CN105921525A - Correction method for tail of strip of continuous rolling unit - Google Patents
Correction method for tail of strip of continuous rolling unit Download PDFInfo
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- CN105921525A CN105921525A CN201610291957.5A CN201610291957A CN105921525A CN 105921525 A CN105921525 A CN 105921525A CN 201610291957 A CN201610291957 A CN 201610291957A CN 105921525 A CN105921525 A CN 105921525A
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- B—PERFORMING OPERATIONS; TRANSPORTING
- B21—MECHANICAL METAL-WORKING WITHOUT ESSENTIALLY REMOVING MATERIAL; PUNCHING METAL
- B21B—ROLLING OF METAL
- B21B38/00—Methods or devices for measuring, detecting or monitoring specially adapted for metal-rolling mills, e.g. position detection, inspection of the product
- B21B38/10—Methods or devices for measuring, detecting or monitoring specially adapted for metal-rolling mills, e.g. position detection, inspection of the product for measuring roll-gap, e.g. pass indicators
- B21B38/105—Calibrating or presetting roll-gap
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- B—PERFORMING OPERATIONS; TRANSPORTING
- B21—MECHANICAL METAL-WORKING WITHOUT ESSENTIALLY REMOVING MATERIAL; PUNCHING METAL
- B21B—ROLLING OF METAL
- B21B37/00—Control devices or methods specially adapted for metal-rolling mills or the work produced thereby
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Abstract
The invention discloses a correction method for the tail of a strip of a continuous rolling unit, and relates to the technical field of metal pressure machining. The method comprises the following steps that a start signal of a strip tail correction program is set, and the strip tail correction program is started when a metal detector arranged at an inlet of the continuous rolling unit detects the tail of an intermediate billet rolled piece; the difference value of roll gaps on the double sides of a second rack of the continuous rolling unit is calculated and corrected; the difference value of roll gaps on the double sides of each of the rest of racks of the continuous rolling unit is calculated and corrected; and self-learning is carried out on the correction factor of the correction value of the difference value of the roll gaps on the double sides of each rack. The correction method solves the problems that in tail lateral bending correction in the existing intermediate billet rolling process, lagging and instability exist, and consequently the correction effect is poor.
Description
Technical field
The present invention relates to metal-pressed machine technical field, the band afterbody method for correcting error of a kind of Continuous mill train.
Background technology
In the production process of coils of hot rolled, on a big mill, plate ingot was rolled into certain thickness centre before this
Base, then be sent to Continuous mill train and be disposably rolled into coiled material.During rolling intermediate blank, affected by various factors, middle
Base there will be lateral bending in various degree, the camber being i.e. commonly called as.When carrying out tandem rolling, if the lateral bending being not for intermediate blank is carried out
Control, then can cause the head of coiled material and afterbody that staggered floor defect occurs.Current production scene be typically operative employee under observation between
After the lateral bending situation of base, the bilateral roll gap difference by adjusting frame is rectified a deviation, but manual operation exists hysteresis quality and unstability,
Rectifying effect is poor.
Summary of the invention
It is an object of the invention to provide the band afterbody method for correcting error of a kind of Continuous mill train, this method can solve existing in
Between afterbody lateral bending correction in the base operation of rolling, exist delayed and unstable, the problem causing rectifying effect difference.
In order to solve the problems referred to above, the technical solution used in the present invention is: the band afterbody method for correcting error of this Continuous mill train
Comprise the following steps:
A, the enabling signal of setting band afterbody correction program, when the metal detector being arranged in Continuous mill train porch detects centre
Band afterbody correction program is started during the afterbody of base rolled piece;
B, calculate and revise Continuous mill train the second frame bilateral roll gap difference: gather and be arranged in first between the first frame and the second frame
Mill drive side and the tension force actual value data of fore side measured by tonometry roller and be arranged in the second frame and the 3rd frame
Between the mill drive side measured by the second tonometry roller and the tension force actual value data of fore side, calculate the second frame bilateral roller
The correction of seam difference, revises the second frame bilateral roll gap;
C, calculate and revise Continuous mill train residue frame bilateral roll gap difference: when band from through correction the second frame roll gap dish out,
And when marching to the pressure tap of tonometry roller, gather the second tonometry roller being arranged between the second frame and the 3rd frame and surveyed
Amount mill drive side and the tension force actual value data of fore side and be arranged between the 3rd frame and the 4th frame the 3rd tension force survey
Measure the mill drive side measured by roller and the tension force actual value data of fore side, calculate the correction of the bilateral roll gap difference of the 3rd frame
Amount, revises the 3rd frame bilateral roll gap;By that analogy, calculate and revise the bilateral roll gap remaining each frame;
D, correction factor to frame bilateral roll gap difference correction carry out self study.
