3For P3Point abscissa;
yP2>yD1、yP3>yD2、rg>yP3When, middle phase conductor C2Exposed range Z28:
Further, it is based on same tower double back transmission line EGM model, calculates the exposed range of each phase conductor, wherein lower phase The exposed range of conducting wire calculates
(1) situation 1: lightning current is smaller, and middle phase conductor is hit away from circle ⊙ C2It hits with lower phase conductor away from circle ⊙ C3There is no intersection point, Or there are intersection point P3And P3Point ordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2; In addition it is hit over the ground away from rgIt hits less than lower phase conductor away from circle ⊙ C3Vertical tangent point D3Ordinate rg<yD3, i.e. yP3<yD2、rg<yD3 When, lower phase conductor C3Exposed range Z31:
Z31=xD3-xD2=d3sinθ3+rC3-rC2
In formula, xD3For D3Point abscissa, xD2For D2Point abscissa;
yP3<yD2、rg>yD3When, lower phase conductor C3Exposed range Z32:
In formula, xE3For E3Point abscissa, hc3For conducting wire C3Distance away the ground;
(2) situation 2: lightning current is larger, and middle phase conductor is hit away from circle ⊙ C2It hits with lower phase conductor away from circle ⊙ C3There are intersection point P3And P3Point ordinate yP3Meet yP3>yD2;In addition it is hit over the ground away from rgLess than D3Point ordinate rg<yD3, i.e. yP3>yD2、rg<yD3When, under Phase conductor C3Exposed range Z33:
In formula, xP3For P3Point abscissa;
yP3>yD2、rg>yD3When, lower phase conductor C3Exposed range Z34:
Further, according to the calculated result of exposed range, corresponding critical lightning current is calculated, comprising:
(1) the critical thunder and lightning stream calculation of phase conductor on:
Upper phase conductor C1One of critical lightning current IC11:
It solves equation and phase conductor C can be obtained1One of critical lightning current IC11
Upper phase conductor C1Another critical lightning current IC12:
It solves equation and phase conductor C can be obtained1Another critical lightning current IC12
Upper phase conductor C1Critical lightning current IC13:
rg=hC1
It solves equation to obtain phase conductor C1One of critical lightning current IC13
Upper phase conductor C1Critical lightning current IC14:
It solves equation and phase conductor C can be obtained1Another critical lightning current IC14
Upper phase conductor C1Maximum shielding lightning current IC1M1:
It solves equation and phase conductor C can be obtained1Maximum shielding lightning current IC1M1
Upper phase conductor C1Maximum shielding lightning current IC1M2:
It solves equation and phase conductor C can be obtained1Maximum shielding lightning current IC1M2
Upper phase conductor C1Maximum shielding lightning current IC1M3:
It solves equation and phase conductor C can be obtained1Maximum shielding lightning current IC1M3
(2) the critical thunder and lightning stream calculation of phase conductor in:
Middle phase conductor C2Critical lightning current IC21:
It solves equation and middle phase conductor C can be obtained2One of critical lightning current IC21
Middle phase conductor C2Critical lightning current IC22:
It solves equation and middle phase conductor C can be obtained2Another critical lightning current IC22
Middle phase conductor C2Critical lightning current IC23:
rg=hC2
It solves equation to obtain middle phase conductor C2One of critical lightning current IC23
Middle phase conductor C2Another critical lightning current IC24:
It solves equation and middle phase conductor C can be obtained2Another critical lightning current IC24
Middle phase conductor C2Maximum shielding lightning current IC2M1:
It solves equation and middle phase conductor C can be obtained2Maximum shielding lightning current IC2M1
Middle phase conductor C2Maximum shielding lightning current IC2M2:
It solves equation and middle phase conductor C can be obtained2Maximum shielding lightning current IC2M2
Middle phase conductor C2Maximum shielding lightning current IC2M3:
It solves equation and middle phase conductor C can be obtained2Maximum shielding lightning current IC2M3
(3) the critical thunder and lightning stream calculation of phase conductor under
Lower phase conductor C3Critical lightning current IC31:
It solves equation and lower phase conductor C can be obtained3One of critical lightning current IC31
Lower phase conductor C3One of critical lightning current IC32:
It solves equation and lower phase conductor C can be obtained3One of critical lightning current IC32
Lower phase conductor C3Maximum shielding lightning current IC3M1:
It solves equation and lower phase conductor C can be obtained3Maximum shielding lightning current IC3M1
Lower phase conductor C3Maximum shielding lightning current IC3M2:
It solves equation and lower phase conductor C can be obtained3Maximum shielding lightning current IC3M2
Lower phase conductor C3Maximum shielding lightning current IC3M3:
It solves equation and lower phase conductor C can be obtained3Maximum shielding lightning current IC3M3
Further, corresponding in conjunction with different segmentation exposed ranges according to the segmentation calculation formula of each phase conductor exposed range Under the critical amplitude of lightning current of upper and lower limit, calculate the shielding probability of flashover of each phase conductor, comprising:
(1) phase conductor shielding flashover strike on
According to the horizontal I of the resistance to thunder of shieldingcAnd upper each critical lightning current I of phase conductorC11、IC12、IC13、IC14Relative size and most Big shielding lightning current IC1M3, exposed range Z is respectively segmented to upper phase conductor in formula1The critical lightning current of the upper and lower limit of integral is determining and total Shielding flashover strike calculation formula is as follows:
1)IC<I<IC11<IC12<IC13When, upper phase conductor shielding flashover strike SFFOR11:
In formula, NgFor CG lightning density, p (I) is amplitude of lightning current cumulative probability density function;
IC<I<IC11<IC12、IC13<IC11When, upper phase conductor shielding flashover strike s 'FFOR11:
2)IC11<I<IC12<IC13When, upper phase conductor shielding flashover strike SFFOR12:
IC11<I<IC12, IC13<IC12When, upper phase conductor shielding flashover strike s 'FFOR12:
3)IC12<I<IC11<IC14When, upper phase conductor shielding flashover strike SFFOR13:
IC12<I<IC11, IC14<IC11When, upper phase conductor shielding flashover strike s 'FFOR13:
4)IC11<IC12When < I, upper phase conductor shielding flashover strike SFFOR14:
IC12<IC11When < I: upper phase conductor shielding flashover strike s 'FFOR14
The total shielding flashover strike calculation formula of upper phase conductor:
a)SFFORC1=SFFOR11+SFFOR12+SFFOR14
b)
c)
d)S”'FFORC1=SFFOR13+S'FFOR14
e)
IC<I<IC11<IC12, IC11>IC1M1, IC12>IC13When:
f)
IC<I<IC11<IC12, IC11>IC1M1, IC12<IC13When:
g)
Last integral upper limit beIC1M2When:
h) i)
(2) phase conductor shielding flashover strike in
1)IC<I<IC21<IC22<IC23When, middle phase conductor shielding flashover strike SFFOR21:
IC<I<IC21<IC22、IC23<IC21When, middle phase conductor shielding flashover strike s 'FFOR21:
2)IC21<I<IC22<IC23When, middle phase conductor shielding flashover strike SFFOR22:
IC21<I<IC22, IC23<IC22When, middle phase conductor shielding flashover strike s 'FFOR22:
3)IC22<I<IC21<IC24When, middle phase conductor shielding flashover strike SFFOR23:
IC22<I<IC21, IC24<IC21, middle phase conductor shielding flashover strike s 'FFOR23When:
4)IC21<IC22When < I, middle phase conductor shielding flashover strike SFFOR24:
IC22<IC21When < I, middle phase conductor shielding flashover strike s 'FFOR24:
The total shielding flashover strike calculation formula of middle phase conductor:
a)SFFORC2=SFFOR21+SFFOR22+SFFOR24
b)
c)
d)S”'FFORC2=SFFOR23+S'FFOR24
e)
IC<I<IC21<IC22, IC21>IC2M1, IC22>IC23When:
f)
IC<I<IC21<IC22, IC21>IC2M1, IC22<IC23When:
g)
Last integral upper limit beIC2M2When:
h) i)
(3) phase conductor shielding flashover strike under
1)IC<I<IC31<IC32When, lower phase conductor shielding flashover strike SFFOR31:
IC<I<IC32<IC31, lower phase conductor shielding flashover strike s 'FFOR31:
2)IC31<I<IC32When, lower phase conductor shielding flashover strike SFFOR32:
IC31<IC32When < I, lower phase conductor shielding flashover strike s 'FFOR32:
The total shielding flashover strike calculation formula of lower phase conductor:
a)SFFORC3=SFFOR31+SFFOR32+S'FFOR32
b)
IC31>IC32, IC31>IC3M1, IC3M1>IC32When:
c)
Last integral upper limit beIC3M2When:
d)
Compared with prior art, the beneficial effects of the present invention are:
(1) it is provided by the invention meter and conducting wire between shielding action multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis method, This method considers mutual shielding action between phase conductor in multiple-circuit on same tower in calculating, and it is sudden and violent to calculate conducting wire more accurately Dew distance, conducting wire analyze same tower in different exposed range lower critical lightning currents and conducting wire shielding flashover strike more fully hereinafter Double-circuit line Lightning performance improves and improves the considerations of multiple-circuit on same tower Lightning performance is analyzed range and accuracy.