In the technical scheme of the band afterbody method for correcting error of above-mentioned Continuous mill train, more specifically technical scheme is it may also is that walk
The method of the enabling signal that rapid A sets intermediate blank rolled piece afterbody correction program is as follows:
By the metal detector being arranged in Continuous mill train porch, the tail position of intermediate blank rolled piece is detected, the peace of metal detector
Holding position is 20000≤D≤50000 with the span of distance D of Continuous mill train first roller seam, and the length of intermediate blank is big
In D, therefore in early stage and the mid-term of continuous rolling process, the signal of metal detector is always 1, shows to detect that intermediate blank is rolled
Part is by the detection position of metal detector, when the afterbody of intermediate blank rolled piece leaves the detection position of metal detector, and gold
The signal belonging to detector is become 0 from 1, shows the afterbody test point by metal detector of intermediate blank rolled piece, i.e. examines when metal
When survey device detects trailing edge signal, send the enabling signal of intermediate blank rolled piece afterbody correction program to PLC system, show out
Begin to carry out the correction of intermediate blank rolled piece afterbody to control.
Further, step B calculates and the concrete grammar of correction Continuous mill train the second frame bilateral roll gap difference is as follows: false
If Continuous mill train total frame number is N;Second frame transmission side roll gap is S2d, unit is millimeter;Second gantry operation side roller seam
For S2o, unit is millimeter;Roll gap difference Q of the second frame2=S2d-S2o, unit is millimeter;
When PLC system receives the enabling signal of intermediate blank rolled piece afterbody correction program, first between the first frame and the second frame
The meansigma methods of 10~30 transmission side tension force actual values that tonometry roller records continuously is T1d, unit is ton;First frame and
The meansigma methods of 10~30 fore side tension force actual values that the first tonometry roller between the second frame records continuously is T1o, unit
For ton;After measurement terminates, calculate the bilateral tension force actual value measured by the first tonometry roller between the first frame and the second frame
Difference R of meansigma methods1For:
R1=T1d-T1o
Unit is ton;
If calculating R1Absolute value more than 1 ton hour, it was demonstrated that there is sideslip situation in the afterbody of intermediate blank, then according to R1Numerical value to
The roll gap difference of two frames is modified;The correction assuming the second frame roll gap difference is q2, unit is millimeter, it is assumed that
q2>=0, the correction factor of the second frame roll gap difference correction is k2, k2Initial value be 1, the second breast roll after being corrected
Seam difference Q2'=Q2+q2, unit is millimeter;
The difference of the meansigma methods of the roll gap difference correction of the second frame and the bilateral tension force actual value measured by the first tonometry roller
Corresponding relation as shown in the table:
After completing above-mentioned calculating, PLC system control the second machine frame rolling mill transmission side and roll gap difference is repaiied by fore side hydraulic cylinder
Just to Q2′。
Further, step C calculates and the concrete grammar of correction Continuous mill train residue frame bilateral roll gap difference is as follows:
After completing the correction of the bilateral roll gap difference of the n-th frame, it is assumed that 2≤n≤N-1, start to calculate and repair through roll gap difference
After just, the strip material portion that rolled marches to be experienced during the pressure tap of the n-th tonometry roller between the n-th frame and the (n+1)th frame
Time tn, unit is the second;
Assume between the n-th frame and the (n+1)th frame that the transmission side tension force actual value measured by the n-th tonometry roller is Tnd, unit is
Ton;The fore side tension force actual value that n-th frame and the (n+1)th interstand tension are measured measured by roller is Tno, unit is ton, wherein
n≤N;Now, it is assumed that the (n+1)th frame transmission side roll gap is S(n+1)d, unit is millimeter;(n+1)th gantry operation side roller seam is
S(n+1)o, unit is millimeter;Roll gap difference Q of the (n+1)th framen+1=S(n+1)d-S(n+1)o, unit is millimeter;Assume the n-th frame
Mill speed be Vn, unit is mm/second;Advancing slip value is wn;N-th rack outlet window of web velocities is vn, unit be millimeter/
Second, then vnCalculating formula is:
vn=Vn(1+wn)
At the roll gap of known n-th frame, the distance of pressure tap to the n-th tonometry roller is G, then tn=G/vn, therefore, when
After completing the correction of the bilateral roll gap difference of the n-th frame, through tnStart after Miao to gather between the n-th frame and the (n+1)th frame
Bilateral tension force actual value measured by tonometry roller;Within the cycle of PLC system reception instrument detection data is 100 milliseconds,
Assume the average of 20 transmission side tension force actual values that now between the n-th frame and the (n+1)th frame, the n-th tonometry roller records continuously
Value is Tnd, unit is ton;20 fore side tension force that between the n-th frame and the (n+1)th frame, the n-th tonometry roller records continuously