(2) analysis method considers existing mutual shielding shielding action between conducting wire, establishes consideration phase conductor Between mutually shielding action multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis model, be to it is existing calculate multi-circuit lines on the same tower around Hit effective supplement of Lightning performance method.
(3) the transmission line of electricity shielding EGM analytic approach of the considerations of this method uses ground elevation, introduces in EGM and first imports The influence of firing angle, it is contemplated that the lightning stroke conducting wire actually occurred or ground, usually there are a clamps with vertical direction for lightning leader Angle, and only consider vertical incidence, still there is a phenomenon where shieldings for route when no method interpretation negative shielding angle, compared with conventional electrical geometry Model can more accurately reflect thunder and lightning and develop physical process.
Detailed description of the invention
Fig. 1 is multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis method flow chart of the invention.
Fig. 2 is same tower double back transmission line EGM model in the present invention.
Fig. 3 is that upper phase exposed range calculates schematic diagram under situation (1).
Fig. 4 is that upper phase exposed range calculates schematic diagram under situation (2).
Fig. 5 is that upper phase exposed range calculates schematic diagram under situation (3).
Fig. 6 is that upper phase exposed range calculates schematic diagram under situation (4).
Fig. 7 is that middle phase exposed range calculates schematic diagram under situation (1).
Fig. 8 is that middle phase exposed range calculates schematic diagram under situation (2).
Fig. 9 is that middle phase exposed range calculates schematic diagram under situation (3).
Figure 10 is that middle phase exposed range calculates schematic diagram under situation (4).
Figure 11 is that the lower phase exposed range of situation (1) calculates schematic diagram.
Figure 12 is that the lower phase exposed range of situation (2) calculates schematic diagram.
Figure 13 is upper phase maximum shielding thunder and lightning stream calculation schematic diagram.
Figure 14 is middle phase maximum shielding thunder and lightning stream calculation schematic diagram.
Figure 15 is lower phase maximum shielding thunder and lightning stream calculation schematic diagram.
Specific embodiment
With reference to the accompanying drawing and specific example is illustrated technical solution of the present invention.But the present invention should not only be limited Within the example ranges.
As shown in Figure 1, a kind of be used for multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis method.Analysis method is based on double with tower Based on the electric geometry method (as shown in Fig. 2) of loop line road Characteristic of Lightning Shielding Failure analysis, exist to conducting wire exposed range, conducting wire Different exposed range lower critical lightning currents, conducting wire shielding flashover strike are calculated.Based on formulaWherein SFFORCFor shielding probability of flashover, NgFor CG lightning density, IcmaxFor maximum shielding thunder Electric current, IcIt is exposed range for the resistance to Lei Shuiping of shielding, Z, p (I) is amplitude of lightning current cumulative probability density function.It is big by lightning current Small point of 4 kinds of situations analyze the multiple-circuit on same tower Characteristic of Lightning Shielding Failure of shielding action between meter and conducting wire, are respectively as follows: basic Steps are as follows:
(1) it is based on same tower double back transmission line EGM model, calculates the exposed range of each phase conductor;
(2) according to the calculated result of exposed range, corresponding critical lightning current is calculated;
(3) according to the segmentation calculation formula of each phase conductor exposed range, in conjunction with different segmentation exposed ranges under corresponding it is upper, The critical amplitude of lightning current of lower limit calculates the shielding probability of flashover of each phase conductor.
Each phase conductor exposed range is calculated for the first time.The present invention is according to each phase conductor relative position of multiple-circuit on same tower Relationship is divided into four kinds of situations away from radius of circle and striking distance factor to the exposed range of conducting wire according to hitting under different lightning current sizes It is calculated.
Upper phase conductor exposed range calculates.
According to each phase conductor relative positional relationship of multiple-circuit on same tower, upper phase conductor exposure arc is hit by ground wire away from circle, middle phase Conducting wire hits to hit away from circle and the earth and determine away from three, according to hitting away from radius of circle and striking distance factor under different lightning current sizes, upper phase The calculating of conducting wire exposed range is divided into following four situation:
(1) lightning current is smaller, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There is no intersection points, or there are intersection point P1 And P1Point ordinate yP1The vertical tangent point S away from circle ⊙ S is hit less than ground wire1Ordinate yP1<yS1;Simultaneously in phase conductor hit away from Circle ⊙ C2It hits with upper phase conductor away from circle ⊙ C1Without intersection point, or there are intersection point P2And P2Point ordinate yP2It hits less than upper phase conductor away from circle ⊙C1Vertical tangent point D1Ordinate yP2<yD1;In addition it hits over the ground and is less than D away from rg1Ordinate rg < y of pointD1, i.e. yP1<yS1、yP2< yD1、rg<yD1When (attached drawing 3 (a)), upper phase conductor C1Exposed range Z11:
Z11=xD1-xS1
Wherein, xD1=aC1+rC1=aS+d1sinθ1+rC1
xS1=aS+rS
Then: Z11=xD1-xS1=d1sinθ1+rC1-rs
Ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There is no intersection points, or there are intersection point P1And P1Point ordinate yP1The vertical tangent point S away from circle ⊙ S is hit less than ground wire1Ordinate yP1<yS1;Phase conductor is hit away from circle ⊙ C in simultaneously2It is led with upper phase Line is hit away from circle ⊙ C1Without intersection point, or there are intersection point P2And P2Point ordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1;In addition it is hit over the ground away from rgGreater than D1The ordinate r of pointg>yD1, i.e. yP1<yS1、yP2<yD1、rg>yD1When it is (attached Fig. 3 (b)), at this time in phase conductor C2With lower phase conductor C3Exposed range is zero, only upper phase conductor C1Exposure arc exists, upper phase conductor C1Exposed range Z12:
Z12=xE1-xS1
Wherein, E1Point hits for the earth away from rgIt hits with upper phase conductor away from circle ⊙ C1Intersection point and have:
By phase conductor C on Shi Ke get1Exposed range Z12:
(2) lightning current is larger, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point ordinate yP1Meet yP1>yS1;Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1Without intersection point, or there are intersection point P2And P2 Point ordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1;In addition it is hit over the ground away from rgLess than D1 Point ordinate rg<yD1, i.e. yP1>yS1、yP2<yD1、 rg<yD1When (attached drawing 4 (a)), upper phase conductor C1Exposed range Z13:
Z13=xD1-xP1
Simultaneous ground wire, which hits to hit away from circle ⊙ S equation and upper phase conductor, obtains equation group away from circle ⊙ C1 equation:
In formula, aC1=aS+d1sin θ 1, hC1=hS-d1cos θ 1.
For the solution procedure of reduced equation group, coordinate system as shown in the figure is translated, to aS unit length of right translation, HS unit length is translated up again, i.e., original coordinate origin is moved at ground wire S point, obtains P1 point abscissa in solution The abscissa xP1 of the P1 point in former coordinate system is obtained further according to coordinate system translation relation afterwards, it may be assumed that
In formula,
By phase conductor C on Shi Ke get1Exposed range Z13:
Ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point ordinate yP1Meet yP1>yS1; Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1Without intersection point, or there are intersection point P2And P2Point ordinate yP2It is small It hits in upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1;In addition it is hit over the ground away from rgGreater than D1Point ordinate rg>yD1, That is yP1>yS1、yP2<yD1、rg>yD1When (attached drawing 4 (b)), at this time in phase conductor C2With lower phase conductor C3Exposed range is zero, only on Phase conductor C1Exposure arc exists, upper phase conductor C1Exposed range Z14:
Z14=xE1-xP1
By phase conductor C on Shi Ke get1Exposed range Z14:
(3) lightning current is larger, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point ordinate yP1Meet yP1<yS1;Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1There are intersection point P2And P2Point ordinate yP2Greater than D1Point ordinate yP2>yD1, in addition hit over the ground away from rgLess than D1Point ordinate rg<yD1, i.e. yP1<yS1、yP2>yD1、rg<yD1 When (attached drawing 5 (a)), upper phase conductor C1Exposed range Z15:
Z15=xP2-xS1
Phase conductor is hit away from circle ⊙ C on simultaneous1Equation and middle phase conductor are hit away from circle ⊙ C2Equation obtains equation group:
In formula, aC2=aC1+d2sinθ2, hC2=hC1-d2cosθ2
It is similarly the solution procedure for simplifying above-mentioned equation group, coordinate system as shown in the figure is translated, to right translation aC1It is a Unit length, then translate up hC1Original coordinate origin is moved to upper phase conductor C by a unit length1At point, solving Obtain P2The P in former coordinate system is obtained further according to coordinate system translation relation after point abscissa2The abscissa x of pointP2, it may be assumed that
In formula,
By phase conductor C on Shi Ke get1Exposed range Z15:
Ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point ordinate yP1Meet yP1<yS1; Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1There are intersection point P2And P2Point ordinate yP2Greater than D1Point is vertical to be sat Mark yP2>yD1, in addition hit over the ground away from rgGreater than P2Point ordinate rg>yP2, i.e. yP1<yS1、yP2>yD1、rg>yP2When (attached drawing 5 (b)), this When in phase conductor C2With lower phase conductor C3Exposed range is zero, only upper phase conductor C1Exposure arc exists, upper phase conductor C1Exposed range Z16:
Z16=xE1-xS1
By phase conductor C on Shi Ke get1Exposed range Z16:
(4) lightning current continues to increase, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point is vertical Coordinate yP1Meet yP1>yS1;Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1There are intersection point P2And P2Point is vertical Coordinate yP2Greater than D1Point ordinate yP2>yD1;In addition it is hit over the ground away from rgLess than P2Point ordinate rg<yP2, i.e. yP1>yS1、yP2>yD1、 rg<yP2When (attached drawing 6 (a)), upper phase conductor C1Exposed range Z17:
Z17=xP2-xP1
By phase conductor C on Shi Ke get1Exposed range Z17:
When lightning current is sufficiently large, if being hit over the ground away from rgGreater than P2Point ordinate yP2, i.e. yP1>yS1、yP2>yD1、 rg>yP2 When (attached drawing 6 (b)), at this time in phase conductor C2With lower phase conductor C3Exposed range is zero, only upper phase conductor C1Exposure arc exists, on Phase conductor C1Exposed range Z18:
Z18=xE1-xP1
By phase conductor C on Shi Ke get1Exposed range Z18:
When being hit over the ground away from rgIt hits equal to ground wire and hits away from circle ⊙ S and upper phase conductor away from circle ⊙ C1Intersection point P1Ordinate yP1When, Corresponding lightning current is upper phase conductor C at this time1Maximum shielding lightning current IC1max, greater than the thunder of this electric current or hit lightning-arrest Line or the earth is hit, upper, middle and lower three-phase conducting wire is all not exposed to shielding.
The range of striking distance factor between zero and one, i.e., is hit over the ground and is hit conducting wire away from therefore Fig. 3 away from being less than under normal conditions (b), the case where Fig. 4 (b), Fig. 5 (b), Fig. 6 (b) less generation, unless tower structure is very special.
Middle phase conductor exposed range calculates.
Centering phase conductor, since distance is remote therewith for the relatively upper phase conductor of distance therewith for lightning conducter, middle phase conductor exposure arc It is hit to hit away from circle, lower phase conductor by upper phase conductor and hits and determined away from three away from circle and the earth, ibid phase conductor exposed range calculates, middle phase The calculating of conducting wire exposed range is also classified into following several situations:
(1) lightning current is smaller, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There is no intersection points, or exist Intersection point P2And P2Point ordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1;With phase at present Conducting wire is hit away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2Without intersection point, or there are intersection point P3And P3Point ordinate yP3It is led less than middle phase Line is hit away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2;In addition it is hit over the ground away from rgLess than D2The ordinate r of pointg<yD2, i.e. yP2< yD1、yP3<yD2、rg<yD2When (attached drawing 7 (a)), middle phase conductor C2Exposed range Z21:
Z21=xD2-xD1
xD2=aC2+rC2=aC1+d2sinθ2+rC2=aS+d1sinθ1+d2sinθ2+rC2
By phase conductor C on Shi Ke get2Exposed range Z21:
Z21=xD2-xD1=d2sinθ2+rC2-rC1
Upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There is no intersection points, or there are intersection point P2And P2Point is vertical Coordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1;It hits with phase conductor at present away from circle ⊙ C3 It hits with middle phase conductor away from circle ⊙ C2Without intersection point, or there are intersection point P3And P3Point ordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Lead Hang down tangent point D2Ordinate yP3<yD2;In addition it is hit over the ground away from rgGreater than D2The ordinate r of pointg>yD2, i.e. yP2<yD1、yP3<yD2、rg> yD2When (attached drawing 7 (b)), this phase conductor C at present3Exposed range is zero, middle phase conductor C2Exposed range Z22:
Z22=xE2-xD1
Wherein, E2Point hits for the earth away from rgIt hits with middle phase conductor away from circle ⊙ C2Intersection point and have:
By phase conductor C on Shi Ke get2Exposed range Z22:
(2) lightning current is larger, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point is vertical Coordinate yP2Meet yP2>yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2Without intersection point, or there are intersection points P3And P3Point ordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2;In addition it is hit over the ground away from rgIt is small In D2Point ordinate rg<yD2, i.e. yP2>yD1、yP3<yD2、 rg<yD2When (attached drawing 8 (a)), middle phase conductor C2Exposed range Z23:
Z23=xD2-xP2
Middle phase conductor C can be obtained by formula2Exposed range Z23:
Upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point ordinate yP2Meet yP2>yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2Without intersection point, or there are intersection point P3And P3Point is vertical to be sat Mark yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2;In addition it is hit over the ground away from rgGreater than D2Point is vertical to be sat Mark rg>yD2, i.e. yP2>yD1、yP3<yD2、rg>yD2When (attached drawing 8 (b)), this phase conductor C at present3Exposed range is zero, middle phase conductor C2Exposed range Z24:
Z24=xE2-xP2
Middle phase conductor C can be obtained by formula2Exposed range Z24:
(3) lightning current is larger, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point is vertical Coordinate yP2Meet yP2<yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2There are intersection point P3And P3Point is vertical Coordinate yP3Greater than D2Point ordinate yP3>yD2, in addition hit over the ground away from rgLess than D2Point ordinate rg<yD2, i.e. yP2<yD1、yP3>yD2、rg <yD2When (attached drawing 9 (a)), middle phase conductor C2Exposed range Z25:
Z25=xP3-xD1
Phase conductor is hit away from circle ⊙ C in simultaneous2Equation and lower phase conductor are hit away from circle ⊙ C3Equation obtains equation group:
In formula, aC3=aC2+d3sinθ3, hC3=hC2-d3cosθ3
It is similarly the solution for simplifying above-mentioned equation group, coordinate system as shown in the figure is translated, to right translation aC2A unit Length, then translate up hC2Original coordinate origin is moved to middle phase conductor C by a unit length2At point, obtained in solution P3The P in former coordinate system is obtained further according to coordinate system translation relation after point abscissa3The abscissa x of pointP3, it may be assumed that
In formula,
Middle phase conductor C can be obtained by formula2Exposed range Z25:
Upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point ordinate yP2Meet yP2<yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2There are intersection point P3And P3Point ordinate yP3Greater than D2 Point ordinate yP3>yD2, in addition hit over the ground away from rgGreater than D2Point ordinate rg>yD2, i.e. yP2<yD1、yP3>yD2、rg>yD2When (attached drawing 9 (b)), this phase conductor C at present3Exposed range is zero, middle phase conductor C2Exposed range Z26:
Z26=xE2-xD1
Middle phase conductor C can be obtained by formula2Exposed range Z26:
(4) lightning current continues to increase, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point ordinate yP2Meet yP2>yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2There are intersection point P3And P3 Point ordinate yP3Greater than D2Point ordinate yP3>yD2;In addition it is hit over the ground away from rgLess than P3Point ordinate rg<yP3, i.e. yP2>yD1、yP3> yD2、rg<yP3When (attached drawing 10 (a)), middle phase conductor C2Exposed range Z27:
Z27=xP3-xP2
Middle phase conductor C can be obtained by formula2Exposed range Z27:
When lightning current is sufficiently large, if being hit over the ground away from rgGreater than P3Point ordinate yP3, i.e. yP2>yD1、yP3>yD2、rg>yP3 When (attached drawing 10 (b)), this phase conductor C at present3Exposed range is zero, middle phase conductor C2Exposed range Z28:
Z28=xE2-xP2
Middle phase conductor C can be obtained by formula2Exposed range Z28:
Lower phase conductor exposed range calculates.