The meansigma methods of actual value is Tno, unit is ton, then difference R of two meansigma methodssnFor:
Rn=Tnd-Tno
Unit is ton;
If difference RnAbsolute value more than 1 ton hour, it was demonstrated that the afterbody of intermediate blank is after the bilateral roll gap difference correction of the n-th frame
Yet suffer from sideslip situation, then according to difference RnNumerical value the roll gap difference of the (n+1)th frame is modified;Assume (n+1)th
The correction of frame roll gap difference is qn+1, unit is millimeter, it is assumed that qn+1>=0, repairing of the (n+1)th frame roll gap difference correction
Positive coefficient is kn+1;Roll gap difference Q after being correctedn′+1=Qn+1+qn+1, unit is millimeter;
The roll gap difference correction of the (n+1)th frame is corresponding with the difference of the bilateral tension force actual value measured by the n-th tonometry roller
Relation is as shown in the table:
After completing above-mentioned calculating, PLC system control the (n+1)th machine frame rolling mill transmission side and fore side hydraulic cylinder by roll gap difference
Revise to Qn′+1。
Further, the method that step D carries out self study to the correction factor of frame bilateral roll gap difference correction is as follows:
After the afterbody completing one piece of intermediate blank is rectified a deviation, available R1, R2, R3…RN-1Ordered series of numbers, this ordered series of numbers is carried out
Search, when finding following two situation, need to learn by oneself the correction factor of the bilateral roll gap difference correction of the (n+1)th frame
Practise:
(1) R is worked asn<-1 and Rn+1During > 1;
The explanation of this kind of situation, transmission side warp tension ratio fore side measured by the n-th tonometry roller between the n-th frame and the (n+1)th frame
Tension force is little, and difference is more than 1 ton, and the band between the i.e. n-th frame and the (n+1)th frame exists lateral bending, and lateral bending direction is operation
Side, after the bilateral roll gap difference revising the (n+1)th frame, the (n+1)th tonometry roller between the (n+1)th frame and the n-th+2 frame
Measured transmission side warp tension ratio fore side tension force is more than more than 1 ton, and the band between the i.e. (n+1)th frame and the n-th+2 frame is deposited
At lateral bending, and lateral bending direction is transmission side, and this shows, when revising the bilateral roll gap difference of the (n+1)th frame, to there is accommodative excess
Phenomenon, make the lateral bending direction of band be changed into transmission side from fore side, i.e. qn+1Absolute value excessive, can by revise system
Number kn+1Carry out self study to reduce qn+1Value, and by the correction factor k after self studyn′+1For the calculating of next block intermediate blank,
kn′+1Calculating formula be:
(2) R is worked asn> 1 and Rn+1During <-1;
The explanation of this kind of situation, transmission side warp tension ratio fore side tension force measured by the n-th tonometry roller between the n-th frame and the (n+1)th frame
More than more than 1 ton, there is lateral bending in the band between the i.e. n-th frame and the (n+1)th frame, and lateral bending direction is transmission side;Through repairing
After the bilateral roll gap difference of positive (n+1)th frame, biography measured by the (n+1)th tonometry roller between the (n+1)th frame and the n-th+2 frame
Dynamic side warp tension ratio fore side tension force is little, and difference is more than 1 ton, and the band between the i.e. (n+1)th frame and the n-th+2 frame exists side
Curved, and lateral bending direction is fore side, this shows, when revising the bilateral roll gap difference of the (n+1)th frame, to there is showing of accommodative excess
As, make the lateral bending direction of band be changed into fore side from transmission side, i.e. qn+1Absolute value excessive, can be by correction factor
kn+1Carry out self study to reduce qn+1Value, and by the correction factor k after self studyn′+1For the calculating of next block intermediate blank, kn′+1
Calculating formula identical with formula (1).
Owing to have employed technique scheme, the present invention compared with prior art has the advantages that the company of being capable of
During rolling, the correction of band afterbody controls, and corrects the afterbody deflection of supplied materials rolled piece, and correction is timely, stable, and rectifying effect is good.
Accompanying drawing explanation
Fig. 1 is the schematic diagram that roller measurement tension force measured by the band of afterbody deflection at the first and second interstand tensions.
Detailed description of the invention
The invention will be further described for embodiment below in conjunction with the accompanying drawings:
As it is shown in figure 1, installed the metal detector 6 for measuring band afterbody before the first frame 1 of Continuous mill train, first
Between frame 1 and the second frame 2, first tonometry roller 3 is installed;First tonometry roller 3 has transmission side pressure tap 4 He
Fore side pressure tap 5;D is the horizontal range of metal detector the 6 to the first frame 1 roll axis, and unit is millimeter;G
For arriving the horizontal range of the pressure tap of tonometry roller thereafter at each frame roll gap, unit is millimeter.