Lower phase conductor exposure arc is hit by middle phase conductor and is hit away from circle and the earth away from determining, lower phase conductor exposed range calculating is divided into Several situations below:
(1) lightning current is smaller, and middle phase conductor is hit away from circle ⊙ C2It hits with lower phase conductor away from circle ⊙ C3There is no intersection points, or exist Intersection point P3And P3Point ordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2;In addition right Ground is hit away from rgIt hits less than lower phase conductor away from circle ⊙ C3Vertical tangent point D3Ordinate rg<yD3, i.e. yP3<yD2、rg<yD3When it is (attached Figure 11 (a)), lower phase conductor C3Exposed range Z31:
Z31=xD3-xD2
xD3=aC3+rC3=aS+d1sinθ1+d2sinθ2+d3sinθ3+rC3
By phase conductor C under Shi Ke get3Exposed range Z31:
Z31=xD3-xD2=d3sinθ3+rC3-rC2
Middle phase conductor is hit away from circle ⊙ C2It hits with lower phase conductor away from circle ⊙ C3There is no intersection points, or there are intersection point P3And P3Point is vertical Coordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2;In addition it is hit over the ground away from rgUnder being greater than Phase conductor is hit away from circle ⊙ C3Vertical tangent point D3Ordinate rg>yD3, i.e. yP3<yD2、rg>yD3When (attached drawing 11 (b)), lower phase Conducting wire C3Exposed range Z32:
Z32=xE3-xD2
Wherein, E3Point hits for the earth away from rgIt hits with lower phase conductor away from circle ⊙ C3Intersection point and have:
By phase conductor C under Shi Ke get3Exposed range Z32:
(2) lightning current is larger, and middle phase conductor is hit away from circle ⊙ C2It hits with lower phase conductor away from circle ⊙ C3There are intersection point P3And P3Point is vertical Coordinate yP3Meet yP3>yD2;In addition it is hit over the ground away from rgLess than D3Point ordinate rg<yD3, i.e. yP3>yD2、rg<yD3When (attached drawing 12 (a)), lower phase conductor C3Exposed range Z33:
Z33=xD3-xP3
By phase conductor C under Shi Ke get3Exposed range Z33:
Middle phase conductor is hit away from circle ⊙ C2It hits with lower phase conductor away from circle ⊙ C3There are intersection point P3And P3Point ordinate yP3Meet yP3>yD2;In addition it is hit over the ground away from rgGreater than D3Point ordinate rg>yD3, i.e. yP3>yD2、rg>yD3When (attached drawing 12 (b)), lower phase conductor C3 Exposed range Z34:
Z34=xE3-xP3
By phase conductor C under Shi Ke get3Exposed range Z34:
Second, according to the calculated result of exposed range, calculates corresponding critical lightning current.
Upper phase conductor C1Critical thunder and lightning stream calculation is as follows:
(1) it is hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C when ground wire is hit1Intersection point P1The vertical away from circle ⊙ S is hit with ground wire to cut Line point S1It is upper phase conductor C when coincidence1Exposed range switch transition it is critical hit away from one of, it may be assumed that xP1=xS1When, it obtains:
Variable r in formulaSAnd rC1It is the function about amplitude of lightning current, therefore formula is substantially about amplitude of lightning current I Linear equation with one unknown, solve equation and phase conductor C can be obtained1One of critical lightning current IC11
(2) when upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2Intersection point P2It hits with upper phase conductor away from circle ⊙ C1Vertical tangent point D1It is upper phase conductor C when coincidence1The another of exposed range switch transition critical is hit away from, it may be assumed that xP2=xD1When, :
Variable r in formulaC1And rC2It is the function about amplitude of lightning current, formula is substantially one about amplitude of lightning current I First linear function solves equation and phase conductor C can be obtained1Another critical lightning current IC12
(3) phase conductor is hit away from circle ⊙ C in2It hits with upper phase conductor away from circle ⊙ C1Without intersection point, or there are intersection point P2And P2Point is vertical Coordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1When, i.e. yP2<yD1When, when hit over the ground away from rgIt hits with upper phase conductor away from circle ⊙ C1Intersection point E1With ⊙ C1Vertical tangent point D1It is upper phase conductor C when coincidence1Exposed range turns That changes another critical hits away from i.e. yE1=yD1When, have:
Solving equations obtain D1Point ordinate:
yD1=hC1
And yE1=rg
By Shi Ke get:
rg=hC1
Variable r in formulagFor the function about amplitude of lightning current, hC1For upper phase conductor C1Average height solves equation to obtain Phase conductor C1One of critical lightning current IC13
Phase conductor is hit away from circle ⊙ C in the middle2It hits with upper phase conductor away from circle ⊙ C1Intersection point P2Ordinate yP2Greater than upper phase conductor It hits away from circle ⊙ C1Vertical tangent point D1Ordinate yP2>yD1When, i.e. yP2>yD1When, when being hit over the ground away from rgIt hits with upper phase conductor away from circle ⊙ C1Intersection point E1It hits with middle phase conductor away from circle ⊙ C2It hits with upper phase conductor away from circle ⊙ C1Intersection point P2It is upper phase conductor C when coincidence1Cruelly Another critical the hitting away from i.e. x of dew distance conversionE1=xP2When, have:
Variable r in formulaC1、rC2And rgIt is the function about amplitude of lightning current, formula is substantially about amplitude of lightning current I's Linear equation with one unknown solves equation and phase conductor C can be obtained1Another critical lightning current IC14
(4) calculating of maximum shielding lightning current
It is hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C when ground wire is hit1There is no intersection points, or there are intersection point P1And P1Point ordinate yP1The vertical tangent point S away from circle ⊙ S is hit less than ground wire1Ordinate yP1<yS1When;Upper phase conductor is hit away from circle ⊙ C simultaneously1Level Tangent point B1Abscissa xB1The vertical tangent line away from circle ⊙ S is hit greater than ground wire to hit with upper phase conductor away from circle ⊙ C1Intersection point A1Cross Coordinate xB1>xA1That is yP1<yS1、xB1>xA1When (such as Figure 13 (a)), when being hit over the ground away from rgIt hits with upper phase conductor away from circle ⊙ C1Intersection point E1 It hits with upper phase conductor away from circle ⊙ C1Horizontal tangent point B1It is upper phase conductor C when coincidence1Maximum shielding lightning current, i.e. xE1=xB1 When, wherein xB1=aC1, have:
Variable r in formulaC1And rgIt is the function about amplitude of lightning current, formula is substantially one about amplitude of lightning current I First linear function solves equation and phase conductor C can be obtained1Maximum shielding lightning current IC1M1
It is hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C when ground wire is hit1There is no intersection points, or there are intersection point P1And P1Point is vertical Coordinate yP1The vertical tangent point S away from circle ⊙ S is hit less than ground wire1Ordinate yP1<yS1When;Upper phase conductor is hit away from circle ⊙ C simultaneously1's Horizontal tangent point B1Abscissa xB1The vertical tangent line away from circle ⊙ S is hit less than ground wire to hit with upper phase conductor away from circle ⊙ C1Intersection point A1 Abscissa xB1<xA1That is yP1<yS1、xB1<xA1When (such as Figure 13 (b)), when being hit over the ground away from rgIt hits with upper phase conductor away from circle ⊙ C1's Intersection point E1The vertical tangent line away from circle ⊙ S is hit with ground wire to hit with upper phase conductor away from circle ⊙ C1Intersection point A1It is upper phase conductor C when coincidence1 Maximum shielding lightning current, i.e. xE1=xA1When, wherein xA1=aS+rS, have:
Variable r in formulaC1、rSAnd rgIt is the function about amplitude of lightning current, formula is substantially about amplitude of lightning current I's Linear equation with one unknown solves equation and phase conductor C can be obtained1Maximum shielding lightning current IC1M2
It is hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C when ground wire is hit1There are intersection point P1And P1Point ordinate yP1Meet yP1> yS1, when being hit over the ground away from rgIt hits with upper phase conductor away from circle ⊙ C1Intersection point E1It hits with ground wire and hits away from circle ⊙ S and upper phase conductor away from circle ⊙ C1Intersection point P1It is upper phase conductor C when coincidence1Maximum shielding lightning current, i.e. xE1=xP1When, have:
Variable r in formulaC1、rgAnd rSFor the function about amplitude of lightning current, formula is substantially one about amplitude of lightning current I First linear function solves equation and phase conductor C can be obtained1Maximum shielding lightning current IC1M3
Middle phase conductor C2Critical thunder and lightning stream calculation is as follows:
(1) when upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2Intersection point P2It hits with upper phase conductor away from circle ⊙ C1Vertical tangent point D1It is overlapped Shi Weizhong phase conductor C2Exposed range switch transition it is critical hit away from one of, it may be assumed that xP2=xD1When, :
Variable r in formulaC1And rC2It is the function about amplitude of lightning current, therefore formula is substantially about amplitude of lightning current I Linear equation with one unknown, solve equation and middle phase conductor C can be obtained2One of critical lightning current IC21
(2) phase conductor is hit away from circle ⊙ C in2It hits with lower phase conductor away from circle ⊙ C3Intersection point P3It hits with middle phase conductor away from circle ⊙ C2Vertical tangent point D2It is overlapped Shi Weizhong phase conductor C2The another of exposed range switch transition critical is hit away from, it may be assumed that xP3=xD2When, It can obtain:
Similarly, the variable r in formulaC2And rC3It is the function about amplitude of lightning current, formula is substantially about amplitude of lightning current The linear equation with one unknown of I solves equation and middle phase conductor C can be obtained2Another critical lightning current IC22
(3) phase conductor is hit away from circle ⊙ C instantly3It hits with middle phase conductor away from circle ⊙ C2Without intersection point, or there are intersection point P3And P3Point is vertical Coordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2When, when being hit over the ground away from rgWith middle phase conductor It hits away from circle ⊙ C2Intersection point E2With ⊙ C2Vertical tangent point D2It is overlapped Shi Weizhong phase conductor C2Exposed range conversion it is critical hit away from, That is yE2=yD2When, have:
Solving equations obtain D2Point ordinate:
yD2=hC2
And yE2=rg
By Shi Ke get:
rg=hC2
Variable r in formulagFor the function about amplitude of lightning current, hC2For middle phase conductor C2Average height, solves equation to obtain Phase conductor C2One of critical lightning current IC23
Instantly phase conductor is hit away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2Intersection point P3Ordinate yP3Greater than middle phase conductor It hits away from circle ⊙ C2Vertical tangent point D2Ordinate yP3>yD2When, when being hit over the ground away from rgIt hits with middle phase conductor away from circle ⊙ C2Intersection point E2With Lower phase conductor is hit away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2Intersection point P3It is overlapped Shi Weizhong phase conductor C2Exposed range conversion Another critical hit away from i.e. xE2=xP3When, have:
Variable r in formulaC2、rC3And rgIt is the function about amplitude of lightning current, formula is substantially about amplitude of lightning current I's Linear equation with one unknown solves equation and middle phase conductor C can be obtained2Another critical lightning current IC24
(4) calculating of maximum shielding lightning current
When upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There is no intersection points, or there are intersection point P2And P2Point Ordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1When;Simultaneously in phase conductor hit away from Circle ⊙ C2Horizontal tangent point B2Abscissa xB2It hits greater than upper phase conductor away from circle ⊙ C1Vertical tangent line and middle phase conductor hit away from circle ⊙C2Intersection point A2Abscissa xB2>xA2, i.e. yP2<yD1、 xB2>xA2When (such as Figure 14 (a)), when being hit over the ground away from rgWith middle phase conductor It hits away from circle ⊙ C2Intersection point E2It hits with middle phase conductor away from circle ⊙ C2Horizontal tangent point B2It is overlapped Shi Weizhong phase conductor C2It is maximum around Hit lightning current, i.e. xE2=xB2When, wherein xB2=aC2, have:
Variable r in formulaC2And rgIt is the function about amplitude of lightning current, formula is substantially one about amplitude of lightning current I First linear function solves equation and middle phase conductor C can be obtained2Maximum shielding lightning current IC2M1
When upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There is no intersection points, or there are intersection point P2And P2 Point ordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1When;Phase conductor is hit in simultaneously Away from circle ⊙ C2Horizontal tangent point B2Abscissa xB2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent line and middle phase conductor hit away from Circle ⊙ C2Intersection point A2Abscissa xB2<xA2, i.e. yP2<yD1、 xB2<xA2When (such as Figure 14 (b)), when being hit over the ground away from rgIt is led with middle phase Line is hit away from circle ⊙ C2Intersection point E2It hits with upper phase conductor away from circle ⊙ C1Vertical tangent line and middle phase conductor hit away from circle ⊙ C2Intersection point A2 It is overlapped Shi Weizhong phase conductor C2Maximum shielding lightning current, i.e. xE2=xA2When, wherein xA2=aC1+rC1, have:
Variable r in formulaC1、rC2And rgIt is the function about amplitude of lightning current, formula is substantially about amplitude of lightning current I Linear equation with one unknown, solve equation and middle phase conductor C can be obtained2Maximum shielding lightning current IC2M2
When upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point ordinate yP2Meet yP2>yD1, when being hit over the ground away from rgIt hits with middle phase conductor away from circle ⊙ C2Intersection point E2It hits with upper phase conductor away from circle ⊙ C1It is hit with middle phase conductor Away from circle ⊙ C2Intersection point P2It is overlapped Shi Weizhong phase conductor C2Maximum shielding lightning current, i.e. xE2=xP2When, joint type has:
Variable r in formulaC1、rC2And rgFor the function about amplitude of lightning current, formula is substantially one about amplitude of lightning current I First linear function solves equation and middle phase conductor C can be obtained2Maximum shielding lightning current IC2M3
Lower phase conductor C3Critical thunder and lightning stream calculation is as follows:
(1) phase conductor is hit away from circle ⊙ C in2It hits with lower phase conductor away from circle ⊙ C3Intersection point P3It hits with middle phase conductor away from circle ⊙ C2Vertical tangent point D2It is lower phase conductor C when coincidence3Exposed range switch transition it is critical hit away from one of, it may be assumed that xP3=xD2When, It can obtain:
Variable r in formulaC2And rC3It is the function about amplitude of lightning current, therefore formula is substantially about amplitude of lightning current I Linear equation with one unknown, solve equation and lower phase conductor C can be obtained3One of critical lightning current IC31
(2) when being hit over the ground away from rgIt hits with lower phase conductor away from circle ⊙ C3Vertical tangent point D3It is lower phase conductor C when coincidence3Cruelly Reveal apart from switch transition it is critical hit away from one of, it may be assumed that xE3=xD3When, it obtains:
Variable r in formulaC3And rgIt is the function about amplitude of lightning current, therefore formula is substantially about amplitude of lightning current I Linear equation with one unknown, solve equation and lower phase conductor C can be obtained3One of critical lightning current IC32
(3) calculating of maximum shielding lightning current
Phase conductor is hit away from circle ⊙ C in the middle2It hits with lower phase conductor away from circle ⊙ C3There is no intersection points, or there are intersection point P3And P3Point Ordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2When;With phase conductor at present hit away from Circle ⊙ C3Horizontal tangent point B3Abscissa xB3It hits greater than middle phase conductor away from circle ⊙ C2Vertical tangent line and lower phase conductor hit away from circle ⊙C3Intersection point A3Abscissa xB3>xA3, i.e. yP3<yD2、 xB3>xA3When (such as Figure 15 (a)), when being hit over the ground away from rgWith lower phase conductor It hits away from circle ⊙ C3Intersection point E3It hits with lower phase conductor away from circle ⊙ C3Horizontal tangent point B3It is lower phase conductor C when coincidence3It is maximum around Hit lightning current, i.e. xE3=xB3When, wherein xB3=aC3, have:
Variable r in formulaC3And rgIt is the function about amplitude of lightning current, formula is substantially one about amplitude of lightning current I First linear function solves equation and lower phase conductor C can be obtained3Maximum shielding lightning current IC3M1
Phase conductor is hit away from circle ⊙ C in the middle2It hits with lower phase conductor away from circle ⊙ C3There is no intersection points, or there are intersection point P3And P3 Point ordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2When;It is hit with phase conductor at present Away from circle ⊙ C3Horizontal tangent point B3Abscissa xB3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent line and lower phase conductor hit away from Circle ⊙ C3Intersection point A3Abscissa xB3<xA3, i.e. yP3<yD2、 xB3<xA3When (such as Figure 15 (b)), when being hit over the ground away from rgIt is led with lower phase Line is hit away from circle ⊙ C3Intersection point E3It hits with middle phase conductor away from circle ⊙ C2Vertical tangent line and lower phase conductor hit away from circle ⊙ C3Intersection point A3 It is lower phase conductor C when coincidence3Maximum shielding lightning current, i.e. xE3=xA3When, wherein xA3=aC2+rC2, have:
Variable r in formulaC2、rC3And rgIt is the function about amplitude of lightning current, formula is substantially about amplitude of lightning current I's Linear equation with one unknown solves equation and lower phase conductor C can be obtained3Maximum shielding lightning current IC3M2
Phase conductor is hit away from circle ⊙ C in the middle2It hits with lower phase conductor away from circle ⊙ C3There are intersection point P3And P3Point ordinate yP3Meet yP3>yD2, when being hit over the ground away from rgIt hits with lower phase conductor away from circle ⊙ C3Intersection point E3It hits with middle phase conductor away from circle ⊙ C2It is hit with lower phase conductor Away from circle ⊙ C3Intersection point P3It is lower phase conductor C when coincidence3Maximum shielding lightning current, i.e. xE3=xP3When, have:
Variable r in formulaC2、rC3And rgFor the function about amplitude of lightning current, formula is substantially one about amplitude of lightning current I First linear function solves equation and lower phase conductor C can be obtained3Maximum shielding lightning current IC3M3
Third is the calculating of each phase conductor shielding flashover strike.
The calculating of upper phase conductor shielding flashover strike.
According to the horizontal I of the resistance to thunder of shieldingcAnd upper each critical lightning current I of phase conductorC11、IC12、IC13、IC14Relative size and most Big shielding lightning current IC1M3, exposed range Z is respectively segmented to upper phase conductor in formula1The critical lightning current of the upper and lower limit of integral is determining and total Shielding flashover strike calculation formula is as follows.
In conjunction with different type shaft tower lightning conducter S, upper phase conductor C1, middle phase conductor C2And the relative position between the earth Relationship successively dodges shielding in different critical lightning current section according to the sequence that minimum shielding thunder and lightning flows to maximum shielding lightning current The expression formula addition of network rate can must go up the total shielding flashover strike calculation formula of phase conductor:
a)SFFORC1=SFFOR11+SFFOR12+SFFOR14
b)
c)
d)S”'FFORC1=SFFOR13+S'FFOR14
e)
With reference to attached drawing 13 (a), IC<I<IC11<IC12, IC11>IC1M1, IC12>IC13When:
f)
IC<I<IC11<IC12, IC11>IC1M1, IC12<IC13When:
g)
If upper phase conductor C1It respectively hits away from shown in such as attached drawing 13 (b) of position, then the upper limit of last integral is in formulaIC1M2, That is:
h) i)
The calculating of middle phase conductor shielding flashover strike.
According to the horizontal I of the resistance to thunder of shieldingcAnd middle each critical lightning current I of phase conductorC21、IC22、IC123、IC24Relative size and most Big shielding lightning current IC2M3, centering phase conductor is respectively segmented exposed range Z in formula2The critical lightning current of the upper and lower limit of integral is determining and total Shielding flashover strike calculation formula is as follows.
In conjunction with phase conductor C on different type shaft tower1, middle phase conductor C2, lower phase conductor C3And the opposite position between the earth Relationship is set, the sequence of maximum shielding lightning current is flowed to successively by shielding in different critical lightning current section according to minimum shielding thunder and lightning The expression formula addition of flashover strike can obtain the total shielding flashover strike calculation formula of middle phase conductor:
a)SFFORC2=SFFOR21+SFFOR22+SFFOR24
b)
c)
d)S”'FFORC2=SFFOR23+S'FFOR24
e)
With reference to Figure 14 (a), IC<I<IC21<IC22, IC21>IC2M1, IC22>IC23When:
f)
IC<I<IC21<IC22, IC21>IC2M1, IC22<IC23When:
g)
If middle phase conductor C2It respectively hits away from shown in such as Figure 14 (b) of position, then the upper limit of last integral is in formulaIC2M2, it may be assumed that
h) i)
The calculating of lower phase conductor shielding flashover strike.
According to the horizontal I of the resistance to thunder of shieldingcAnd lower each critical lightning current I of phase conductorC31、IC32Relative size and maximum shielding thunder Electric current IC3M3, exposed range Z is respectively segmented to lower phase conductor in formula3The determining and total shielding flashover of the critical lightning current of the upper and lower limit of integral Rate calculation formula is as follows.
In conjunction with phase conductor C in different type shaft tower2, lower phase conductor C3And the relative positional relationship between the earth three, according to Minimum shielding thunder and lightning flows to the sequence of maximum shielding lightning current successively by the table of shielding flashover strike in different critical lightning current section The shielding flashover strike calculation formula that phase conductor can must be descended total is added up to formula:
a)SFFORC3=SFFOR31+SFFOR32+S'FFOR32
b)
With reference to Figure 15 (a), IC31>IC32, IC31>IC3M1, IC3M1>IC32When:
c)
If lower phase conductor C3It respectively hits away from shown in such as Figure 15 (b) of position, then the upper limit of last integral is in formulaIC3M2, it may be assumed that
d)
The total shielding flashover strike of route can be obtained according to formula after obtaining each phase conductor shielding flashover strike.
The above embodiments are only used to illustrate and not limit the technical solutions of the present invention, although above-described embodiment to the present invention into Gone detailed description, the related technical personnel of this field it is understood that can modify to the present invention or replace on an equal basis, but Any modification and part replacement for not departing from spirit and scope of the invention should all be covered in scope of the presently claimed invention.

Claims (6)

1. the multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis method of shielding action between meter and conducting wire, which is characterized in that based on same The electric geometry method of tower double-circuit line Characteristic of Lightning Shielding Failure analysis, to conducting wire exposed range, conducting wire under different exposed ranges Critical lightning current, conducting wire shielding flashover strike are calculated, and formula is based onWherein SFFORCFor Shielding probability of flashover, NgFor CG lightning density, IcmaxFor maximum shielding lightning current, IcIt is exposed range, p for the resistance to Lei Shuiping of shielding, Z (I) be amplitude of lightning current cumulative probability density function, by lightning current size divide 4 kinds of situations to based on and between conducting wire shielding action it is same Tower double-circuit line Characteristic of Lightning Shielding Failure is analyzed, and the analysis method includes:
(1) it is based on same tower double back transmission line EGM model, calculates the exposed range of each phase conductor;
(2) according to the calculated result of exposed range, corresponding critical lightning current is calculated;
(3) according to the segmentation calculation formula of each phase conductor exposed range, in conjunction with upper and lower limit of the different segmentation exposed ranges under corresponding Critical amplitude of lightning current calculates the shielding probability of flashover of each phase conductor.