The present invention considers when intermediate blank rolled piece is rolling to soon finish up at Continuous mill train, by being arranged in Continuous mill train porch
Metal detector the tail position of intermediate blank rolled piece is detected, when afterbody intermediate blank rolled piece being detected passes through metal detection
During the detection position of device, send the enabling signal of intermediate blank rolled piece afterbody correction program to PLC system, in showing to proceed by
Between the correction of base rolled piece afterbody control, milling train measured by the tonometry roller being now arranged between the first frame and the second frame passes
Move side and the tension force actual value data of fore side and the milling train measured by tonometry roller being arranged between the second frame and the 3rd frame
The tension force actual value data of transmission side and fore side are transferred to computer by data collecting system and process, and these two groups of numerical value are turned
Turn to the correction of the bilateral roll gap difference of the second frame.When band is dished out from the second frame roll gap through revising, and march to
During the pressure tap of tonometry roller, the mill drive side measured by tonometry roller that will be arranged between the second frame and the 3rd frame
And the tension force actual value data of fore side and the mill drive measured by tonometry roller that is arranged between the 3rd frame and the 4th frame
The tension force actual value data of side and fore side are transferred to computer by data collecting system and process, and these two groups of numerical value are converted into
The correction of the bilateral roll gap difference of the 3rd frame.By that analogy, until obtaining the correction of the bilateral roll gap difference of end frame,
Thus reach the purpose that band dish afterbody is rectified a deviation.More detailed step is as follows:
Step A: set the enabling signal of band afterbody correction program
When intermediate blank is rolling to soon finish up at Continuous mill train, intermediate blank is rolled the metal detector being arranged in Continuous mill train porch
The tail position of part detects, and the installation site of metal detector should be with reality with distance D that Continuous mill train first roller stitches
During rolling intermediate blank rolled piece afterbody glance off part length equal, i.e. need the intermediate blank rolled piece tail length carrying out rectifying a deviation,
This length is determined by the Side Bend Control level of the roughing mill of cogging, if the Side Bend Control level of roughing mill is higher, then and this length
Can be a smaller value, otherwise be a higher value, the span of this value be 20000≤D≤50000.The length one of intermediate blank
As more than D, be therefore always 1 in the early stage of continuous rolling process and the signal of metal detector in mid-term, show intermediate blank to be detected
Rolled piece is by the detection position of metal detector, when the afterbody of intermediate blank rolled piece leaves the detection position of metal detector,
The signal of metal detector is become 0 from 1, shows the afterbody test point by metal detector of intermediate blank rolled piece, i.e. works as metal
When detector detects trailing edge signal, send the enabling signal of intermediate blank rolled piece afterbody correction program to PLC system, show
Proceed by the correction of intermediate blank rolled piece afterbody to control.
Step B: calculate the correction of Continuous mill train the second frame bilateral roll gap difference
Assume that Continuous mill train total frame number is N=4;Second frame transmission side roll gap is S2d=23.05 millimeters;Second gantry operation side
Roll gap is S2o=23.24 millimeters;Roll gap difference Q of the second frame2=S2d-S2o=23.05-23.24=-0.19 millimeter;
When PLC system receives the enabling signal of intermediate blank rolled piece afterbody correction program, the first frame and the second interstand tension are surveyed
The meansigma methods of 20 transmission side tension force actual values that amount roller records continuously is T1d=16 tons;First frame and the second interstand tension
The meansigma methods measuring 20 fore side tension force actual values that roller records continuously is T1o=22 tons.After measurement terminates, calculate the first machine
Frame and the second interstand tension measure difference R of the meansigma methods of the bilateral tension force actual value measured by roller1For:
R1=T1d-T1o=16-22=-6 ton
Calculated R1Absolute value more than 1 ton, it was demonstrated that there is sideslip situation in the afterbody of intermediate blank, then according to R1Numerical value to the second frame
Roll gap difference be modified.It is noted that aborning in application, transmission side that tonometry roller records continuously or behaviour
The number scope making side tension force actual value can be 10~30.The correction assuming the second frame roll gap difference is q2, unit is
Millimeter, it is assumed that q2>=0, the correction factor of the second frame roll gap difference correction is k2, k2Initial value be 1.After being corrected
Roll gap difference Q2'=Q2+q2, unit is millimeter;
The roll gap difference correction of the second frame is right with the difference of the meansigma methods of the bilateral tension force actual value measured by the first tonometry roller
Should be related to as shown in table 1:
Table 1
Due to R1=-6 tons, inquiry table 1 understands q2=0.2k2=0.2, therefore Q2'=Q2+q2=-0.19+0.2=0.01 millimeter.Complete
After becoming above-mentioned calculating, PLC system control the second machine frame rolling mill transmission side and fore side hydraulic cylinder by roll gap difference correction extremely
Q2'=0.01 millimeter.
Step C: calculate the correction of Continuous mill train residue frame bilateral roll gap difference
The most respectively the correction of the third and fourth frame bilateral roll gap difference is calculated:
(1) correction of the 3rd frame bilateral roll gap difference is calculated
After completing the correction of the bilateral roll gap difference of the second frame, start to calculate the strip material portion rolled after roll gap difference correction
March to the time t experienced during the pressure tap of the second frame and the 3rd interstand tension measurement roller2, unit is the second;
Now, it is assumed that the 3rd frame transmission side roll gap is S3d=15.52 millimeters;3rd gantry operation side roller seam is S3o=15.71 millimeters;
Roll gap difference Q of the 3rd frame3=S3d-S3o=15.52-15.64=-0.12 millimeter.The mill speed assuming the second frame is
Vn=3000 mm/second;Advancing slip value is wn=0.043;Second rack outlet window of web velocities is vn, unit is mm/second, then
vnCalculating formula is:
vn=Vn(1+wn)=3000 × (1+0.043)=3129 mm/second
Measure the distance G=1200 millimeter of the pressure tap of roller to the second frame and the 3rd interstand tension at the roll gap of known second frame.
Then tn=G/vn=1200/3129=0.384 the second.Therefore, after completing the correction of the bilateral roll gap difference of the second frame, pass through
Start to gather the second frame after 0.384 second and the 3rd interstand tension measures the bilateral tension force actual value measured by roller.Assume this
Time the second frame and the 3rd interstand tension to measure the meansigma methods of 20 transmission side tension force actual values that roller records continuously be T2d=21
Ton;Second frame and the 3rd interstand tension measure the meansigma methods of 20 fore side tension force actual values that roller records continuously
T2o=17 tons.Then difference R of two meansigma methodss2For:
R2=T2d-T2o=21-17=4 ton
Due to R2Absolute value more than 1 ton, it was demonstrated that the afterbody of intermediate blank is still deposited after the bilateral roll gap difference correction of the second frame
In sideslip situation, then according to difference R2Numerical value the roll gap difference of the 3rd frame is modified.Assume that the 3rd frame roll gap is poor
The correction of value is q3, unit is millimeter, it is assumed that q3>=0, the correction factor of the 3rd frame roll gap difference correction is k3, its
Initial value design is k3=1.Roll gap difference Q after being corrected3'=Q3+q3, unit is millimeter;
The corresponding relation of the difference of the roll gap difference correction of the (n+1)th frame and the bilateral tension force actual value measured by the n-th tonometry roller
As shown in table 2:
Table 2
Due to R2=4 tons, therefore tabling look-up 2 can obtain:
Then Q3'=-0.12+ (-0.033)=-0.153 millimeter.After completing above-mentioned calculating, PLC system control the 3rd machine frame rolling mill transmission
Side and fore side hydraulic cylinder are by roll gap difference correction to Q3'=-0.153 millimeter.
(2) correction of the 4th frame bilateral roll gap difference is calculated
When, after the correction of the bilateral roll gap difference completed the 3rd frame, starting to calculate the strip material portion rolled after roll gap difference correction
March to the time t experienced during the pressure tap of the 3rd frame and the 4th interstand tension measurement roller3, unit is the second.
Now, it is assumed that the 4th frame transmission side roll gap is S4d=12.32 millimeters;4th gantry operation side roller seam is S3o=12.41 millimeters;
Roll gap difference Q of the 4th frame4=S4d-S4o=12.32-12.41=-0.09 millimeter.The mill speed assuming the 3rd frame is
V3=4000 mm/second;Advancing slip value is w3=0.057;3rd rack outlet window of web velocities is v3, unit is mm/second, then v3
Calculating formula is:
v3=V3(1+w3)=4000 × (1+0.057)=4228 mm/second
Measure the distance G=1200 millimeter of the pressure tap of roller to the 3rd frame and the 4th interstand tension at the roll gap of known 3rd frame.
Then tn=G/vn=1200/4228=0.284 the second.Therefore, when, after the correction of the bilateral roll gap difference completed the 3rd frame, passing through
Start to gather the 4th frame after 0.284 second and the 4th interstand tension measures the bilateral tension force actual value measured by roller.Assume this
Time the 3rd frame and the 4th interstand tension to measure the meansigma methods of 20 transmission side tension force actual values that roller records continuously be T3d=19
Ton;3rd frame and the 4th interstand tension measure the meansigma methods of 20 fore side tension force actual values that roller records continuously
T3o=21 tons.Then difference R of two meansigma methodss3For:
R3=T3d-T3o=19-21=-2 ton
Due to R3Absolute value more than 1 ton, it was demonstrated that the afterbody of intermediate blank yet suffers from after the bilateral roll gap difference correction of the 3rd frame
Sideslip situation, then according to difference R3Numerical value the roll gap difference of the 4th frame is modified.Assume the 4th frame roll gap difference
Correction is q4, unit is millimeter, it is assumed that q4>=0, the correction factor of the 3rd frame roll gap difference correction is k4, its initial value
It is set as k4=1.Roll gap difference Q after being corrected4'=Q4+q4, unit is millimeter.