2. the multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis side of shielding action between meter according to claim 1 and conducting wire Method, which is characterized in that be based on same tower double back transmission line EGM model, calculate the exposed range of each phase conductor, wherein upper phase conductor Exposed range calculating include:
(1) situation 1: lightning current is smaller, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There is no intersection points, or there are intersection points P1And P1Point ordinate yP1The vertical tangent point S away from circle ⊙ S is hit less than ground wire1Ordinate yP1<yS1;Simultaneously in phase conductor hit away from Circle ⊙ C2It hits with upper phase conductor away from circle ⊙ C1Without intersection point, or there are intersection point P2And P2Point ordinate yP2It hits less than upper phase conductor away from circle ⊙C1Vertical tangent point D1Ordinate yP2<yD1;In addition it is hit over the ground away from rgLess than D1The ordinate r of pointg<yD1, i.e. yP1<yS1、yP2< yD1、rg<yD1When, upper phase conductor C1Exposed range Z11:
Z11=xD1-xS1=d1sinθ1+rC1-rs
In formula, xD1For D1Point abscissa, xS1For S1Point abscissa, d1For ⊙ S and ⊙ C1Distance, θ1For ⊙ S point vertical line and ⊙ S To ⊙ C1Between line angle, rc1For conducting wire C1Hit away from rsFor ground wire hit away from;
yP1<yS1、yP2<yD1、rg>yD1When, upper phase conductor C1Exposed range Z12:
In formula, xE1For E1Point abscissa, rgTo be hit over the ground away from hc1For conducting wire C1Distance away the ground;
(2) situation 2: lightning current is larger, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point is vertical to be sat Mark yP1Meet yP1>yS1;Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1Without intersection point, or there are intersection point P2And P2Point ordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1;In addition it is hit over the ground away from rgLess than D1 Point ordinate rg<yD1, i.e. yP1>yS1、yP2<yD1、rg<yD1When, upper phase conductor C1Exposed range Z13:
In formula, xP1For P1Point abscissa.
yP1>yS1、yP2<yD1、rg>yD1When, upper phase conductor C1Exposed range Z14:
In formula, xE1For E1Point abscissa;
(3) situation 3: lightning current is larger, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point is vertical to be sat Mark yP1Meet yP1<yS1;Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1There are intersection point P2And P2Point is vertical to be sat Mark yP2Greater than D1Point ordinate yP2>yD1, in addition hit over the ground away from rgLess than D1Point ordinate rg<yD1, i.e. yP1<yS1、yP2>yD1、rg< yD1When, upper phase conductor C1Exposed range Z15:
In formula, xP2For P2Point abscissa, θ2For ⊙ C1Point vertical line and ⊙ C1To ⊙ C2Between line angle, rc2For conducting wire C2Hit Away from d2For ⊙ C1With ⊙ C2Between distance;
yP1<yS1、yP2>yD1、rg>yP2When, upper phase conductor C1Exposed range Z16:
(4) situation 4: lightning current continues to increase, and ground wire, which is hit, to be hit away from circle ⊙ S and upper phase conductor away from circle ⊙ C1There are intersection point P1And P1Point Ordinate yP1Meet yP1>yS1;Phase conductor is hit away from circle ⊙ C in simultaneously2It hits with upper phase conductor away from circle ⊙ C1There are intersection point P2And P2Point Ordinate yP2Greater than D1Point ordinate yP2>yD1;In addition it is hit over the ground away from rgLess than P2Point ordinate rg<yP2, i.e. yP1>yS1、yP2>yD1、 rg<yP2When, upper phase conductor C1Exposed range Z17:
yP1>yS1、yP2>yD1、rg>yP2When, upper phase conductor C1Exposed range Z18:
3. the multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis side of shielding action between meter according to claim 1 and conducting wire Method, which is characterized in that be based on same tower double back transmission line EGM model, calculate the exposed range of each phase conductor, wherein middle phase conductor Exposed range calculating include:
(1) situation 1: lightning current is smaller, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There is no intersection points, or deposit In intersection point P2And P2Point ordinate yP2It hits less than upper phase conductor away from circle ⊙ C1Vertical tangent point D1Ordinate yP2<yD1;With at present Phase conductor is hit away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2Without intersection point, or there are intersection point P3And P3Point ordinate yP3Less than middle phase Conducting wire is hit away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2;In addition it is hit over the ground away from rgLess than D2The ordinate r of pointg<yD2, i.e., yP2<yD1、yP3<yD2、rg<yD2When, middle phase conductor C2Exposed range Z21:
Z21=xD2-xD1=d2sinθ2+rC2-rC1
In formula, xD2For D2Point abscissa;
yP2<yD1、yP3<yD2、rg>yD2When, middle phase conductor C2Exposed range Z22:
In formula, xE2For E2Point abscissa, hc2For conducting wire C2Distance away the ground;
(2) situation 2: lightning current is larger, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point Ordinate yP2Meet yP2>yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2Without intersection point, or there are intersection points P3And P3Point ordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2;In addition it is hit over the ground away from rgIt is small In D2Point ordinate rg<yD2, i.e. yP2>yD1、yP3<yD2、rg<yD2When, middle phase conductor C2Exposed range Z23:
yP2>yD1、yP3<yD2、rg>yD2When, middle phase conductor C2Exposed range Z24:
(3) situation 3: lightning current is larger, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point Ordinate yP2Meet yP2<yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2There are intersection point P3And P3Point Ordinate yP3Greater than D2Point ordinate yP3>yD2, in addition hit over the ground away from rgLess than D2Point ordinate rg<yD2, i.e. yP2<yD1、yP3>yD2、 rg<yD2When, middle phase conductor C2Exposed range Z25:
In formula, xP3For P3Point abscissa, θ3For ⊙ C2Point vertical line and ⊙ C2To ⊙ C3Between line angle, rc3For conducting wire C3Hit Away from d3For ⊙ C2With ⊙ C3Between distance;
yP2<yD1、yP3>yD2、rg>yD2When, middle phase conductor C2Exposed range Z26:
In formula, xE2For E2Point abscissa;
(4) situation 4: lightning current continues to increase, and upper phase conductor is hit away from circle ⊙ C1It hits with middle phase conductor away from circle ⊙ C2There are intersection point P2And P2Point ordinate yP2Meet yP2>yD1;It hits with phase conductor at present away from circle ⊙ C3It hits with middle phase conductor away from circle ⊙ C2There are intersection point P3And P3 Point ordinate yP3Greater than D2Point ordinate yP3>yD2;In addition it is hit over the ground away from rgLess than P3Point ordinate rg<yP3, i.e. yP2>yD1、yP3> yD2、rg<yP3When, middle phase conductor C2Exposed range Z27:
In formula, xP3For P3Point abscissa;
yP2>yD1、yP3>yD2、rg>yP3When, middle phase conductor C2Exposed range Z28:
4. the multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis side of shielding action between meter according to claim 1 and conducting wire Method, which is characterized in that be based on same tower double back transmission line EGM model, calculate the exposed range of each phase conductor, wherein lower phase conductor Exposed range calculating include:
(1) situation 1: lightning current is smaller, and middle phase conductor is hit away from circle ⊙ C2It hits with lower phase conductor away from circle ⊙ C3There is no intersection points, or deposit In intersection point P3And P3Point ordinate yP3It hits less than middle phase conductor away from circle ⊙ C2Vertical tangent point D2Ordinate yP3<yD2;In addition It is hit over the ground away from rgIt hits less than lower phase conductor away from circle ⊙ C3Vertical tangent point D3Ordinate rg<yD3, i.e. yP3<yD2、rg<yD3When, Lower phase conductor C3Exposed range Z31:
Z31=xD3-xD2=d3sinθ3+rC3-rC2
In formula, xD3For D3Point abscissa, xD2For D2Point abscissa;
yP3<yD2、rg>yD3When, lower phase conductor C3Exposed range Z32:
In formula, xE3For E3Point abscissa, hc3For conducting wire C3Distance away the ground;