Due to R3=-2 tons, therefore tabling look-up 2 can obtain:
Then Q4'=-0.09+0.025=-0.065 millimeter.After completing above-mentioned calculating, PLC system control the 3rd machine frame rolling mill transmission side
And fore side hydraulic cylinder is by roll gap difference correction to Q4'=-0.065 millimeter.
Step D: the self study of the correction factor of roll gap difference correction
After the afterbody completing this block intermediate blank is rectified a deviation, available R1=-6, R2=4, R3=-2, carry out following to this ordered series of numbers
The search of two kinds of situations:
(1) R is worked asn<-1 and Rn+1During > 1;
By R1And R2Numerical value understand, R1<-1 and R2> 1, meets the condition of this situation.The explanation of this kind of situation, the first frame and the
Between two frames, the transmission side warp tension ratio fore side tension force measured by the first tonometry roller is little, and difference is more than 1 ton, the i.e. first machine
There is lateral bending in the band between frame and the second frame, and lateral bending direction is fore side.Through revising the bilateral roll gap difference of the second frame
After, big more than 1 ton of transmission side warp tension ratio fore side tension force measured by the second tonometry roller between the second frame and the 3rd frame,
There is lateral bending in the band between the i.e. second frame and the 3rd frame, and lateral bending direction is transmission side.This shows revising the second frame
During bilateral roll gap difference, there is the phenomenon of accommodative excess, make the lateral bending direction of band be changed into transmission side from fore side, i.e. q2's
Absolute value is excessive.Can be by correction factor k2Carry out self study to reduce q2Value, and by the correction factor k after self study2' use
Calculating in next block intermediate blank.k2' calculating formula be:
(2) R is worked asn> 1 and Rn+1During <-1;
By R1And R2Numerical value understand, R2> 1 and R3<-1, meets the condition of this situation.The explanation of this kind of situation, the second frame and the
Three interstand tensions measure big more than 1 ton of transmission side warp tension ratio fore side tension force measured by roller, the i.e. second frame and the 3rd frame
Between band there is lateral bending, and lateral bending direction is transmission side.After revising the bilateral roll gap difference of the 3rd frame, the 3rd frame
Little with the transmission side warp tension ratio fore side tension force that the 4th interstand tension is measured measured by roller, and difference is more than 1 ton, the i.e. the 3rd machine
There is lateral bending in the band between frame and the 4th frame, and lateral bending direction is fore side.This shows at the bilateral roll gap revising the 3rd frame
During difference, there is the phenomenon of accommodative excess, make the lateral bending direction of band be changed into fore side from transmission side, i.e. q3Absolute value mistake
Greatly.Can be by correction factor k3Carry out self study to reduce q3Value, and by the correction factor k after self study3' for next block
The calculating of intermediate blank.k3' calculating formula be:
Claims (5)
1. the band afterbody method for correcting error of a Continuous mill train, it is characterised in that comprise the following steps:
A, the enabling signal of setting band afterbody correction program, when the metal detector being arranged in Continuous mill train porch detects centre
Band afterbody correction program is started during the afterbody of base rolled piece;
B, calculate and revise Continuous mill train the second frame bilateral roll gap difference: gather and be arranged in first between the first frame and the second frame
Mill drive side and the tension force actual value data of fore side measured by tonometry roller and be arranged in the second frame and the 3rd frame
Between the mill drive side measured by the second tonometry roller and the tension force actual value data of fore side, calculate the second frame bilateral roller
The correction of seam difference, revises the second frame bilateral roll gap;
C, calculate and revise Continuous mill train residue frame bilateral roll gap difference: when band from through correction the second frame roll gap dish out,
And when marching to the pressure tap of tonometry roller, gather the second tonometry roller being arranged between the second frame and the 3rd frame and surveyed
Amount mill drive side and the tension force actual value data of fore side and be arranged between the 3rd frame and the 4th frame the 3rd tension force survey
Measure the mill drive side measured by roller and the tension force actual value data of fore side, calculate the correction of the bilateral roll gap difference of the 3rd frame
Amount, revises the 3rd frame bilateral roll gap;By that analogy, calculate and revise the bilateral roll gap remaining each frame;
D, correction factor to frame bilateral roll gap difference correction carry out self study.