(2) situation 2: lightning current is larger, and middle phase conductor is hit away from circle ⊙ C2It hits with lower phase conductor away from circle ⊙ C3There are intersection point P3And P3Point Ordinate yP3Meet yP3>yD2;In addition it is hit over the ground away from rgLess than D3Point ordinate rg<yD3, i.e. yP3>yD2、rg<yD3When, lower phase conductor C3Exposed range Z33:
In formula, xP3For P3Point abscissa;
yP3>yD2、rg>yD3When, lower phase conductor C3Exposed range Z34:
5. according to the resistance to thunder of multiple-circuit on same tower shielding of shielding action between the described in any item meters of claim 2~4 and conducting wire Energy analysis method, which is characterized in that according to the calculated result of exposed range, calculate corresponding critical lightning current, comprising:
(1) the critical thunder and lightning stream calculation of phase conductor on:
Upper phase conductor C1One of critical lightning current IC11:
It solves equation and phase conductor C can be obtained1One of critical lightning current IC11
Upper phase conductor C1Another critical lightning current IC12:
It solves equation and phase conductor C can be obtained1Another critical lightning current IC12
Upper phase conductor C1Critical lightning current IC13:
rg=hC1
It solves equation to obtain phase conductor C1One of critical lightning current IC13
Upper phase conductor C1Critical lightning current IC14:
It solves equation and phase conductor C can be obtained1Another critical lightning current IC14
Upper phase conductor C1Maximum shielding lightning current IC1M1:
It solves equation and phase conductor C can be obtained1Maximum shielding lightning current IC1M1
Upper phase conductor C1Maximum shielding lightning current IC1M2:
It solves equation and phase conductor C can be obtained1Maximum shielding lightning current IC1M2
Upper phase conductor C1Maximum shielding lightning current IC1M3:
It solves equation and phase conductor C can be obtained1Maximum shielding lightning current IC1M3
(2) the critical thunder and lightning stream calculation of phase conductor in:
Middle phase conductor C2Critical lightning current IC21:
It solves equation and middle phase conductor C can be obtained2One of critical lightning current IC21
Middle phase conductor C2Critical lightning current IC22:
It solves equation and middle phase conductor C can be obtained2Another critical lightning current IC22
Middle phase conductor C2Critical lightning current IC23:
rg=hC2
It solves equation to obtain middle phase conductor C2One of critical lightning current IC23
Middle phase conductor C2Another critical lightning current IC24:
It solves equation and middle phase conductor C can be obtained2Another critical lightning current IC24
Middle phase conductor C2Maximum shielding lightning current IC2M1:
It solves equation and middle phase conductor C can be obtained2Maximum shielding lightning current IC2M1
Middle phase conductor C2Maximum shielding lightning current IC2M2:
It solves equation and middle phase conductor C can be obtained2Maximum shielding lightning current IC2M2
Middle phase conductor C2Maximum shielding lightning current IC2M3:
It solves equation and middle phase conductor C can be obtained2Maximum shielding lightning current IC2M3
(3) the critical thunder and lightning stream calculation of phase conductor under
Lower phase conductor C3Critical lightning current IC31:
It solves equation and lower phase conductor C can be obtained3One of critical lightning current IC31
Lower phase conductor C3One of critical lightning current IC32:
It solves equation and lower phase conductor C can be obtained3One of critical lightning current IC32
Lower phase conductor C3Maximum shielding lightning current IC3M1:
It solves equation and lower phase conductor C can be obtained3Maximum shielding lightning current IC3M1
Lower phase conductor C3Maximum shielding lightning current IC3M2:
It solves equation and lower phase conductor C can be obtained3Maximum shielding lightning current IC3M2
Lower phase conductor C3Maximum shielding lightning current IC3M3:
It solves equation and lower phase conductor C can be obtained3Maximum shielding lightning current IC3M3
6. the multiple-circuit on same tower Characteristic of Lightning Shielding Failure analysis side of shielding action between meter according to claim 5 and conducting wire Method, which is characterized in that according to the segmentation calculation formula of each phase conductor exposed range, under being corresponded in conjunction with different segmentation exposed ranges The critical amplitude of lightning current of upper and lower limit calculates the shielding probability of flashover of each phase conductor, comprising:
(1) phase conductor shielding flashover strike on
According to the horizontal I of the resistance to thunder of shieldingcAnd upper each critical lightning current I of phase conductorC11、IC12、IC13、IC14Relative size and it is maximum around Hit lightning current IC1M3, exposed range Z is respectively segmented to upper phase conductor in formula1The critical lightning current determination of the upper and lower limit of integral and total shielding Flashover strike calculation formula is as follows:
1)IC<I<IC11<IC12<IC13When, upper phase conductor shielding flashover strike SFFOR11:
In formula, NgFor CG lightning density, p (I) is amplitude of lightning current cumulative probability density function;
IC<I<IC11<IC12、IC13<IC11When, upper phase conductor shielding flashover strike s 'FFOR11:
2)IC11<I<IC12<IC13When, upper phase conductor shielding flashover strike SFFOR12:
IC11<I<IC12, IC13<IC12When, upper phase conductor shielding flashover strike s 'FFOR12:
3)IC12<I<IC11<IC14When, upper phase conductor shielding flashover strike SFFOR13:
IC12<I<IC11, IC14<IC11When, upper phase conductor shielding flashover strike s 'FFOR13:
4)IC11<IC12When < I, upper phase conductor shielding flashover strike SFFOR14:
IC12<IC11When < I: upper phase conductor shielding flashover strike s 'FFOR14
The total shielding flashover strike calculation formula of upper phase conductor:
a)SFFORC1=SFFOR11+SFFOR12+SFFOR14
b)
c)
d)S'FFORC1=SFFOR13+S'FFOR14
e)
IC<I<IC11<IC12, IC11>IC1M1, IC12>IC13When:
f)
IC<I<IC11<IC12, IC11>IC1M1, IC12<IC13When:
g)
Last integral upper limit beIC1M2When:
h)i)
(2) phase conductor shielding flashover strike in
1)IC<I<IC21<IC22<IC23When, middle phase conductor shielding flashover strike SFFOR21:
IC<I<IC21<IC22、IC23<IC21When, middle phase conductor shielding flashover strike s 'FFOR21:
2)IC21<I<IC22<IC23When, middle phase conductor shielding flashover strike SFFOR22:
IC21<I<IC22, IC23<IC22When, middle phase conductor shielding flashover strike s 'FFOR22:
3)IC22<I<IC21<IC24When, middle phase conductor shielding flashover strike SFFOR23:
IC22<I<IC21, IC24<IC21, middle phase conductor shielding flashover strike s 'FFOR23When:
4)IC21<IC22When < I, middle phase conductor shielding flashover strike SFFOR24:
IC22<IC21When < I, middle phase conductor shielding flashover strike s 'FFOR24:
The total shielding flashover strike calculation formula of middle phase conductor:
a)SFFORC2=SFFOR21+SFFOR22+SFFOR24
b)
c)
d)S'FFORC2=SFFOR23+S'FFOR24
e)
IC<I<IC21<IC22, IC21>IC2M1, IC22>IC23When:
f)
IC<I<IC21<IC22, IC21>IC2M1, IC22<IC23When:
g)
Last integral upper limit beIC2M2When:
h)i)
(3) phase conductor shielding flashover strike under
1)IC<I<IC31<IC32When, lower phase conductor shielding flashover strike SFFOR31:
IC<I<IC32<IC31, lower phase conductor shielding flashover strike s 'FFOR31:
2)IC31<I<IC32When, lower phase conductor shielding flashover strike SFFOR32:
IC31<IC32When < I, lower phase conductor shielding flashover strike s 'FFOR32:
The total shielding flashover strike calculation formula of lower phase conductor:
a)SFFORC3=SFFOR31+SFFOR32+S'FFOR32
b)
IC31>IC32, IC31>IC3M1, IC3M1>IC32When:
c)
Last integral upper limit beIC3M2When:
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CN110687371B (en) * 2019-09-24 2023-01-31 中国电力科学研究院有限公司 Method and system for determining lightning shielding failure performance of same-tower multi-circuit line
CN112785117A (en) * 2020-12-18 2021-05-11 国网浙江省电力有限公司台州供电公司 Multidimensional analysis method for risk of full-line lightning shielding failure tripping of power transmission line

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