The band afterbody method for correcting error of Continuous mill train the most according to claim 1, it is characterised in that: step A sets intermediate blank
The method of the enabling signal of rolled piece afterbody correction program is as follows:
By the metal detector being arranged in Continuous mill train porch, the tail position of intermediate blank rolled piece is detected, metal detector
The span of distance D of installation site and Continuous mill train first roller seam be 20000≤D≤50000, the length of intermediate blank
Degree is more than D, and therefore in early stage and the mid-term of continuous rolling process, the signal of metal detector is always 1, shows centre to be detected
Base rolled piece is by the detection position of metal detector, when the afterbody of intermediate blank rolled piece leaves the detection position of metal detector
Time, the signal of metal detector is become 0 from 1, shows the afterbody test point by metal detector of intermediate blank rolled piece, i.e. when
When metal detector detects trailing edge signal, send the enabling signal of intermediate blank rolled piece afterbody correction program to PLC system,
Show that proceeding by the correction of intermediate blank rolled piece afterbody controls.
The band afterbody method for correcting error of Continuous mill train the most according to claim 1 and 2, it is characterised in that: step B calculate and
The concrete grammar revising Continuous mill train the second frame bilateral roll gap difference is as follows:
Assume that Continuous mill train total frame number is N;Second frame transmission side roll gap is S2d, unit is millimeter;Second gantry operation
Side roller seam is S2o, unit is millimeter;Roll gap difference Q of the second frame2=S2d-S2o, unit is millimeter;
When PLC system receives the enabling signal of intermediate blank rolled piece afterbody correction program, first between the first frame and the second frame
The meansigma methods of 10~30 transmission side tension force actual values that tonometry roller records continuously is T1d, unit is ton;First frame and
The meansigma methods of 10~30 fore side tension force actual values that the first tonometry roller between the second frame records continuously is T1o, unit
For ton;After measurement terminates, calculate the bilateral tension force actual value measured by the first tonometry roller between the first frame and the second frame
Difference R of meansigma methods1For:
R1=T1d-T1o
Unit is ton;
If calculating R1Absolute value more than 1 ton hour, it was demonstrated that there is sideslip situation in the afterbody of intermediate blank, then according to R1Numerical value to
The roll gap difference of two frames is modified;The correction assuming the second frame roll gap difference is q2, unit is millimeter, it is assumed that
q2>=0, the correction factor of the second frame roll gap difference correction is k2, k2Initial value be 1, the second breast roll after being corrected
Seam difference Q2'=Q2+q2, unit is millimeter;
The difference of the meansigma methods of the roll gap difference correction of the second frame and the bilateral tension force actual value measured by the first tonometry roller
Corresponding relation as shown in the table:
After completing above-mentioned calculating, PLC system control the second machine frame rolling mill transmission side and roll gap difference is repaiied by fore side hydraulic cylinder
Just to Q '2。
The band afterbody method for correcting error of Continuous mill train the most according to claim 3, it is characterised in that: step C calculates and revises
The concrete grammar of Continuous mill train residue frame bilateral roll gap difference is as follows:
After completing the correction of the bilateral roll gap difference of the n-th frame, it is assumed that 2≤n≤N-1, start to calculate and repair through roll gap difference
After just, the strip material portion that rolled marches to be experienced during the pressure tap of the n-th tonometry roller between the n-th frame and the (n+1)th frame
Time tn, unit is the second;
Assume between the n-th frame and the (n+1)th frame that the transmission side tension force actual value measured by the n-th tonometry roller is Tnd, unit is
Ton;The fore side tension force actual value that n-th frame and the (n+1)th interstand tension are measured measured by roller is Tno, unit is ton, wherein
n≤N;Now, it is assumed that the (n+1)th frame transmission side roll gap is S(n+1)d, unit is millimeter;(n+1)th gantry operation side roller seam is
S(n+1)o, unit is millimeter;Roll gap difference Q of the (n+1)th framen+1=S(n+1)d-S(n+1)o, unit is millimeter;Assume the n-th frame
Mill speed be Vn, unit is mm/second;Advancing slip value is wn;N-th rack outlet window of web velocities is vn, unit be millimeter/
Second, then vnCalculating formula is:
vn=Vn(1+wn)
At the roll gap of known n-th frame, the distance of pressure tap to the n-th tonometry roller is G, then tn=G/vn, therefore, when
After completing the correction of the bilateral roll gap difference of the n-th frame, through tnStart after Miao to gather between the n-th frame and the (n+1)th frame
Bilateral tension force actual value measured by tonometry roller;Within the cycle of PLC system reception instrument detection data is 100 milliseconds,
Assume the average of 20 transmission side tension force actual values that now between the n-th frame and the (n+1)th frame, the n-th tonometry roller records continuously
Value is Tnd, unit is ton;20 fore side tension force that between the n-th frame and the (n+1)th frame, the n-th tonometry roller records continuously
The meansigma methods of actual value is Tno, unit is ton, then difference R of two meansigma methodssnFor:
Rn=Tnd-Tno
Unit is ton;
If difference RnAbsolute value more than 1 ton hour, it was demonstrated that the afterbody of intermediate blank is after the bilateral roll gap difference correction of the n-th frame
Yet suffer from sideslip situation, then according to difference RnNumerical value the roll gap difference of the (n+1)th frame is modified;Assume (n+1)th
The correction of frame roll gap difference is qn+1, unit is millimeter, it is assumed that qn+1>=0, repairing of the (n+1)th frame roll gap difference correction
Positive coefficient is kn+1;Roll gap difference Q after being correctedn′+1=Qn+1+qn+1, unit is millimeter;
The roll gap difference correction of the (n+1)th frame is corresponding with the difference of the bilateral tension force actual value measured by the n-th tonometry roller
Relation is as shown in the table:
After completing above-mentioned calculating, PLC system control the (n+1)th machine frame rolling mill transmission side and fore side hydraulic cylinder by roll gap difference
Revise to Q 'n+1。
The band afterbody method for correcting error of Continuous mill train the most according to claim 4, it is characterised in that: step D is to frame bilateral
The method that the correction factor of roll gap difference correction carries out self study is as follows:
After the afterbody completing one piece of intermediate blank is rectified a deviation, available R1, R2, R3…RN-1Ordered series of numbers, this ordered series of numbers is carried out
Search, when finding following two situation, need to learn by oneself the correction factor of the bilateral roll gap difference correction of the (n+1)th frame
Practise:
(1) R is worked asn<-1 and Rn+1During > 1;
The explanation of this kind of situation, transmission side warp tension ratio fore side measured by the n-th tonometry roller between the n-th frame and the (n+1)th frame
Tension force is little, and difference is more than 1 ton, and the band between the i.e. n-th frame and the (n+1)th frame exists lateral bending, and lateral bending direction is operation
Side, after the bilateral roll gap difference revising the (n+1)th frame, the (n+1)th tonometry roller between the (n+1)th frame and the n-th+2 frame
Measured transmission side warp tension ratio fore side tension force is more than more than 1 ton, and the band between the i.e. (n+1)th frame and the n-th+2 frame is deposited
At lateral bending, and lateral bending direction is transmission side, and this shows, when revising the bilateral roll gap difference of the (n+1)th frame, to there is accommodative excess
Phenomenon, make the lateral bending direction of band be changed into transmission side from fore side, i.e. qn+1Absolute value excessive, can by revise system
Number kn+1Carry out self study to reduce qn+1Value, and by the correction factor k ' after self studyn+1For the calculating of next block intermediate blank,
k′n+1Calculating formula be:
(2) R is worked asn> 1 and Rn+1During <-1;
The explanation of this kind of situation, transmission side warp tension ratio fore side measured by the n-th tonometry roller between the n-th frame and the (n+1)th frame
Tension force is more than more than 1 ton, and the band between the i.e. n-th frame and the (n+1)th frame exists lateral bending, and lateral bending direction is transmission side;Warp
After crossing the bilateral roll gap difference of correction the (n+1)th frame, between the (n+1)th frame and the n-th+2 frame measured by the (n+1)th tonometry roller
Transmission side warp tension ratio fore side tension force little, and difference is more than 1 ton, and the band between the i.e. (n+1)th frame and the n-th+2 frame is deposited
At lateral bending, and lateral bending direction is fore side, and this shows, when revising the bilateral roll gap difference of the (n+1)th frame, to there is accommodative excess
Phenomenon, make the lateral bending direction of band be changed into fore side from transmission side, i.e. qn+1Absolute value excessive, can by revise system
Number kn+1Carry out self study to reduce qn+1Value, and by the correction factor k ' after self studyn+1For the calculating of next block intermediate blank,
k′n+1Calculating formula identical with formula (1).
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CN110711771A (en) * | 2019-11-22 | 2020-01-21 | 马鞍山钢铁股份有限公司 | Control method for correcting strip steel deviation based on finish rolling vertical roll |
CN111468541A (en) * | 2020-04-30 | 2020-07-31 | 河南中孚高精铝材有限公司 | Novel belt threading deviation mathematical model control method for 1+4 aluminothermic continuous rolling edge trimmer |
CN114309087A (en) * | 2021-12-28 | 2022-04-12 | 北京科技大学 | Feed-forward continuous control method for tail deviation of strip steel of finishing mill group |
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CN114309087A (en) * | 2021-12-28 | 2022-04-12 | 北京科技大学 | Feed-forward continuous control method for tail deviation of strip steel of finishing mill group |
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